Outer automorphism group

In mathematics, the outer automorphism group of a group, $G$ , is the quotient, $Aut(G) / Inn(G)$ , where $Aut(G)$ is the automorphism group of $G$ and $Inn(G$ ) is the subgroup consisting of inner automorphisms. The outer automorphism group is usually denoted $Out(G)$ . If $Out(G)$ is trivial and $G$ has a trivial center, then $G$ is said to be complete.

An automorphism of a group which is not inner is called an outer automorphism. The cosets of $Inn(G)$ with respect to outer automorphisms are then the elements of $Out(G)$ ; this is an instance of the fact that quotients of groups are not, in general, (isomorphic to) subgroups. If the inner automorphism group is trivial (when a group is abelian), the automorphism group and outer automorphism group are naturally identified; that is, the outer automorphism group does act on the group.

For example, for the alternating group, $A n$ , the outer automorphism group is usually the group of order 2, with exceptions noted below. Considering $A n$ as a subgroup of the symmetric group, $S n$ , conjugation by any odd permutation is an outer automorphism of $A n$ or more precisely "represents the class of the (non-trivial) outer automorphism of $A n$ ", but the outer automorphism does not correspond to conjugation by any particular odd element, and all conjugations by odd elements are equivalent up to conjugation by an even element.

Structure

The Schreier conjecture asserts that $Out(G)$ is always a solvable group when $G$ is a finite simple group. This result is now known to be true as a corollary of the classification of finite simple groups, although no simpler proof is known.

As dual of the center

The outer automorphism group is dual to the center in the following sense: conjugation by an element of $G$ is an automorphism, yielding a map $σ : G \to Aut(G)$ . The kernel of the conjugation map is the center, while the cokernel is the outer automorphism group (and the image is the inner automorphism group). This can be summarized by the exact sequence:

Z(G) ↪ G σ \to Aut(G) ↠ Out(G)

.

Applications

The outer automorphism group of a group acts on conjugacy classes, and accordingly on the character table. See details at character table: outer automorphisms.

Topology of surfaces

The outer automorphism group is important in the topology of surfaces because there is a connection provided by the Dehn–Nielsen theorem: the extended mapping class group of the surface is the outer automorphism group of its fundamental group.

In finite groups

For the outer automorphism groups of all finite simple groups see the list of finite simple groups. Sporadic simple groups and alternating groups (other than the alternating group, $A 6$ ; see below) all have outer automorphism groups of order 1 or 2. The outer automorphism group of a finite simple group of Lie type is an extension of a group of "diagonal automorphisms" (cyclic except for $D n (q)$ , when it has order 4), a group of "field automorphisms" (always cyclic), and a group of "graph automorphisms" (of order 1 or 2 except for $D 4 (q)$ , when it is the symmetric group on 3 points). These extensions are not always semidirect products, as the case of the alternating group $A 6$ shows; a precise criterion for this to happen was given in 2003.[1]

Group	Parameter	$Out(G)$	$\| Out(G) \|$
$Z$		$C 2$	$2$ : the identity and the outer automorphism $x \mapsto - x$
$C n$	$n > 2$	$(ℤ/ n ℤ) \times$	$φ (n) =$ $n\prod _{p\|n}\left(1-{\frac {1}{p}}\right)$ ; one corresponding to multiplication by an invertible element in the ring $ℤ/ n ℤ$ .
$Z p n$	$p$ prime, $n > 1$	$GL n (p)$	$(p n - 1)(p n - p)(p n - p 2)...(p n - p n -1)$
$S n$	$n \neq 6$	$C 1$	$1$
$S 6$		$C 2$ (see below)	$2$
$A n$	$n \neq 6$	$C 2$	$2$
$A 6$		$C 2 \times C 2$ (see below)	$4$
$PSL 2 (p)$	$p > 3$ prime	$C 2$	$2$
$PSL 2 (2 n)$	$n > 1$	$C n$	$n$
$PSL 3 (4) = M 21$		$Dih 6$	$12$
$M n$	$n \in {11, 23, 24}$	$C 1$	$1$
$M n$	$n \in {12, 22}$	$C 2$	$2$
$Co n$	$n \in {1, 2, 3}$	$C 1$	$1$

In symmetric and alternating groups

The outer automorphism group of a finite simple group in some infinite family of finite simple groups can almost always be given by a uniform formula that works for all elements of the family. There is just one exception to this:[2] the alternating group $A 6$ has outer automorphism group of order 4, rather than 2 as do the other simple alternating groups (given by conjugation by an odd permutation). Equivalently the symmetric group $S 6$ is the only symmetric group with a non-trivial outer automorphism group.

{\begin{aligned}n\neq 6:\operatorname {Out} (\mathrm {S} _{n})&=\mathrm {C} _{1}\\n\geq 3,\ n\neq 6:\operatorname {Out} (\mathrm {A} _{n})&=\mathrm {C} _{2}\\\operatorname {Out} (\mathrm {S} _{6})&=\mathrm {C} _{2}\\\operatorname {Out} (\mathrm {A} _{6})&=\mathrm {C} _{2}\times \mathrm {C} _{2}\end{aligned}}

Note that, in the case of $G = A 6 = PSL(2, 9)$ , the sequence $1 ⟶ G ⟶ Aut(G) ⟶ Out(G) ⟶ 1$ does not split. A similar result holds for any $PSL(2, q 2)$ , $q$ odd.

In reductive algebraic groups

The symmetries of the Dynkin diagram,

D 4

, correspond to the outer automorphisms of

Spin(8)

in triality.

Let $G$ now be a connected reductive group over an algebraically closed field. Then any two Borel subgroups are conjugate by an inner automorphism, so to study outer automorphisms it suffices to consider automorphisms that fix a given Borel subgroup. Associated to the Borel subgroup is a set of simple roots, and the outer automorphism may permute them, while preserving the structure of the associated Dynkin diagram. In this way one may identify the automorphism group of the Dynkin diagram of $G$ with a subgroup of $Out(G)$ .

$D 4$ has a very symmetric Dynkin diagram, which yields a large outer automorphism group of $Spin(8)$ , namely $Out(Spin(8)) = S 3$ ; this is called triality.

In complex and real simple Lie algebras

The preceding interpretation of outer automorphisms as symmetries of a Dynkin diagram follows from the general fact, that for a complex or real simple Lie algebra, $𝔤$ , the automorphism group $Aut(𝔤)$ is a semidirect product of $Inn(𝔤)$ and $Out(𝔤)$ ; i.e., the short exact sequence

1 ⟶ Inn(𝔤) ⟶ Aut(𝔤) ⟶ Out(𝔤) ⟶ 1

splits. In the complex simple case, this is a classical result,[3] whereas for real simple Lie algebras, this fact has been proven as recently as 2010.[4]

Word play

The term outer automorphism lends itself to word play: the term outermorphism is sometimes used for outer automorphism, and a particular geometry on which $Out(F n)$ acts is called outer space.

gollark: Lasers are better.

gollark: Ooh, I could have a bot for that.

gollark: You've spent 807KST from your in game wallet in total.

gollark: No, just 285.

gollark: Or is it 2850?

References

A. Lucchini, F. Menegazzo, M. Morigi (2003), "On the existence of a complement for a finite simple group in its automorphism group", Illinois J. Math. 47, 395–418.
ATLAS p. xvi
(Fulton & Harris 1991, Proposition D.40)
JLT20035

External links

ATLAS of Finite Group Representations-V3, contains a lot of information on various classes of finite groups (in particular sporadic simple groups), including the order of $Out(G)$ for each group listed.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.

[1] A. Lucchini, F. Menegazzo, M. Morigi (2003), "On the existence of a complement for a finite simple group in its automorphism group", Illinois J. Math. 47, 395–418.

[2] ATLAS p. xvi

[3] (Fulton & Harris 1991, Proposition D.40)

[JOLT-4] JLT20035