Khoroshevo, Alexandrovsky District, Vladimir Oblast
Khoroshevo (Russian: Хорошево) is a rural locality (a village) in Krasnoplamenskoye Rural Settlement, Alexandrovsky District, Vladimir Oblast, Russia. The population was 13 as of 2010.[2] There is 1 street.
Khoroshevo Хорошево | |
|---|---|
Village | |
  Khoroshevo  Khoroshevo | |
| Coordinates: 56°33′N 38°30′E[1] | |
| Country | Russia |
| Region | Vladimir Oblast |
| District | Alexandrovsky District |
| Time zone | UTC+3:00 |
Geography
The village is located 2 km west from Krasnoye Plamya, 29 km north-west from Alexandrov.
gollark: Ah...
gollark: It should be okay with regexes or something non-turing-complete.
gollark: Hold on, I can probably make a much nicer one.
gollark: It's kind of bad.
gollark: ```python#!/bin/env python3chars = [chr(n) for n in range(126)]firstchar = chars[0]lastchar = chars[len(chars) - 1]def increment_char(character): return chr(ord(character) + 1)def old_increment_string(string_to_increment): reversed_string = list(reversed(string_to_increment)) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed(reversed_string)))def increment_string(to_increment): reversed_string = list(to_increment) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed_string))def string_generator(): length = 0 while 1: length += 1 string = chars[0] * length while True: try: string = increment_string(string) except IndexError: # Incrementing has gone out of the char array, move onto next length break yield string```
References
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