Legion Gold

Legion Gold is a turn-based strategy video game with a historical setting, designed by Slitherine and released in 2002. In Legion Gold, the player attempts to build a powerful army by controlling villages and defeating enemies with the ultimate goal of dominating a region.

Legion Gold
Title screen
Developer(s)Slitherine
Publisher(s)Strategy First
Designer(s)Iain McNeill
Platform(s)PC, iPad
ReleaseJune 6, 2002
Genre(s)Turn-based strategy
Mode(s)Single player

Gameplay

Legion Gold is a turn-based single-player wargame. The strategy of battle involves fighting on favorable terrain with enemies weak against the player's units. Other concerns are capturing cities that produce food, stone and wood. Upgrading the cities' buildings leads to the production of stronger units.

Each unit in Legion Gold has its own strengths and weaknesses, different types of attacks (melee and ranged) and weapon.

Victory screen of an alternative campaign in Elysium Field. Note that the game declares the player a victor when domination is achieved, rather than total conquest

Legion takes place in the historic setting of the Roman expansion, from the conquest of Italy, Britain, Hispania, Gaul and Germania.

Campaigns

Legion Gold comes with eight campaign maps (including tutorial), each of which has three difficulty levels and options for historical and non-historical gameplay settings. The maps are generally well-researched and correspond closely to historical geography in the names of tribes and locations of cities.

Development

The development release of Legion Gold was in 2002. An iPad version was released on December 31, 2012.[1]

Reception

Legion Gold got a 6.9 on Gamezone,[2] an 8 on Gamevortex[3] and a 7.5 on the Entertainment Depot,[4] amongst others.

gollark: It's kind of bad.
gollark: ```python#!/bin/env python3chars = [chr(n) for n in range(126)]firstchar = chars[0]lastchar = chars[len(chars) - 1]def increment_char(character): return chr(ord(character) + 1)def old_increment_string(string_to_increment): reversed_string = list(reversed(string_to_increment)) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed(reversed_string)))def increment_string(to_increment): reversed_string = list(to_increment) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed_string))def string_generator(): length = 0 while 1: length += 1 string = chars[0] * length while True: try: string = increment_string(string) except IndexError: # Incrementing has gone out of the char array, move onto next length break yield string```
gollark: Except it enumerates all possible ASCII strings instead.
gollark: I made that!
gollark: no.

References
  1. "Legion coming to the IPad". 2012-10-19. Archived from the original on 2016-03-04. Retrieved 2012-10-19.
  2. "Legion Gold Review". 2003-06-03.
  3. "Legion Gold Review". 2002.
  4. "Legion Gold Review". 2002.
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