Additive identity

In mathematics the additive identity of a set that is equipped with the operation of addition is an element which, when added to any element x in the set, yields x. One of the most familiar additive identities is the number 0 from elementary mathematics, but additive identities occur in other mathematical structures where addition is defined, such as in groups and rings.

Elementary examples

Formal definition

Let N be a set that is closed under the operation of addition, denoted +. An additive identity for N is any element e such that for any element n in N,

e + n = n = n + e

Example: The formula is n + 0 = n = 0 + n.

Further examples

  • In a group, the additive identity is the identity element of the group, is often denoted 0, and is unique (see below for proof).
  • A ring or field is a group under the operation of addition and thus these also have a unique additive identity 0. This is defined to be different from the multiplicative identity 1 if the ring (or field) has more than one element. If the additive identity and the multiplicative identity are the same, then the ring is trivial (proved below).
  • In the ring Mm×n(R) of m by n matrices over a ring R, the additive identity is denoted 0 and is the m by n matrix whose entries consist entirely of the identity element 0 in R. For example, in the 2 by 2 matrices over the integers M2(Z) the additive identity is
  • In the quaternions, 0 is the additive identity.
  • In the ring of functions from R to R, the function mapping every number to 0 is the additive identity.
  • In the additive group of vectors in Rn, the origin or zero vector is the additive identity.

Properties

The additive identity is unique in a group

Let (G, +) be a group and let 0 and 0' in G both denote additive identities, so for any g in G,

0 + g = g = g + 0 and 0' + g = g = g + 0'

It follows from the above that

0' = 0' + 0 = 0' + 0 = 0

The additive identity annihilates ring elements

In a system with a multiplication operation that distributes over addition, the additive identity is a multiplicative absorbing element, meaning that for any s in S, s · 0 = 0. This can be seen because:

The additive and multiplicative identities are different in a non-trivial ring

Let R be a ring and suppose that the additive identity 0 and the multiplicative identity 1 are equal, or 0 = 1. Let r be any element of R. Then

r = r × 1 = r × 0 = 0

proving that R is trivial, that is, R = {0}. The contrapositive, that if R is non-trivial then 0 is not equal to 1, is therefore shown.

gollark: Well, you decided it was acceptable to ban people for apparently *causing* incivility, so I guess we can... ban lyric and rwd0c?
gollark: No, he's just ignoring the rules and banning people for no valid reason.
gollark: You are arbitrarily punishing people. *This is why people don't like you.*Also, this deleted the message history.
gollark: ++delete <@!309787486278909952>
gollark: What? Seriously? That is a ridiculous application of the rules.

See also

References

  • David S. Dummit, Richard M. Foote, Abstract Algebra, Wiley (3rd ed.): 2003, ISBN 0-471-43334-9.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.