Alexander Gordon (journalist)

Alexander Garrievich Gordon (Russian: Алeксандp Гаppиeвич Гордон, born February 20, 1964) is a Russian radio and television presenter, journalist, actor and director, of Russian Jewish descent. Head of the Moscow Institute Workshop of journalism TV and Radio "Ostankino" (Mitra), a lecturer in a Makgaffina Film School. Five-time winner TEFI (2007, twice in 2008, 2010, 2011). His surname is pronounced with stress on the last syllable, i.e. rhyming with "anon", unlike the regular pronunciation of "Gordon" rhyming with "colon".

Alexander Gordon
2011
BornAlexander Garrievich Gordon
(1964-02-20) February 20, 1964
Obninsk, Soviet Union
Occupationradio and TV presenter, journalist, actor, director
NationalityRussian
CitizenshipRussia, United States
Notable awardsTEFI (2007, 2008 — twice, 2010, 2011)

According to the results of many surveys of TV viewers Gordon repeatedly is recognized as one of the best contemporary Russian TV people.[1] Founder and permanent moderator of the "Gordon", "private screening", "Gordon Quixote", "Citizen Gordon" shows. He has worked on "NTV" channel and "Channel One". In addition to a successful television career, Alexander Gordon tried himself and as a film-maker, creating several full-length feature films. Two of his movies, The Shepherd of His Cows and Brothel Lights, were based on the works of his father Harry. He is a son of the poet and artist from Odessa Harry Gordon and Antonina Striga.

Honors and awards

  • 2007 - TEFI for the "Talk Show" (program "Private screening").[2]
  • 2008 - TEFI for the categories "Talk Show" and "talk-show" (the program "private screening").[2]
  • 2010 - TEFI for the "Talk show host" (the program "Gordon Quixote").[3]
  • 2011 - TEFI for the "Talk show host" (the program "private screening").

Filmography

Director

  • 2002 - "The shepherd of his cows" (based on the book by Harry Gordon)
  • 2009 - "Liberal Democratic Party. 20 years of face-to-Russia"
  • 2010 - "Blizzard"[4]
  • 2011 - "Brothel Lights"
gollark: Differentiate it, substitute x=3 into that, set dy/dx to 0, solve.
gollark: Oh, actually just > 0 since it's a denominator, yes.
gollark: The $9-x^2$ bit has to have a value >= 0. So solve that and work out for which values it is >= 0.
gollark: You want the bit in the square root to be greater than or equal to 0, so just figure out what values of x give you that.
gollark: I see.

References

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