Inverse quadratic interpolation

In numerical analysis, inverse quadratic interpolation is a root-finding algorithm, meaning that it is an algorithm for solving equations of the form f(x) = 0. The idea is to use quadratic interpolation to approximate the inverse of f. This algorithm is rarely used on its own, but it is important because it forms part of the popular Brent's method.

The method

The inverse quadratic interpolation algorithm is defined by the recurrence relation

where fk = f(xk). As can be seen from the recurrence relation, this method requires three initial values, x0, x1 and x2.

Explanation of the method

We use the three preceding iterates, xn2, xn1 and xn, with their function values, fn2, fn1 and fn. Applying the Lagrange interpolation formula to do quadratic interpolation on the inverse of f yields

We are looking for a root of f, so we substitute y = f(x) = 0 in the above equation and this results in the above recursion formula.

Behaviour

The asymptotic behaviour is very good: generally, the iterates xn converge fast to the root once they get close. However, performance is often quite poor if the initial values are not close to the actual root. For instance, if by any chance two of the function values fn2, fn1 and fn coincide, the algorithm fails completely. Thus, inverse quadratic interpolation is seldom used as a stand-alone algorithm.

The order of this convergence is approximately 1.84 as can be proved by Secant Method analysis.

Comparison with other root-finding methods

As noted in the introduction, inverse quadratic interpolation is used in Brent's method.

Inverse quadratic interpolation is also closely related to some other root-finding methods. Using linear interpolation instead of quadratic interpolation gives the secant method. Interpolating f instead of the inverse of f gives Muller's method.

gollark: The solution is obvious. Build a computer with more RAM so you can make more number.
gollark: Radeon 7s have been discontinued, I think.
gollark: Not *everyone* streams and has a large amount of money for it.
gollark: And "best performance out of everything" only matters if you're just happy to throw away money for the absolute highest-end available.
gollark: Better performance *per unit of money* though? Generally no.

See also

References

  • James F. Epperson, An introduction to numerical methods and analysis, pages 182-185, Wiley-Interscience, 2007. ISBN 978-0-470-04963-1
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.