Victoria Dyring

Sonja Victoria Dyring (born 18 December 1972 in Uppsala)[1] is a Swedish TV host and film producer. She is a former host of the knowledge TV program Hjärnkontoret.[2][3][4] Since 2010 she has hosted Vetenskapens värld.[5][6] She has also hosted and appeared on Vi i femman (2001–03, together with Jonas Hallberg[7]), National Day celebrations, Nobel Prize programmes and Lilla Melodifestivalen (in 2003[8]).

Victoria Dyring
Victoria Dyring
Born (1972-12-18) 18 December 1972
Uppsala, Sweden
OccupationTV presenter, film producer

Education[9]

Dyring's parents are science journalists and her sister is physicist. Dyring studied theatre at university. She has also studied natural science.

Awards

References/sources
  1. "Sök personer - Birthday.se". Retrieved 1 October 2015.
  2. "Aftonbladet nyheter: Grattis... Victoria Dyring". Aftonbladet. Retrieved 1 October 2015.
  3. "Aftonbladet puls: på pulsen". Aftonbladdet. Retrieved 1 October 2015.
  4. "Aftonbladet resor: Resfolk: "Hjärnkontorets" Victoria Dyring". Aftonbladet. Retrieved 1 October 2015.
  5. "Dyring tar över "Vetenskapens värld"". Retrieved 1 October 2015.
  6. Spektra. "Dyring tar över "Vetenskapens värld"". SvD.se. Retrieved 1 October 2015.
  7. "Svensk mediedatabas (SMDB)". Retrieved 1 October 2015.
  8. "Lilla Melodifestivalens vinnare". SvD.se. Retrieved 1 October 2015.
  9. "Victoria Dyring". miagahne.se. Retrieved 1 October 2015.
  10. "Victoria Dyring får Gunilla Arhéns Ruter Dam Jubileumspris "Entusiastpris" på 15.000:-". Retrieved 1 October 2015.
  11. "Victoria Dyring utsedd till hedersdoktor". svt.se. Archived from the original on 18 April 2010. Retrieved 1 October 2015.
  12. "Årets hedersdoktorer vid Stockholms universitet". Mynewsdesk. Retrieved 1 October 2015.
gollark: Although I don't know why you can't long-divide it, p and q are just constants for the purposes of that.
gollark: That lets you work out a/b/c/d, which you can substitute back into (x-1)(ax^3+bx^2+cx+d).
gollark: So:2 = a (x^4 terms)p = b - a (x^3 terms)-6 = c - b (x^2 terms)q = d - c (x terms)6 = -d (constant terms)
gollark: So you can do `2x^4+ px^3 - 6x^2 + qx + 6 = ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d`, and you know the coefficients on x^4 and so on should be equal.
gollark: Which you can then simplify to ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d.
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