Vinogradovo, Sheksninsky District, Vologda Oblast
Vinogradovo (Russian: Виноградово) is a rural locality (a village) in Sizemskoye Rural Settlement, Sheksninsky District, Vologda Oblast, Russia. The population was 4 as of 2002.[2]
Vinogradovo Виноградово | |
|---|---|
Village | |
  Vinogradovo  Vinogradovo | |
| Coordinates: 59°23′N 38°29′E[1] | |
| Country | Russia |
| Region | Vologda Oblast |
| District | Sheksninsky District |
| Time zone | UTC+3:00 |
Geography
The distance to Sheksna is 33 km, to Charomskoye is 9 km. Shigoyevo is the nearest rural locality.
gollark: https://math.stackexchange.com/questions/1803080/if-the-left-riemann-sum-of-a-function-converges-is-the-function-integrable
gollark: It seems to be if you use the WRONG version, is the thing.
gollark: Apparently, if you integrate the "characteristic function of the rational numbers" (1 if rational, 0 otherwise) from 0 to 1, you will attain 1, because x is always rational (because b - a is 1, and all the partitions are the same size), even though it should be 0.
gollark: For another thing, as I found out while reading a complaint by mathematicians about the use of Riemann integrals over gauge integrals, if you always take the point to "sample" as the left/right/center of each partition *and* the thing is evenly divided up into partitions, it's actually wrong in some circumstances.
gollark: For one thing, the sum operator is very bee there because it does not appear to be counting integers.
References
- Карта Шекснинского района Вологодской области
- Данные переписи 2002 года: таблица 2С. М.: Федеральная служба государственной статистики, 2004.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.