Acria
Acria is a moth genus of the superfamily Gelechioidea. It is placed in the family Depressariidae, which is often – particularly in older treatments – considered a subfamily of Oecophoridae or included in the Elachistidae.
Acria | |
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Scientific classification | |
Kingdom: | Animalia |
Phylum: | Arthropoda |
Class: | Insecta |
Order: | Lepidoptera |
Family: | Depressariidae |
Subfamily: | Acriinae |
Genus: | Acria Stephens, 1834 |
Type species | |
Phalaena emarginella Donovan, 1806 | |
Synonyms | |
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Species
- Acria amphorodes (Meyrick, 1923) (India)
- Acria ceramitis Meyrick, 1908 (China, India, Korea, Japan)
- Acria cocophaga Chen & Wu, 2011
- Acria emarginella (Donovan, 1804) (China, India, Japan, Sri Lanka)
- Acria equibicruris Wang, 2008 (China)
- Acria eulectra Meyrick, 1908 (India)
- Acria gossypiella (Shiraki, 1913)
- Acria javanica Lvovsky, 2015
- Acria malacolectra Meyrick, 1930
- Acria meyricki Shashank, 2014 (India)
- Acria nivalis Wang & Li, 2000 (China)
- Acria obtusella (Walker, 1864) (Borneo, Sri Lanka)
- Acria ornithorrhyncha Wang, 2008 (China)
- Acria psamatholeuca Meyrick, 1930
- Acria sciogramma Meyrick, 1915 (New Guinea)
- Acria sulawesica Lvovsky, 2015
- Acria xanthosaris Meyrick, 1908 (India)
gollark: Although I don't know why you can't long-divide it, p and q are just constants for the purposes of that.
gollark: That lets you work out a/b/c/d, which you can substitute back into (x-1)(ax^3+bx^2+cx+d).
gollark: So:2 = a (x^4 terms)p = b - a (x^3 terms)-6 = c - b (x^2 terms)q = d - c (x terms)6 = -d (constant terms)
gollark: So you can do `2x^4+ px^3 - 6x^2 + qx + 6 = ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d`, and you know the coefficients on x^4 and so on should be equal.
gollark: Which you can then simplify to ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d.
References
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