Sophia Aliberti
Sophia Aliberti (Greek: Σοφία Αλιμπέρτη) is a Greek talk show and game show host since 2004, television actress and former fashion model.
Sophia Aliberti Σοφία Αλιμπέρτη | |
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Born | Sophia Parlama (Σοφία Παρλαμά) |
Occupation | Actress, television host, model |
Spouse(s) | Yiannis Parios (1986–1996) |
Filmography
- Ta Tsakalia: Ena koinoniko provlima, 1981 .... Athina Fotiadou
- Garsoniera gia deka 1981
- Apenanti, Oi 1981
- Vasika... kalispera sas 1982 .... Lilian
- Strofi, I 1982 .... Stefi
- Kamikazi, agapi mou 1983 .... Sofia Paskhalidi
- Epikindynoi (Mia diamartyria), Oi 1983
- Thilyko thiriotrofeio 1983
- Rakos... No. 14, kai o protos bounakias 1985 .... Sophia Paskhalidi
- Skiahtra, I 1985
- Tile-kannivaloi 1987 .... Marina
- Lordan, o varvaros 1987 .... Varvara
- Paidia tis Helidonas, Ta 1987
- Goiteia tou hrimatos, I 1988
- M' agapas? 1989
- Ena atithaso koritsi 1989 .... Sophia
gollark: I'm not entirely sure how, but it seems to construct a tree/maybe deterministic finite automaton/finite state machine/I don't know theoretical CS which matches anagrams and unmatches unanagrams.
gollark: ```pythonimport collectionsdef do_thing(s): if len(s) == 1: return { s[0]: True } out = {} for i, c in enumerate(s): without = s[:i] + s[i + 1:] things = do_thing(without) out[c] = things return outdef match(r, s): print(r) c = r for i, x in enumerate(s): print(x) try: c = c[x] if c == True: if i + 1 == len(s): return True # full match else: return False # characters remain except KeyError: return False # no match return False # incomplete matchentry = lambda a, b: match(do_thing(a.lower().replace(" ", "")), b.lower().replace(" ", ""))```Here is my entry (pending a port to osmarkslisp™️). This is definitely my entry.
gollark: I wish to use Mathematica in my code. Please install it. DO NOT READ, ubq.
gollark: I have a "great" way to do this which I think takes O(n²) space-time-beeite.
gollark: Perhaps it is also possible to construct some sort of regex/deterministic finite automaton to match things matching anagramatically.
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