Diagonal Alphabet

Question

Given no input, your task is to generate the following:

a
 b
  c
   d
    e
     f
      g
       h
        i
         j
          k
           l
            m
             n
              o
               p
                q
                 r
                  s
                   t
                    u
                     v
                      w
                       x
                        y
                         z

Nonvisually, your task is to generate each letter in the alphabet, with spaces before it equal to its position in the alphabet minus one.

If you print this, it must appear like the above. Extraneous whitespace that does not affect appearance, as well as a trailing newline, is allowed. You can use all lowercase, or all uppercase.

You may also return this from a function as per usual rules, either as a string with newlines, or a list of strings.

This is code-golf, so shortest answer in bytes wins!

Answer 1

Charcoal, 2 bytes

↘β

Try it online!

How?

 β - the lowercase alphabet
↘  - direction

Exactly the kind of challenge for which Charcoal was originally designed.

Answer 2

C, 45 bytes

f(i){for(i=0;++i<27;)printf("%*c\n",i,i+96);}

Thanks to @Dennis for saving 5 bytes!

Answer 3

05AB1E, 14 8 6 bytes

-2 bytes thanks to @Emigna

AvyNú»

How it works

A      # lowercase alphabet
 v     # for letter in alphabet
  y    # push letter
   N   # push index of letter
    ú  # Pad letter with index of letter spaces
     » # Join with stack on newline.

Try it online!

Original version, 14 bytes

26FNð×N65+ç«}»

Answer 4

JavaScript (ES6), 60 59 bytes

f=(n=10)=>n-36?" ".repeat(n-10)+n.toString(++n)+`
`+f(n):""

A recursive function which returns a string with a trailing newline.

Answer 5

Ruby, 28 bytes

26.times{|a|puts" "*a<<97+a}

Try it online!

Explanation:

The << operator on a string in Ruby does the trick, as explained in the Documentation

• str << integer → str

• str << obj → str

Append—Concatenates the given object to str. If the object is a Integer, it is considered as a codepoint, and is converted to a character before concatenation.

Answer 6

R, 38 37 36 bytes

write(intToUtf8(diag(65:90),T),1,26)

(The use of write is inspired by @Giuseppe's answer.)

Answer 7

Python 2, 36 bytes

n=65;exec"print'%*c'%(n,n);n+=1;"*26

This takes advantage of the extraneous whitespace that does not affect appearance rule.

Try it online!

Alternate version, 38 bytes

n=1;exec"print'%*c'%(n,n+96);n+=1;"*26

This produces the exact output from the challenge spec.

Try it online!

Answer 8

Vim, 29 bytes

:h<_↵↵↵y$ZZ25o <Esc>{qqpblD+q25@q

Try it online!

↵ means press the return key

< Esc> means press the escape key

How does this work?

:h<_↵↵↵                             Open the help and navigate to the alphabet
       y$ZZ                         Copy the alphabet and close the help
           25o <Esc>                Abuse auto-indent and create a whitespace diagonal
                    gg              Go to the beginning of the file
                      qq            Record a macro
                        pb          Paste the alphabet and go to the first letter
                          lD        Go to the second letter and cut the rest of the alphabet
                            +       Go to the first non-blank character in the next line
                             q      Stop recording the macro
                              25@q  Run the macro for the remaining letters

Answer 9

PHP, 39 bytes

for($s=a;!$s[26];$s=" ".++$s)echo"$s
";

Answer 10

Pure Bash, 13

echo {a..z}^K^H

Here ^K and ^H are literal vertical tab and backspace ASCII control characters. The xxd dump of this script is as follows - use xxd -r to regenerate the actual script:

00000000: 6563 686f 207b 612e 2e7a 7d0b 08         echo {a..z}..

• {a..z} is a standard bash brace expansion to produce a b c ... z (space separated)
• the ^K vertical tab drops the cursor down one line to the same position
• the ^H backspace moves the cursor back one to erase the separator space

Try it online. col and tac are used in the footer to get this to render correctly in a browser window, but this is unnecessary in a regular terminal.

---

If the above unorthodox control characters in the output are too much of a stretch for you, then you can do this:

Bash + common utilities, 24

echo {a..z}^K^H|col -x|tac

Here ^K and ^H are literal vertical tab and backspace ASCII control characters. The xxd dump of this script is as follows - use xxd -r to regenerate the actual script:

00000000: 6563 686f 207b 612e 2e7a 7d0b 087c 636f  echo {a..z}..|co
00000010: 6c20 2d78 7c74 6163                      l -x|tac

Try it online. The vertical tab and backspace may be rendered invisible by your browser, but they are there (invisible on chrome, visible on firefox).

• col -x re-renders the input such that funny control characters are replaced with spaces and newlines to give the same visual result
• for some reason col outputs lines in reverse order. tac corrects that.

Answer 11

Brain-Flak, 124, 116, 106 bytes

((((()))))(((([][]){}){})[[]()]<>){(({})<(({})<({}<>({})({})<>)>)
{({}<(<>({})<>)>[()])}{}(<>[][]<>)>[()])}

Try it online!

Explanation:

This answer abuses the Stack Height Nilad, but in a new way that I've never used before, which I'm pretty proud of. Other than that, the answer's not too clever.

So analyzing the characters used in this ASCII art, there are really three values that are frequently used:

• 32 (space),

• 64 (add 64 to N to get the N'th letter of the alphabet), and

• 10 (newline)

As well as 26. (number of loops) And these numbers are pushed in different locations, so we can't really reuses intermediate values to make the large numbers smaller. And pushing all for of these numbers is a whopping 86 bytes alone:

10:
((()()()()()){})

26:
((((()()()){}){}()){})

32:
((((()()()()){}){}){})

64:
(((((()()()()){}){}){}){})

This is horrible. So here's how we make it more convenient. The obvious approach is to push a 32 onto the alternate stack, which makes our 32 snippet become: (<>({})<>) and our 64 snippet become (<>({})({})<>). If we combine our initial push 32 with our initial push 26, we can save 8 bytes roughly. (my first golf).

But here is where the trick I'm really proud of comes in. Since we're not using the alternate stack for anything else, we might as well golf down the 10 also. To do this, we'll push 4 arbitrary numbers onto the stack right at the start of the program. Since we also push 32, this increases the value of the [] nilad, to 5, which makes our 10 snippet much more convenient. And lucky for us, it actually lets us golf the push 32 and 26 snippet down too!

#Push 32, 26
(((((()()()()){}){}){})<>[(()()()){}])

#Push 10
((()()()()()){})

Becomes

#Push 32, 26 (-2 bytes)
(((((())))))((([][][]){}()())[[]]<>)

#Push 10 (-6 bytes)
(<>[][]<>)

So here is a detailed explanation:

# Push 1 four times
((((()))))

# Push 32 to main stack (to reuse later)...
((([][][]){}()())

# And then 26 to the alternate stack
[[]()]<>)

#While true
{

    # Keep track of the current TOS
    (({})<

        # Push [TOS, TOS + 64] (To get uppercase characters)
        (({})<({}<>({})({})<>)>)

        # TOS times...
        {
            # Decrement the loop counter, while pushing a space underneath it
            ({}<(<>({})<>)>[()])

        # Endwhile, pop zeroed counter
        }{}

        # Push 10 (newline)
        (<>[][]<>)

    # Push TOS - 1 back one
    >[()])

# Endwhile
}

Answer 12

V, 15 13 11 bytes

¬azòÙr klDj

Try it online!

Explanation

¬az         ' Insert a-z
   ò        ' Recursively
    Ù       ' Duplicate current line down
     r      ' Replace the first character with a ' '
       kl   ' Move up a line and right
         D  ' Delete from here to the end
          j ' Move back down

Answer 13

APL (Dyalog), 9 7 bytes^SBCS

-2 bytes thanks to ngn's hint.

↑⍨∘-⌸⎕A

[Try it online!][TIO-j3o0ipjy]

⎕A the uppercase Alphabet

⌸ between each (element,list of indices) pair, insert the following tacit function:

 ↑⍨ from the element (the letter) take…

 ∘ the…

 - negated-index number of characters, i.e. that many characters from the back, padding on the front with spaces.

Try it online!

Answer 14

Google Sheets, 67 65 bytes

=ArrayFormula(IF(ROW(A1:Z)=COLUMN(A1:Z26),CHAR(96+ROW(A1:Z26)),))

=ArrayFormula(IF(ROW(A1:Z)=COLUMN(A1:Z26),CHAR(96+ROW(A1:Z26)),""))

Going off the clarification that any whitespace will do, I've used visibly empty cells

Let me know if this doesn't count, if I've misunderstood the byte count or if I've screwed up some etiquette as this is my first post here.

Edit: It turns out I can save 2 bytes by leaving out the "" as Google sheets will accept an empty if value.

Answer 15

Octave, 25 19 or 12? bytes

[diag(65:90)+32 '']

Try it online!

Other solution proposed by @LuisMendo (12 bytes) that I tested it in windows version of Octave:

diag('a':'z')

Explanation:

Generates diagonal matrix of a:z.

Answer 16

Java 8, 72 71 70 61 bytes

o->{for(int a=0;a++<26;)System.out.printf("%"+a+"c%n",a+96);}

-1 byte by outputting the uppercase alphabet instead of lowercase.
-1 byte by printing directly, instead of returning a multiline String.
-8 bytes thanks to @OliverGrégoire by using printf directly to get rid of String s="";. And also -1 byte by changing ()-> to o->.

Try it here.

Answer 17

Jelly,  10  9 bytes

-1 byte thanks to Dennis (avoid decrementing J by using a lowered range, 26Ḷ, directly)

26Ḷ⁶ẋżØaY

A full program that prints the result.

Try it online!

(ØaJ’⁶ẋż for 7 is a monadic link that returns a list of lists of lists of characters, but that is like [["a"],[" ","b"],[" ","c"],...] which is probably unacceptable.)

I would, however, not be surprised if there was a shorter way I have not thought about!

How?

26Ḷ⁶ẋżØaY - Main link: no arguments
26        - literal 26
  Ḷ       - lowered range = [0,1,2,...,26]
   ⁶      - literal space character
    ẋ     - repeat          [ [],      [' '],      [' ',' '],    ...,  [' ',' ',...,' ']]
      Øa  - yield lowercase alphabet
     ż    - zip             [[[],'a'],[[' '],'b'],[[' ',' '],'c'],...,[[' ',' ',...,' '],'z']]
        Y - join with newlines  [[],'a','\n',[' '],'b',\n',[' ',' '],'c','\n',...,'\n',[' ',' ',...,' '],'z']
          - implicit print (smashes the above together, printing the desired output)

Answer 18

PowerShell, 29 bytes

0..25|%{' '*$_+[char]($_+97)}

Answer 19

Alice, 22 20 bytes

52E&waq'a+q&' d&o]k@

Try it online!

Even though the output is a string, it turns out ordinal mode is not the way to go for this challenge.

Explanation

52E&w             k@     do 26 times
     a                   push 10 (LF)
      q                  push current tape position (initially zero)
       'a+               add the ASCII code for "a"
          q&'            push 32 (space) a number of times equal to tape position
              d&o        output entire stack
                 ]       move tape position one space to the right

Previous solution

["za/?rO&
' !]\"ohkw@/

Try it online!

I went through about ten 23-byte solutions before I was able to find this one.

Explanation

This program uses the tape to track the number of spaces to output. Cardinal and ordinal modes use the same tape, but they have separate tape heads. The two modes have different interpretations of what they see on the tape, and the program fully exploits that difference.

The commands are executed in the following order:

[                   move cardinal tape position left
 "za"               push this string (as a string, since the final " is in ordinal mode)
     r              interpolate to entire range (i.e., the lowercase alphabet backward)
      h             split first character from string
       &            for each character in string: push that character and...
        w                                         push current address onto return address stack
         ' !        (cardinal mode) place 32 (space) at current cardinal tape position
            ]       (cardinal mode) move cardinal tape position right
             ?      (back to ordinal mode) read string from tape starting at ordinal tape position
                    this string will consist of n-1 spaces.
              o     output string of spaces
               O    output top of stack (current letter) followed by newline
                k   return to pushed return address. 
                    after 26 times through this loop, the return address stack will be empty and this is a no-op.
                 @  terminate

Answer 20

Brainfuck, 103 bytes

>-<-----[[<+>->>+++>-<<<]>++]<<<<<<<<<[-]>>>-[<[-]<[-]<[>+>+<<-]>>[<<+>>-]<[>>>>.<<<<-]<+>>>>.+>>.<<<-]

Try it online!

The location of the variables is somehow improvable.

Explanation

>-<-----[[<+>->>+++>-<<<]>++]   Initializes the tape.
<<<<<<<<<[-]>[-]>>-             Resets variables that
                                need to be at 0.
[                               For loop (25 to 0).
 <[-]<<[>+>+<<-]>>[<<+>>-]      Copy the spaces count in
                                order to use it in a loop.
 <[>>>>.<<<<-]                  Prints the spaces.
                                Prints the character followed
 <+>>>>.+>>.<<<-                by a new line. Also decrements
                                the main loop counter.
]

Answer 21

Google Sheets, 69 bytes

=ArrayFormula(JOIN("
",REPT(" ",ROW(A1:A26)-1)&CHAR(96+ROW(A1:A26))))

Nothing complicated here. The only trick is using ArrayFormula and ROW(A1:A26) to return 26 different values for the JOIN function. Output looks like this:

---

I think Excel 2016 can do the same thing with TEXTJOIN but I can't enter array formulas in the online version and only have 2013 myself. The formula should be this:

=TEXTJOIN("
",FALSE,REPT(" ",ROW(A1:A26)-1)&CHAR(96+ROW(A1:A26)))

Entering it as an array formula (Ctrl+Shift+Enter) adds curly brackets { } on both sides, bringing it to 67 bytes. Anyone who can verify it works is welcome to use it as their own answer.

Answer 22

Seed, 6014 bytes

I don't think this will win any awards, but just for fun, here's a solution in Seed.

86 11103250503694729158762257823050815521568836599011209889044745493166180250197633623839266491438081837290079379263402288506775397211362446108152606095635373134468715450376738199004596861532212810083090232034321755895588102701453625219810339758989366211308223221344886043229936009486687653111291562495367476364760255760906228050130847228170228716790260998430434027546345063918859356161024202180254514539438087787769611000320430464740566450402368450792375043801526494811596087812709169139468697779440918934518195843690439213251884693846598754642076364755341359062651237754916053099089619667382845958005035392458577634784453744876558142057256976895330859887974064083588368087014591508237946214519271550243549214199679364098489146944338807874570414584343165070707969101892779772740177526390597395955859236589308394889243501541206981604661264930842784772121710695027991351718061777696274815931123342985242351444203296855501870888626347939456384376808446806093364176576945969539054970975848477876079897476093353730443488664472826635815956526890935049081522728044807877072639829234224838977148057506785320443165975265560224605597481381188291535996775480326796788286452216432605854564432262547835415260058472165825285438444435690700488258778785613363062417500848996527077259315494936037544655054620369560227407957368700650031346856230643646273909094915618471799926504192999361174763592054723307855670381682927214117502862645460031555724588536036895597768493827964819026940533784490457441244859937078155137620826821294513857153097135094397278852300032685608169642137925241118197368192392427097109982751185030229544527638686131131545529690698706313745703838144933923021851042677941879847025167921010148923860660695145106913052517930707522151230705792709484338746351589089180137363986003757314611932324492978098101655359729841878862276799317010824753645947659706175083519817734448003718088115457982394423932136760435046136644679525408371158980833993157988971884061469882136904103033944270884697456159261033500286722891139158500027351042265757431184139617566089023339480051231776345929815102059539844917563709940188668873305602146506284075271989710388430531233185164106985265575418252638186398535149202928422854319253947591044830747981534342833040219194969504971457701296402664807369043224201667623773161453335066484102800249947322601702575025462427139266561015140950621152993027466758026351218924607290766894274223554418125824416921899080393405328694235821466034161071834073874727856768719898425047229002772806527172294625623026601313091815217479540688812203850300478145319935479599086534606210099372526810614742385909275512758349679098012967475393301857434507012875239092688018536028125644341148882858752275129016876257290205949225918496182271679312996010157634568807332616541938310641844258434083838017690572891417189135014450484203635258935943095637185443145042430274553211816422809756194554145177421779800554334935224073734034988935790096239926730047370699006392111034056662661567902477446646680125183082979598538506383502737734442490068661537425714549752783861222862366340979663873475326752237893690641570287341027097775099918958849864419430754493042534812120486345363285167685811903366691676146427476942948696624274431993989133835880516551024369474029197791751838810883302415448112237526350703063618171739262753474029252659418383385834751808940073804107171146665382663467460066719556797639176747423279761528061219482681051780434845070421974558638870988408449698678976622755518024906714421419806347234183574860655249471877105716127767795785164699804819127058322715857697491583787449703283625085118896433923054087238479453964363805045497229148813441732912067120594705269402106426011497763749556561398150139686331615167139081591537739333533146667211063179804707883556569241294269430626179579760506971066676011512530066694518309930078451295032445835025178124213221937594928472509588116557231122849491576207720183829735710200290762251904109318007206980645946249679357907549498615310165588678201768095297568708803842208357473777731751349499510116345704811971207818719582793964185192140178454948686109674659005978400204479072321714207828018696339659886683414074211823497880135255138161141724546221354224299071581607979907417508104234534779573666933024250229754952685174194168516481670999039048675109878524061868078078216337487277443941946961426121900907734301692962783139932352047932263834773963592317279425421954035566305805348109175553209815893678595198155962166838761859540063188209014774346841267440789072833797121217961797443744676162541668802226500817146368372390178287945076657776275930590173768326046610094573983886099504933977126798348879838826160714899283593774855907724617352862079916515034033299006419237012240730789008999523238851913897908225482003661109026061857228300111070725651744312468140016983078297938157227595743419983763920290850801438187869169473456288283458163865462359588316419331445070232596307970490434468929587726795603069137946085898481642595124580643542063564880389350236902538522311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It translates to the following Befunge program:

vaa{       @>
v#      g02<v
>30g20g`   |
10g-:!v!: < >#<
v,:g02_40g,1- ^
>1+20p$91+, v

Answer 23

shortC, 33 bytes

AOI_=0;++_<27;R"%*c\n",_,_+96));}

Try it online!

Answer 24

R, 59 49 47 bytes

-10 bytes thanks to djhurio

-2 bytes thanks to Sven Hohenstein

write("diag<-"(matrix("",26,26),letters),"",26)

Prints to stdout. Outgolfed by user2390246

Try it online!

Answer 25

><>, 46 44 42 bytes

"A"0::?!v" "o1-40.
*(?!;30.>~$:oao1+$1+:d2

Try it online!

Explanation

Line 1:
"a"0::?!v" "o1-40.
"a"0                       :Initialize the stack items (print char and space count)
    ::?!v                  :Duplicate the space count, check if 0, go down if 0
         " "o1-            :Print a space then take 1 from the space count
               40.         :Jump to codepoint row 0 col 4 (this restarts the loop)
Line 2:
*(?!;30.>~$:oao1+$1+:d2
        >~                 :Remove the zeroed space counter off the stack
          $:oao1+          :Place our print char on the top of the stack, duplicate and print it, print a new line, increase it by 1; a->b->c etc
                 $1+       :Place our space count on the top of the stack and increase it by 1
*                   :d2    :Duplicate the space counter, add 26 to the stack
 (?!;                      :Add 0 to the stack, less than compare 0, if the counter is above 0 it terminates
     30.                   :Jump to the first line, (back to printing spaces)

This is a completely different take from my previous 46 bytes so I've included the TIO to the only one as well. 46 bytes Try it online!

Below is a link to Emigna's submissions, it was the first ><> answer but I believe mine is different enough (and saves a few bytes) to warrant a second one.

Emigna's answer

Answer 26

Add++, 1069 bytes

+97
&
-87
&
+22
&
+66
&
-88
&
+22
&
&
+67
&
-89
&
+22
&
&
&
+68
&
-90
&
+22
&
&
&
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+69
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-91
&
+22
&
&
&
&
&
+70
&
-92
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+22
&
&
&
&
&
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+71
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-93
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+22
&
&
&
&
&
&
&
+72
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-94
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+22
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&
&
&
&
&
&
&
+73
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-95
&
+22
&
&
&
&
&
&
&
&
&
+74
&
-96
&
+22
&
&
&
&
&
&
&
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&
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+75
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-97
&
+22
&
&
&
&
&
&
&
&
&
&
&
+76
&
-98
&
+22
&
&
&
&
&
&
&
&
&
&
&
&
+77
&
-99
&
+22
&
&
&
&
&
&
&
&
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&
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&
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+78
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-100
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+22
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+79
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-101
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+22
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+80
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-102
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+22
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+81
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-103
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+22
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+90
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P

Try it online!

Yep. That is hardcoded. I'm sure there is a better way, and if you want to find it, go ahead, but this way seems to work the best as Add++ is difficult to work with memory.

Answer 27

Haskell, 66 65 58 57 45 43 bytes

Thanks to @nimi and @maple_shaft for saving 12 14 bytes.

unlines[(' '<$['b'..n])++[n]|n<-['a'..'z']]

Try it online!

Answer 28

PHP, 23 bytes

Note: uses IBM-850 encoding.

<?=join(~¶,range(a,z));

Run like this:

echo '<?=join(~¶,range(a,z));' | php -n;echo
# With default (utf8) terminal:
echo '<?=join("\v",range(a,z));' | php -n;echo

Explanation

Create an array of all characters of the alphabet, join it with a vertical tab as glue.

Answer 29

VBA, 35 Bytes

Anonymous VBE immediate window function that takes no input and outputs the alphabet, diagonally, to the VBE immediate window

For i=0To 25:?Spc(i)Chr(97+i):Next

-2 Bytes thanks to @Chronocidal

---

Alternatively, _{76 50} 46 Bytes

Anonymous VBE immediate window function that takes no input and outputs the alphabet, diagonally, to the range [A1:Z26] on the VBE immediate window function

[A:Z]="=If(Row()=Column(),Char(64+ROW()),"""")

Answer 30

brainfuck, 80 bytes

++++++++[>+>++++>++++++++>+++<<<<-]>++>>+>++[->[<<<.>>>->+<]>+[-<+>]<<<.+<<.>>>]

Try it online!

Formatted:

++++++++[>+>++++
>++++++++>+++<<<
<-]>++>>+>++[->[
<<<.>>>->+<]>+[-
<+>]<<<.+<<.>>>]

Uses a simple multiplicative generation function to put some constants in memory, then repeats the process of printing N spaces then 'A' + N for N = 0..25.

Annotated:

INITIALIZE TAPE: 10 32 65 >26< 0 0
C_NEWLINE: 10
C_SPACE: 32
V_ALPHA: 65
V_COUNTER: 26
V_PREFIX: 0
V_PREFIX_TEMP: 0
++++++++[>+>++++>++++++++>+++<<<<-]>++>>+>++

WHILE V_COUNTER != 0  [-
   "PRINT C_SPACE REPEATED V_PREFIX TIMES"
   "V_PREFIX_TEMP = V_PREFIX"
     V_PREFIX TIMES  >[-
       PRINT C_SPACE <<<.>>>
       INCREMENT V_PREFIX_TEMP >+<
     ]
   "V_PREFIX = V_PREFIX_TEMP PLUS 1"
     V_PREFIX_TEMP PLUS 1 TIMES  >+[-
       INCREMENT V_PREFIX <+>
     ]
   PRINT C_ALPHA <<<.
   INCREMENT C_ALPHA +
   PRINT C_NEWLINE <<.
>>>]

Answer 31

RProgN 2, 5 bytes

aS`\x0B.

\x0B is a Vertical Tab Literal

This just takes the lowercase alphabet, splits it, and joins it with vertical tabs. This produces the intended effect on certain Bash Terminals.

Answer 32

Gforth, 45 Bytes

: X CR 26 0 DO i SPACES i 97 + EMIT CR LOOP ;

Explanation

Gforth doesn't allow interpretation of loops, so I had to define a new word X.

: X                 \ Define new word X
   CR               \ Go to a new line
   26 0 DO          \ Loop from 0 to 25
   i SPACES         \ Print i spaces
   i 97 + EMIT      \ Calculate ASCII-code and print it
   CR               \ Next line
;                   \ End of word definition

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Answer 33

Kotlin, 36 35 bytes

Saved a byte by removing comma (lambda outside of call.)

{List(26){" ".repeat(it)+('a'+it)}}

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Answer 34

Python 2, 42 bytes

Out-golfed... by Dennis, no less... ><

lambda:[' '*n+chr(n+65)for n in range(26)]

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Answer 35

Brachylog, 17 bytes

25⟦{;Ṣj₍}ᵐ;Ạzcᵐẉᵐ

Try it online!

Answer 36

Brachylog, 16 bytes

Ạ;I∋₎C∧Ṣ;Ij₎wCẉ⊥

Try it online!

Explanation

Ạ;I∋₎C             C is the Ith character of "abcdefghijklmnopqrstuvwxyz"
      ∧Ṣ;Ij₎       Juxtapose " " I times
            w      Write to STDOUT
             Cẉ    Writeln C to STDOUT
               ⊥   False: try another C

Answer 37

J, 28 bytes

([,{&a.@+&97@#)@#&' '"0 i.26

pretty:

([ , {&a. @ +&97 @ #) @ #&' ' "0 i.26

Answer 38

C#, 82 bytes

using System.Linq;()=>Enumerable.Range(0,26).Select(i=>"".PadLeft(i)+(char)(i+65))

Works by creating an array of ints from 0 - 25, creates a string of i length of only spaces. Then adds a char onto the end corresponding to an upper case letter. It lastly implicitly returns an array, in this case an IEnumerable<string>, of each line.

Answer 39

><>, 50 49 46 45 38 bytes

0>:5d*+oao:64*)?;1+:191.
?v84*o:{1+:}(

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Explanation

0>          # initialize outer counter and start outer loop
:5d*+oao    # add outer counter to 65 and print as ascii followed by a newline
64*)?;      # if outer counter is greater than 24, end program
1+:1        # increment outer counter and initialize inner counter
91.         # jump to inner loop
:}(?v       # if inner counter is greater than outer counter go back to outer loop
84*o        # else print a space character
:{1+        # and increment inner counter

Answer 40

Perl 5 + -l, 21 bytes

$\.=$",print for a..z

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Answer 41

MATL, 5 bytes

2Y2Xd

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Explanation

2Y2    % Predefined literal: 'a':'z'
Xd     % Diagonal matrix. Implicit display

Answer 42

R, 40 bytes

write(c("",LETTERS)[diag(1:26)+1],"",26)

Try it online

                    diag(1:26)+1           # Create a matrix of ones with 2:27 on the diagonal
      c("",LETTERS)                        # Create a vector containing an empty string followed by the alphabet
      c("",LETTERS)[diag(1:26)+1]          # Use that vector as a lookup table for the matrix
write(                           ,"",26)   # Print over 26 columns

Use of write() copied from @Giuseppe's answer, but uses a different approach to creating the matrix.

Outgolfed by Sven Hohenstein

Answer 43

q/kdb+, 26 22 bytes

Solution:

-1(!:[26]#'" "),'.Q.a;

Example:

q)-1(!:[26]#'" "),'.Q.a;
a
 b
  c
   d
    e
     f
      g
       h
        i
         j
          k
           l
            m
             n
              o
               p
                q
                 r
                  s
                   t
                    u
                     v
                      w
                       x
                        y
                         z

Explanation:

Joins each letter of the alphabet with an increasing number of spaces. Brackets are used due to right-to-left evaluation.

-1(til[26]#'" "),'.Q.a; / ungolfed solution
-1                    ; / print to stdout and swallow return value
                  .Q.a  / shorthand for abc..xyz
                ,'      / concatenate (,) each-left/each-right (')
  (            )        / do all this together
          #'" "         / take each-left/each-right (space)
   til[26]              / range of 0..25

Answer 44

Go, 97 bytes

package main;import."strings";func main(){for i:=0;i<26;i++{println(Repeat(" ",i)+string(i+97))}}

Definitely not the best language to golf with but wanted to get my first solution up, also should note this prints to stderr but I assume that's okay if it's not specificed

Go (as far as I know) lacks the ability to specify a dynamic width for padding formatted strings which is why I had to bring in and use strings.Repeat()

Readable version:

package main

import . "strings"

func main() {
    for i := 0; i < 26; i++ {
        println(Repeat(" ", i) + string(i+97))
    }
}

Answer 45

Ohm, 10 bytes

αß:^MüL;_,

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Explanation

αß:^MüL;_,  
αß          # Pushes [a-z]
  :         # For each...
   ^MüL;    # Print index amout of spaces
        _,  # Prints the char

Answer 46

Python 3, 41 bytes

for n in range(26):print(" "*n+chr(n+97))

Answer 47

Perl: 23 bytes

22 + 1 for -E flag.

say$"x$i++,$_ for a..z

Usage:

perl -E 'say$"x$i++,$_ for a..z'

Answer 48

k, 21 bytes

`0:`c$32+(65+!26)*=26

Try it online.

Explanation:

                  =26 /identity matrix of length 26
         (65+!26)*    /for i in {0..25}:
                      /    matrix[i] *= 65 + i
      32+             /add 32 to everything
                      /    turns 0's into spaces
                      /    brings us to a lowercase alphabet for the rest
   `c$                /turn to characters
`0:                   /write to stdout/stderr

Answer 49

Common Lisp, 58 bytes

(dotimes(i 26)(format t"~v@a~%"(1+ i)(code-char(+ i 97))))

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Answer 50

Yabasic, 49 bytes

Another basic answer which takes no input and outputs to the console.

For i=0To 25
For j=1To i?" ";Next
?Chr$(65+i)Next

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Answer 51

SmileBASIC 3, 33 bytes

FOR I=0TO 25?" "*I+CHR$(97+I)NEXT

Looks like 12Me hasn't answered this one yet…

Answer 52

Assembly (nasm, x64, Linux), 62 59 55 45 + 8 bytes

func:
  ; R8 is the buffer the function will write the output to.
  ; most GPRs must be 0'd!
  mov al, 'a'
  inc edx
  or r8, buf ; Suprise! It's more efficient to write it this way, the equivilent mov requires 3 bytes of padding to follow.
.append:
  mov byte [r8+rbx], al
  mov byte [r8+rbx+1], 0Ah
  add ebx, 2
  cmp al, 'z'
  je .exit
  inc eax
  mov ecx, edx
  inc edx
.dospaces:
  mov byte [r8+rbx], ' '
  inc ebx
  ; cx is used here. Be aware!
  loop .dospaces
  jmp .append
.exit:
  ret

Try it online!

I spent a fair while doing this one. Seriously, some things will slowly drive you insane. This function outputs a buffer containing the requested data. Said buffer is in the .bss section.

NOTE: It doesn't seem to work on TIO for some reason. Works perfectly fine on my laptop. I built it using the following commands:

nasm -felf64 diagonal-alphabet_125117.s
gcc diagonal-alphabet_125117.o -no-pie 

For your viewing pleasure, the TIO version is modified to use the data section instead, so it actually runs.

The bytecount is currently based on the bytecount of the function and the 8 bytes needed to represent the length of .bss

Note to future readers: A CC where most GPRs must be 0'd can be useful, because or is shorter than mov, at least in the case demonstrated above.

Answer 53

Underload, 104 bytes

(z)(y)(x)(w)(v)(u)(t)(s)(r)(q)(p)(o)(n)(m)(l)(k)(j)(i)(h)(g)(f)(e)(d)(c)(b)(a)(
)(:S( )*~S):*::*:*::***^

Try it online!

The snippet :S( )*~S has the meaning:

• Duplicate and print the TOS
• Add a space to the TOS
• Print the string under the TOS

If the TOS starts as a newline and the strings on the stack form the alphabet (with a highest), then executing this snippet 26 times generates the correct output.

Answer 54

Kotlin, 39 bytes

{('a'..'z').map{" ".repeat(it-'a')+it}}

Lambda returning a list of lines.

Try it online!

{                                  // lambda; implicitly return
    ('a'..'z').map {               // map over the lowercase alphabet
        " ".repeat(it - 'a')       // repeat space by letter position
                             + it  // append letter
    }
}

Answer 55

MathGolf, 10 7 bytes

▄{ï *▌p

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I'm happy to announce that MathGolf now has a 1-byte literal for the lowercase alphabet! That should make any challenge related to the alphabet a lot easier!

Explanation

▄         Push alphabet as string
 {        For-each
  ï *     Push " "*(loop counter)
     ▌    Prepend to the character
      p   Print

Answer 56

PowerShell, 29 26 bytes

'a'..'z'|%{' '*($_-97)+$_}

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Output:

a
 b
  c
   d
    e
     f
      g
       h
        i
         j
          k
           l
            m
             n
              o
               p
                q
                 r
                  s
                   t
                    u
                     v
                      w
                       x
                        y
                         z

Answer 57

Pyth, 9 8 bytes

.e+*dkbG

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Explanation

.e     G  For each element of 'abc...z'...
   *dk    Take a string of spaces with length equal to the index...
  +   b   Add the letter.

Answer 58

Japt, 10 9 bytes

Saved 1 byte thanks to @Shaggy

;C£RiXiYî

Run it online!

Explanation:

;C£RiXiYî
;C          // Lowercase alphabet
  £         // Map; At each char:
   R        //   Newline
    iX      //   Insert: X (Iterative char)
      iYî   //   Insert: " " repeated Y (index) times

By default, i inserts the target char at index 0. So, RiXiYî becomes Yî +X+R.

Answer 59

QBIC, 27 bytes

[26|?space$(a-1)+chr$(a+96)

Explanation

[26|          FOR a = 1 to 26
?space$(a-1)  PRINT a-1 spaces (SPACES$ is a QBasic function that prints x spaces)
+chr$(a+96)      and a char representation of a+96

Answer 60

Tcl, 52 bytes

set i 96;time {puts [format %[incr j]c [incr i]]} 26

time is really a tool for measuring time spent, but it's also handy for repetition of code. Indentation and letter are advanced in each iteration. Ascii code i needs preset to one-before-first-letter, j will be auto-set to 1 on first incr.

If run in an interactive tclsh, the time would also output timings, but if the line is in a script, then it's silent, except for the diagonal.

Answer 61

ZX Spectrum BASIC, 29 bytes

FOR i=NOT PI TO VAL "25": LPRINT TAB i;CHR$ (i+VAL "97"): NEXT i

Numeric literals carry a 6-byte penalty, so using VAL saves me 3 bytes (VAL is a 1-byte token). Note: The ZX Spectrum's output area is only 22 lines high, so I'm sending the output to the printer instead.

Answer 62

Scala, 41 bytes

('a'to'z').map(a=>println(" "*(a-'a')+a))

Previous answer: 45 bytes

(0 to 25).map(a=>printf("%s%c\n"," "*a,97+a))

It is 1 byte shorter than

(0 to 25).map(a=>println(" "*a+(97+a).toChar))

Try it online!

Answer 63

Bash, 38 36 35 bytes

printf "%*s
" `echo $[++i]\ {a..z}`

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2 bytes less thanks to @DigitalTrauma

1 byte less thanks to @NahuelFouilleul

"%*s\n" takes padding as an argument. $((++i))\ {a..z} for each letter increment and prepend i plus space (arithmetic expansion)

Answer 64

Nano, 186 77 bytes

M- represents the alt key

M-ia
 b
 c
 d
 e
 f 
 g
 h
 i
 j
 k
 l
 m
 n
 o
 p
 q
 r
 s
 t
 u
 v
 w
 x
 y
 z

Explanation

I've seen a few Vim answers on this site so I thought I would do a nano answer. Its not nearly as terse as the Vim answers but its still better than typing out the whole thing.

This is pretty simple (a lot simpler than my original answer). M-i sets the auto-indent on. This means that every line will copy the indentation of the last. So we start with a and every line add a space and a letter all the way through.

Answer 65

T-SQL, 63 bytes

DECLARE @ INT=0a:PRINT SPACE(@)+CHAR(@+65)SET @+=1IF @<26GOTO a

Written more conventionally, that would be:

DECLARE @ INT=0
a:
    PRINT SPACE(@) + CHAR(@+65)
    SET @ += 1
IF @<26 GOTO a

Tested and working on SQL Server 2012.

Answer 66

Mathematica, 39 Bytes

Grid@DiagonalMatrix@Alphabet[]/. 0->" "

This has trailing whitespace.

Explanation:

                    Alphabet[]          - Create a list of the alphabet
     DiagonalMatrix@                    - Use that as the diagonal of a matrix
                              /. 0->" " - Replaces the 0's with whitespace
Grid@                                   - Then turn it into a 2D grid

Answer 67

TI-Basic, 71 69 bytes

"       
For(I,1,26
Disp sub(Ans+Ans+Ans+Ans,1,I)+sub("ABCDEFGHIJKLMNOPQRSTUVWXYZ",I,1
End

Answer 68

braingasm, 20 bytes

26[#[32.]97+#+.10.>]

26 times, print (.) a space (32) # (current position on the tape) times; increase cell (+) by 97, then by #; and print the current cell value, along with a newline (10); then go to next cell (>).

Answer 69

JAVASCRIPT

Option 1: 59 bytes

a='';for(i=0;i<26;)a+=''.padEnd(i++)+(i+9).toString(36)+`
`

Option 2: 60 bytes

a='';for(i=0;i<26;)a+=' '.repeat(i++)+(i+9).toString(36)+`
`

Option 3: 61 bytes

a='',i=0;while(i<26)a+=' '.repeat(i++)+(i+9).toString(36)+`
`

Option 4: 67 bytes

a='';for(i=0;i<26;)a+=' '.repeat(i++)+String.fromCharCode(96+i)+`
`

Option 5: 68 bytes

[...Array(26)].map(_=>' '.repeat(++i-10)+i.toString(36),i=9).join`
`

Answer 70

Perl 6, 25 bytes

{" " «x«^26 Z~'a'..'z'}

This function returns a list of the required strings: "a", " b", " c", ...

^26 is a list of the numbers from 0 to 25. «x« is the string-replication hyperoperator that maps each element n of its right-hand side to the left-hand side replicated n times, producing the list "", " ", " ", .... That list is then zipped with string concatenation (the Z~ operator) with the range of letters from 'a' to 'z'.

Answer 71

R, 56 bytes

for(i in 1:26){cat(rep(" ",i-1),LETTERS[i],'\n',sep='')}

Try it online!

Prints i-1 spaces and the ith letter of the alphabet, plus a newline, 26 times.

Outgolfed by Giuseppe (47 bytes), user2390246 (40 bytes), and Sven Hohenstein (37 bytes), but this is the only answer (so far) that doesn't use diag.

Answer 72

Julia, 42 bytes

for i=0:25 println(" "^i,Char[97+i][1])end

Pretty straight forward, print space and character.

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Answer 73

Ruby, 18 bytes

puts [*?a..?z]*?\v

Does not work on TIO, link for reference:

Try it online!

Answer 74

Pyth, 11 bytes

j.b+*dNY26G

Explanation:

Try it online!

j.b+*dNY26G   expects no input

j             joins on new line
 .b           for...in loop, uses two iterator variables
   +          joins *dN and Y
    *dN       repeats d (space) N times, where N is one of .b's iterating variables
       Y      another one of .b's iterating variables
        26    the array being iterated for N,.b automatically takes the unary range
          G   initialized to the lowercase alphabet, the array being iterated for Y

Answer 75

SOGL V0.12, 2 bytes

z╝

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z   push the alphabet
 ╝  convert to a diagonal array
    implicitly output as a newline joined string

Answer 76

Pyth, 13 bytes

I've noticed that I've been getting better at these, but Dave or Mr. Xcoder will school me any day of the week.

Update: Pyth tester is down, rip back up.

#p*dt=hZhG=tG

Explanation:

#         Loop until error
 p*dt=hZ  Print without newline: " " times ++Z - 1 (Z defaults to 0) (Could have used + instead of p, but it's easier to explain)
 hG       Implicit print with newline: The first character of the alphabet
 =tG      Remove the first letter in the alphabet variable

Try it online!

Answer 77

Befunge-98 (PyFunge), 30 bytes

1+:0\:'`+\' \k:>:#,_$:'␚-!k@a,

Where ␚ is a literal substitute character

Every line has 3 leading spaces

Try it online!

Answer 78

J, 19 16 bytes

u:32+(*=)65+i.26

Try it online!

Answer 79

uBASIC, 36 bytes

Anonymous function that takes no input and outputs to the console.

0ForI=0To25:?Tab(I);Chr$(65+I):NextI

Try it online!

Answer 80

Pepe, 79 76 56 bytes

Way better, faster algorithm which performs like 3 times less operations. And saves 3 bytes. Now even more, because Pepe supports flags - no more unnecessary item movement!

REeEEEEeEErEeEEeeeeEREEreeereeErEEEEERrEeeEeeeeerEEEeRee

Try it online!

Explanation

REeEEEEeEE   # push "{" to R
rEeEEeeeeE   # push "a" to r

REE # label "{"

  reee # print stack contents
  reeE # print newline

  rEEEEE       # increment the letter
  R rEeeEeeeee # prepend a space
  rEEEe        # r pointer to end

Ree # goto "{" if the letter didn't reach "{" yet

Answer 81

PowerShell, 35 bytes

$i=97;0..25|%{" "*$_+[char]$i;$i++}

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Pipes an array of 0 through 25 to ForEach-Object, which cycles through ascii codes and prefixes with a space multiplied by an incrementing variable.

Answer 82

Mouse-2002, 43 bytes

(A.Z1+<^A.B:(B.^" "B.1-B:)A.97+!'"!"A.1+A:)

Needs to be run in the Mouse-2002 Interpreter REPL. Working interpreter can be found here.

Answer 83

brainfuck, 64 bytes

+[[-<+>>++<]>]<<++[>[-<<<.>>>>+<]>+[-<+>]<<<+.<<---.+++>>>-----]

Try it online!

Prints in uppercase with a trailing newline.

Initialises the tape to 2^N, and uses the 16(-3) as the newline, the 32 as the space, the 64 as the start of the uppercase alphabet, the 128(+2) as the counter (-5 each loop), and the cell at the end as the space counter.

Answer 84

Canvas, 2 bytes

ｚ＼

Try it here!

Answer 85

Stax, 6 bytes^CP437

åuvÉ◄┘

Try it online!

Explanation

Uses the unpacked format to explain.

Vam]i^)
Va         "abcdefghijklmnopqrstuvwxyz"
  m        For each letter, execute the rest of the program
               Output the result on individual lines
   ]       Change the letter to a single-letter string
    i^     Current loop index+1
      )    Pad the string to given length

Answer 86

K4, 18 bytes

Solution:

-1(-1-!26)$'$.Q.a;

Example:

q)k)-1(-1-!26)$'$.Q.a;
a
 b
  c
   d
    e
     f
      g
       h
        i
         j
          k
           l
            m
             n
              o
               p
                q
                 r
                  s
                   t
                    u
                     v
                      w
                       x
                        y
                         z

Explanation:

Left-pad the alphabet:

-1(-1-!26)$'$.Q.a; / the solution
-1               ; / print to STDOUT, swallow return
             .Q.a  / "abcdefghijklmnopqrstuvwxyz"
            $      / string, basically 1#'
          $'       / pad ($) each-both
  (      )         / do together
      !26          / range 0..25
   -1-             / subtract from -1

Bonus:

15 bytes returning a list of strings rather than printing to STDOUT:

(-1-!26)$'$.Q.a

Answer 87

QBasic 1.1, 35 bytes

FOR S=0TO 25
?SPC(S)CHR$(S+97)
NEXT

-8 thanks to DLosc.

Answer 88

Z80Golf, 19 bytes

00000000: c661 ff3e 0aff 3e20 0c41 ff10 fd79 fe1a  .a.>..> .A...y..
00000010: 20ee 76                                   .v

Try it online!

Disassembly:

restart:
  add 'a'
  rst $38
  ld a, '\n'
  rst $38
  ld a, ' '
  inc c
  ld b, c
k:rst $38
  djnz k
  ld a, c
  cp 26
  jr nz, restart
  halt

Answer 89

Pascal (FPC), 56 bytes

Well, I found 2 programs with the same number of bytes.

Program 1:

var c:char;begin for c:='a'to'z'do writeln(c:ord(c))end.

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Explanation:

var c:char; //declare c as char variable
begin
  for c:='a' to 'z' do //iterate in a loop, c is getting values from a to z
    writeln(c          //write the current character followed by a newline
             :         //with a width of
              ord(c))  //ASCII code of the current character
                       //(using extraneous whitespace allowed by the challenge)
end.

Program 2:

var i:byte;begin for i:=97to 122do writeln(chr(i):i)end.

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Explanation:

var i:byte; //declare i as integer variable in range 0..255
begin
  for i:=97 to 122 do //iterate in a loop, i starts from 97 and is incremented in each iteration
    writeln(chr(i)    //write character which ASCII codepoint is the current value of i
                  :   //with a width of
                   i) //current value of i
                      //(using extraneous whitespace allowed by the challenge)
end.

Answer 90

brainfuck, 74 bytes

++++++++[->+++>+>++++++++>++++<<<<]>++>++<[->>>>[-<.>>+<]+>[-<+>]<<<+.<.<]

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Explanation

++++++++[->+++>+>++++++++>++++<<<<]>++>++ Initialize tape:
26(letter count) 10(lf) 64("A" minus 1) 32(" ") 0(space count) 0(temp) 

<[                                        for each letter count
  -                                       decrement letter count
  >>>>[-<.>>+<]                           for each space count print space and move value to temp
  +                                       increment space count
  >[-<+>]                                 add temp to space count
  <<<+.                                   increment and print letter
  <.                                      print lf
  <                                       go to count
]

Answer 91

C (gcc), 37 bytes

f(i){for(i=2912;i++%113;printf(&i));}

Inspired by @NieDzejkob; needs to be run on a little endian ASCII machine from a terminal supporting vertical tabs. Try it online!

Answer 92

Javascript, 75 72 bytes

_=>[...'abcdefghijklmnopqrstuvwxyz'].map((n,i)=>' '.repeat(i)+n).join`
`

3 bytes thanks to Stephen S.

Answer 93

Cheddar, 31 bytes

->(|>26).map(n->' '*n+@"(n+97))

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Defines a niladic lambda which returns a list of strings.

Full program, 42 bytes

print(|>26).map(n->' '*n+@"(n+97)).asLines

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Answer 94

Mathematica, 42 bytes

Table[" "~Table~i<>Alphabet[][[i]],{i,26}]

outputs a list of strings

Answer 95

Braingolf, 24 bytes

V# 7-#
R#a[R!&@# >1+v!@]

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Explanation

V# 7-#\nR#a[R!&@# >1+v!@]
V                          Create stack2 and switch to it
 # 7-                      Push 32 and subtract 7
     #\n                   Push newline
        R                  Return to stack1
         #a                Push lowercase a
           [............]  Do-while loop, uses stack2 for loop counting
                           Will run 26 times
            R              Return to stack1
             !&@           Print entire stack without popping
                # >        Push space and move it to start of stack
                   1+      Increment letter
                     v     Switch to stack2
                      !@   Print newline

Answer 96

Noether, 52 bytes

"abcdefghijklmnopqrstuvwyxz"~aL(" "i*Pai/P"
"Pi1+~i)

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Pushes the alphabet and loops through it, increasing the number of spaces before the character by one each time.

---

A non competing solution for 26 24 bytes is:

26(" "i*P0Ai/P"
"Pi1+~i)

Try it here!

Answer 97

Aceto, 28 bytes

L 'XcIo
p*=`MILp
aM{'&n
'@dL

Explanation:

First of all, we put the character a in our quick storage ('aM) and set a catch point (@). We then duplicate the top stack element (initially a zero) and load both from quick storage and from the character literal {. These characters are then tested for equality, in which case we exit (=`X).

Otherwise we push a space and multiply it with the previously duplicated stack element (used as a counter). This is then printed, which prints nothing the first time this is run, a single space the second time, and so on (' *p).

We load the current character again and print it, then we load it again, convert it to the number of its codepoint, increment it, convert it to a character again and memorize it (LpLoIcM). Finally, we increment our counter, print a newline, and jump to the catch mark (In&).

Answer 98

S.I.L.O.S, 101 bytes

a=26
c=97
lblb
i=0
GOTO d
lblc
print  
b-1
i+1
lbld
if b c
b=i+1
printChar c
printLine
a-1
c+1
if a b

Try it online!

Answer 99

LOGO, 47 bytes

Can be tried with FMSLogo. Unfortunately the version at Turtle Academy does not work well.

for[i 0 25][repeat :i[type "\ ]show char 65+:i]

Answer 100

Oracle SQL, 62 bytes

SELECT LPAD(CHR(LEVEL+96),LEVEL) FROM DUAL CONNECT BY LEVEL<27

Answer 101

AWK, 40 bytes

BEGIN{for(;++i<27;)printf"%"i"c\n",i+96}

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I'm curious if there's a shorter way to do this in AWK.

Answer 102

C# 73 68 bytes (Thanks to raznagul)

I'm pretty new to this. Do I need to include class/main declaration overhead for C#?

Edited to include anonymous function declaration

()=>{for(var x='a';x<123;)Console.WriteLine("".PadLeft(x-97)+x++);};

Answer 103

Micro, 35 bytes

64:i {i1+:i i c:\
64 26+i=if(,a)}:a a

Answer 104

Pyke, 6 bytes

G Foh-

Try it here!

G      -  alphabet
  Foh- - for i in ^:
   oh  -   (o++)+1
     - -  i.pad(" ", ^)

Answer 105

Pyke, 4 bytes

G\J

G   - alphabet
 \J - "\x0B".join(^)

Joins alphabet by vertical tabs

Answer 106

SimpleTemplate, 66 42 bytes

This simply loops through all characters and outputs them one by one, with newlines and spaces.

{@forfrom"a"to"z"}{@echolV,_}{@setV V," "}

This abuses the automatic variable _ and the automatic flattening of echoed arrays and automatic newline with echol.

Ungolfed: (produces invalid results due to whitespace)

{@for chr from "a" to "z"}
    {@echo indentation, chr, "\n"}
    {@// will create an array like: [[[..., " "], " "], " "]}
    {@set indentation indentation, " "}
{@/}{@// automatically added after the code}

---

---

Old version:

There's a repeat function, but I couldn't use it because it's broken.
But this works too.

{@for_ from"a"to"z"}{@incz}{@callstr_repeat intos" ",z}{@echols,_}

---

Ungolfed: (produces incorrect results due to whitespace added)

{@set z 0}{@//removes warning}
{@for chr from "A" to "Z"}
    {@inc spaces by 1}
    {@call str_repeat into indentation " ", spaces}
    {@echo indentation, chr, "\n"}
{@/}{@// automatically added after the code}

Answer 107

Rexx (Regina), 41 37 bytes

do i=1 to 26
  say right(d2c(96+i),i)
end

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Answer 108

Batch, 187 114 bytes

@set s=
@for %%p in (a b c d e f g h i j k l m n o p q r s t u v w x y z)do @call:e %%p
:e
@echo(%s%%1
@set s= %s%

Answer 109

Modern Pascal 2.0, 43 bytes

for var l:=97 to 122 do write(chr(l),#13);

Explanation For loop range is the ascii of 'a' to 'z', and the output is converting the ordinal to character, followed by LF (Line Feed, not CRLF), thus producing a forward diagonal alphabet. Also, Modern Pascal does not require the Begin/End block on simple instructions like this.

// Author of Modern Pascal

Answer 110

tcl, 54 47

time {puts [format %[incr i]c [expr $i+96]]} 26

demo

Answer 111

vim 14+16=30 keystrokes

16 keystrokes if you have alpha in nrformats already (I mean, who hasn't?), 30 otherwise.

:set nf=alpha<cr>
ia<esc>
qqYp<c-a>I <esc>q
24@q

Angle brackets denote single characters, e.g. <c-a> is ctrl+a (increment). Actual newlines only for clarity. Seriously, set nf+=alpha is really neat, and it's a feature I've missed in a few specific cases when programming.

Answer 112

Retina, 93 bytes

aAbBc¶3d¶4e¶5f¶6g¶7h¶8i¶9jA0kA1lA2mA3nA4oA5pA6qA7rA8sA9tB0uB1vB2wB3xB4yB5z
B
¶2
A
¶1
\d+
$* 

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Answer 113

C#, 82 bytes

var b="";for(int i=0;i<=25;i++){var a=(char)(97+i);b+=new string(' ',i)+a+"\r\n";}

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Answer 114

Swift 3, 75 bytes

for i in 0..<26{print(String(repeating:" ",count:i)+String(i+10,radix:36))}

Answer 115

Groovy, 40 38 bytes

i=0;("a".."z").each{println" "*++i+it}

Previous solution:

0.upto(25){println" "*it+("a".."z")[it]}

iis used to store the number of spaces that must be printed before each letter. The program iterates through the range "a".."z" (the alphabet), printing each letter with i spaces before it and increments i inline.

Answer 116

Common Lisp, SBCL, 70 bytes

(dotimes(i 26)(format t"~v@t~a
"i(aref"abcdefghijklmnopqrstuvwxyz"i)))

Looping through letters of alphabet and outputting accurate number of spaces before each letter.

another 70 bytes solution:

(format t"~{~26<~a~#@t~>
~}"(coerce"abcdefghijklmnopqrstuvwxyz"'list))

looping through letters and justifying to 26 columns, where word to justify is letter+accurate number of spaces.

building alphabet list using code-char would make it 76 bytes:

(format t"~{~26<~a~#@t~>
~}"(loop as i from 97 to 122 collect(code-char i)))

Answer 117

dc, 53 52 bytes

0si[32Plj1+dsjli>S]sS[0sjlid0<S1+dsi64+dPAP90>M]dsMx

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Uppercase because checking that we're below character 90 (Z) is one fewer byte than checking that we're below character 122 (z). Otherwise pretty straightforward: one macro to print spaces and another to call the spacing macro, print the letter, and print a newline.

-1 byte because I forgot to golf my 10 into an A.

Answer 118

Pyth, 9 bytes

m+*;xGddG

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The other Pyth approach is golfier because it uses enumerated map, which is 1 byte shorter. I just wanted to post a solution with regular map m, that happens to use the same variable, d as the built-in space. That may be inconvenient, because you cannot refer to the space with d. However, I did a work-around with ;, which gets the global value of the innermost lambda variable.

This returns a list of lines. In order to join them by newlines, we just need to add j in front of the whole code (the link contains the j for readability).

Explanation

jm+*;xGddG  - Full program.

 m       G  - Map over the alphabet with a variable d.
  +         - Add:
   *          - The multiplication of:
     xGd        - The index of the current letter in the alphabet (0-indexed) and
    ;           - Space (which is the global value of d, the innermost lambda 
variable).
        d     - The current letter.
j           - Optional: Join by newlines.

Answer 119

QBasic, 54 bytes

SCREEN 12
FOR x=1TO 26
LOCATE x,x
?CHR$(x+96)
NEXT

Explanation

SCREEN 12       Set the screen mode to something that can actially handle > 20 chars on a line
FOR x=1TO 26    Loop from 1 to 26
LOCATE x,x      Set the cursior to the screen position x,x, starting at 1,1 on the top left.
?CHR$(x+96)  Print the current letter of the alphabet
NEXT

Answer 120

C++ (gcc), 73 bytes

As unnamed generic lambda, requires a stream as parameter (like std::cout)

[](auto&O){for(char c=96;++c<123;O<<c<<'\n')for(char w=c-96;--w;O<<' ');}

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Answer 121

Recursiva, 16 15 bytes

{)"P+*-O}97' '}

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Explanation:

{)"P+*-O}97' '}
{                - For each
 )               - lower-case alphabet yield 'abc...z'
  "              - Iteration command begin
   P             - Print
    +            - concatenate
     *-O}97' '   - Appropriate number of spaces
              }  - current alphabet (iterate)          

Answer 122

Pushy, 10 bytes

`a\x26`:"h32}

Where \x26 represents the literal byte 0x26.

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`a\x26`         \ Push 'a' and 26
       :        \ Pop 26, loop that many times:
        "       \   Print the stack
         h      \   Increment the letter
          32}   \   Prepend a space

Answer 123

AWK, 40 bytes

BEGIN{for(;i<26;)printf"%"++i"c\n",i+96}

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I didn't see an AWK solution, so here we go. Straightforward implementation, so more golfing may be possible.

Answer 124

Sincalr ZX81/Timex TS1000/1500 BASIC, ~45 tokenized BASIC bytes

 1 FOR I=CODE "A" TO CODE "Z"
 2 PRINT TAB (I-CODE "A");CHR$ I
 3 NEXT I

Some notes; without adding in more bytes to the listing, the standard output to the screen is 32 x 22 only, so when the screen fills, you will need to press C, and the keyword CONT will appear. You will then see the rest of the alphabet.

For those who want to see the Alphabet without having to manually enter CONT each time the last row is hit in the text area, this solution does it for you:

 1 FOR I=CODE "A" TO CODE "Z"
 2 PRINT AT CODE "+",I-CODE "A";CHR$ I
 3 SCROLL
 4 NEXT I

This version costs another 9 tokenized bytes though.

Answer 125

SNOBOL4 (CSNOBOL4), 72 65 bytes

E	&LCASE POS(X) LEN(1) . O @X	:F(END)
	OUTPUT =LPAD(O,X)	:(E)
END

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swapping &UCASE for &LCASE would do the uppercase diagonal instead.

Answer 126

Pyth, 12 bytes

Fb26p*\ b@Gb

There's probably some way I can shave off a couple bytes, but I'm not quite sure yet.

Explanation:

Fb26p*\ b@Gb |
Fb26         | for b in range(26):
    p        |     print(
     *\ b    |           " "*b
         @Gb |                +G[b]

Note: G is initialized to "abcdefghijklmnopqrstuvwxyz"

Answer 127

MY-BASIC, 62 bytes

Anonymous function that takes no input and outputs to the console.

For i=0 To 25
For j=1 To i
Print" "
Next
Print Chr(65+I);
Next

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Answer 128

Visual Basic .NET (Mono), 98 bytes

Declared Subroutine that that takes no input and outputs to the console.

Module M
Sub Main
Dim I
For I=0To 25
Console.WriteLine(Space(i)+Chr(65+I))
Next
End Sub
End Module

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Answer 129

Momema, 51 bytes

m01*0w1-9 32 1+*1-1w0w=*1-9+97*0-9 10 0+1*0m=+-26*0

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Explanation:

                                                              #  a = 0
m   0        #  label m0: jump past label m0 (no-op)          #  do {
1   *0       #            [1] = [0]                           #    b = a
w   1        #  label w0: jump past label w1                  #    while b != 0 {
-9  32       #            print chr 32                        #      print ' '
1   +*1-1    #            [1] = [1] - 1                       #      b -= 1
w   0        #  label w1: jump past label w0 (no-op)          #    [end-of-loop jump point]
w   =*1      #  label w2: jump past label w((2 + !![1]) % 3)  #    }
-9  +97*0    #            print chr 97 + [0]                  #    print chr(97 + a)
-9  10       #            print chr 10                        #    print '\n'
0   +1*0     #            [0] = [0] + 1                       #    a += 1
m   =+-26*0  #  label m1: jump past label m((1 + !![0]) % 2)  #  } while a != 0

Answer 130

Python 3, 74 64 63 Bytes

Saved ten bytes thanks to Caird

Saved one byte thanks to Stephen

Changed format to one-liner

Yes there are several Python 2 answers but how about one with Python 3?

for b in'abcdefghijklmnopqrstuvwxyz':print(' '*(ord(b)-97)+b)

First it makes a list of the alphabet then prints each letter but with n (Index of the value) spaces.

Answer 131

Python 3, 51 bytes

print("\n".join(" "*n+chr(n+97)for n in range(26)))

Answer 132

Japt -R, 7 bytes

;C¬ËiEç

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Answer 133

PHP, 72 68 67 Bytes

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Try it online (after @Titus review)

Try it online, last review. @Titus Strikes Back

Code, recursive function

function f($v=26){$v&&print str_pad("",$v).chr($v+96)." 
".f($v-1);}

Explanation

function f($v=26){
    $v&&print           # if $v not zero then print
    str_pad("",$v)     # pad spaces $v times
    .chr($v+96)     # concat the character at 96+$v 
    ."                 # concat a linebreak 
    ".f($v-1);          # call the function 
}

Answer 134

Java (OpenJDK 8), 58 bytes

a->{for(char b=96;b++<122;a+=' ')System.out.println(a+b);}

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I had no idea that you could make a for loop with a char variable... but here ya go! I’m pretty proud of my solution here, it may be my most golfed submission to date!

Answer 135

Add++, 43 36 bytes

D,f,@:^,32$yVVL97+
D,g,,26RBF€{f}
$g

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Super suboptimal because I don't know what I'm doing

Answer 136

Python 2, 56 bytes

a=map(chr,range(65,91))
for i in a:print' '*a.index(i)+i

Answer 137

CJam, 13 bytes

26{_S*\'a+N}/

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Explanation

26{        }/  for i in [0..25]:
    S*           puts ' ' * i
   _  \'a+       puts 'a' + i
          N      puts '\n'

Answer 138

Ahead, 31 30 bytes

"az"E>0\:'a-' l
  @?lj:oNW:k\<

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-1 because leading spaces are allowed as long as everything is still aligned.

Answer 139

Ruby, 43 bytes

(0..25).each{|n|print" "*n;puts (n+97).chr}

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Answer 140

Perl 6, 24 bytes

{map ' 'x$++~*,'a'..'z'}

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Anonymous code block that returns a list of lines.

Alternatively,

{' 'x$++xx㉖Z~'a'..'z'}

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behaves the same for the same bytecount.

Answer 141

C# (.NET Core), 71 58 53 52 bytes

for(var i='A';i<91;)WriteLine("".PadLeft(i-65)+i++);

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Answer 142

dc, 28 bytes

97[ddPAP1+2z8*B-^+z27>M]dsMx

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Outputs to stdout, makes lowercase letters

Explanation

P pops a number from the stack and outputs it as a base-256 byte stream. So I use some math to calculate each number (representing the appropriate string) "inductively" from the previous.

97        A literal, which P will print as ASCII 97 ('a')
[         Each loop starts with these two things true:
              The next number to Print is on top of the stack
              The stack depth is the # of times the loop has started (inclusive)
  dd        Make two copies: one to manipulate stack depth, one to print
  PAP       Print the number, then Print a newline (0x0A)
  1+        Increment the last digit (i.e., the letter)
  2z8*B-^+  Add the leftmost space, calculated as: 
                 32*(256^loop counter)  (because 32 = ' ')
               = 2^5*(2^8)^(z-2)        (z = stack depth = counter + 2)
               = 2^(8z-11)              (and to dc, 'B' pushes literal 11)
  z27>M     Repeat unless this was our 26th time through
]dsMx       End the loop, store it as a macro, and run it

Answer 143

><>, 35 Bytes

0::?\~1+:8c*+oao:55*)?;!
-10.\84*o1

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0                         initialise counter
 :                        make a copy to count spaces
  :?\                     only keep looping if greater than 0
    \84*o                 output a space
-        1                decrement the inner counter
 10.                      jump back to the start of the inner loop
     ~                    delete the inner loop counter
      1+                  increment the outer counter
        :8c*+o            make a copy of the counter, add 96, output the character
              ao          output a newline
                :55*)?;   terminate if the counter is now 26 or higher
                       !  skip the 0 at the start of the line

Answer 144

Red, 37 bytes

repeat n 26[print pad/left #"`"+ n n]

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Answer 145

Dart, 65 bytes

f()=>List.generate(26,(i)=>String.fromCharCode(i+65).padLeft(i));

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Answer 146

C++ (gcc), 50 48 bytes

[](){for(int c=0;printf("%*c\n",++c,c+97)-27;);}

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Answer 147

MBASIC, 43 bytes

1 FOR I=0 TO 25:PRINT SPC(I)CHR$(97+I):NEXT

similar to Alphabet Staircase.

Answer 148

PowerShell Core, 27 bytes

'a'..'z'|%{' '*(+$_-97)+$_}

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Answer 149

Python 3 43 Bytes

for i in range(26):print(" "*i+chr(i+97))

Answer 150

Aheui (esotope), 183 bytes (65 chars; 59 Hangul, 6 ASCII)

발밦다빠따반두발따받타빠싺싻삮타빠바파자초
분벋서썩떠번벌또여cbtp어또벓범석터번벋
타타빠싹빠싺밨볺아멓히셕처오져퍼서써섟뻐서

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---

"cbtp" in the middle of the code is just an abbreviation of my nickname, which is ignored by the interpreter and reduce 8 bytes by using ASCII, not Hangul.

Answer 151

Pushy, 10 bytes

`a\0x1A;`:"32}h

Where \0x1A is the character 26, 'SUB'

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Answer 152

Attache, 21 bytes

Output[sp*0:25+$a:$z]

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Explanation

Output[sp*0:25+$a:$z]
Output[             ]     write each entry as a line to stdout:
       sp*0:25                spaces repeated 0 to 25 times (array)
              +$a:$z          each followed by a letter from "a" to "z"

Alternatives

22 bytes: Output[" "*0:25+$a:$z]

23 bytes: Print=>(" "*0:25+$a:$z)

24 bytes: Print@{_*sp+NTS@_}=>0:25

31 bytes: Print@&PadLeft=>Zip[$a:$z,1:26]

35 bytes: {Print@_If[$z!in_,$[sp+Succ@_]]}@$a

37 bytes: {Print@_If[_@-1/=$z,$[sp+Succ@_]]}@$a

37 bytes: Print@&PadLeft=>Zip[Chars@alpha,1:26]

40 bytes: Output!ZipWith[PadLeft,Chars@alpha,1:26]

40 bytes: Print=>ZipWith[PadLeft,Chars@alpha,1:26]