Sakurako
Sakurako (written 桜子 or 櫻子) is a feminine Japanese given name. Notable people with the name include:
- Sakurako Gokurakuin (極楽院 櫻子), Japanese manga artist
- Sakurako Kaoru (born 1982), Japanese gravure model and AV idol
- Sakurako Kimino (公野 櫻子), Japanese writer
- Sakurako Ohara (大原櫻子) (born 1996), Japanese actress and singer
- Sakurako Okubo (大久保櫻子) (born 1998), Japanese actress
- Sakurako Terada (寺田 桜子) (born 1984), Japanese curler
Gender | Female |
---|---|
Language(s) | Japanese |
Origin | |
Word/name | Japanese |
Meaning | Different meanings depending on the kanji used |
Region of origin | Japan |
Other names | |
Related names | Sakura, Sakurano, Sakurana, Sakurazawa |
Look up Sakurako in Wiktionary, the free dictionary. |
Fictional characters
- Sakurako Kujō (九条 櫻子), a character in the light novel Beautiful Bones: Sakurako's Investigation
- Sakurako Minase (水無瀬 桜子), a character in the visual novel Flyable Heart
- Sakurako Ohmuro (大室 櫻子), a character in the manga series YuruYuri
- Sakurako Sawatari (沢渡 桜子), a character in the television series Kamen Rider Kuuga
- Sakurako Shiina (椎名 桜子), a character in the manga series Mahō Sensei Negima!
- Sakurako Yukihira (雪平 桜子), a character in the manga series Detective School Q
gollark: So:2 = a (x^4 terms)p = b - a (x^3 terms)-6 = c - b (x^2 terms)q = d - c (x terms)6 = -d (constant terms)
gollark: So you can do `2x^4+ px^3 - 6x^2 + qx + 6 = ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d`, and you know the coefficients on x^4 and so on should be equal.
gollark: Which you can then simplify to ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d.
gollark: ax^4 + bx^3 + cx^2 + dx - ax^3 - bx^2 - cx - d
gollark: If you expand/simplify (x-1)(ax^3+bx^2+cx+d) you get, er, a lot of things, hold on.
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