2018 Oracle Challenger Series – Indian Wells – Women's Doubles

Taylor Townsend and Yanina Wickmayer won the title after defeating Jennifer Brady and Vania King 6–4, 6–4 in the final.

Indian Wells – Women's Doubles
2018 Oracle Challenger Series – Indian Wells
Champions	Taylor Townsend Yanina Wickmayer
Runners-up	Jennifer Brady Vania King
Final score	6–4, 6–4

Main article: 2018 Oracle Challenger Series – Indian Wells

This was the first edition of the tournament.

Seeds

1. Raluca Olaru / Olga Savchuk (First round)
2. Barbora Krejčíková / Vera Lapko (Semifinals)
3. Jennifer Brady / Vania King (Final)
4. Duan Yingying / Wang Yafan (Quarterfinals)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	R Olaru O Savchuk	3	5
		S Chang A Mueller	6	7					S Chang A Mueller	1	1
		C Dolehide A Riske	6	6					C Dolehide A Riske	6	6
		N Broady E Hrdinová	3	3												C Dolehide A Riske	2	3
	3	J Brady V King	6	6											3	J Brady V King	6	6
		M Doi E Rodina	4	3				3	J Brady V King	6	6
		PC Gonçalves S Marand	6	6^8	[1]			WC	J Elbaba I Neel	1	3
	WC	J Elbaba I Neel	3	7^10	[10]																	3	J Brady V King	4	4
		V Golubic M Linette	1	3																			T Townsend Y Wickmayer	6	6
		T Townsend Y Wickmayer	6	6					T Townsend Y Wickmayer	6	6^5	[10]
	Alt	S Kenin A Weinhold	1	6^3				4	Y Duan Y Wang	4	7^7	[6]
	4	Y Duan Y Wang	6	7^7												T Townsend Y Wickmayer	6	6^3	[10]
		A Tomljanović V Zvonareva	4	6	[5]										2	B Krejčíková V Lapko	2	7^7	[6]
		A Petkovic F Schiavone	6	3	[10]				A Petkovic F Schiavone	3	4
		K Bondarenko V Lepchenko	0	0				2	B Krejčíková V Lapko	6	6
	2	B Krejčíková V Lapko	6	6

References

• Main Draw