2019 Little Rock Challenger – Doubles
Matías Franco Descotte and Orlando Luz won the title after defeating Treat Huey and Max Schnur 7–5, 1–6, [12–10] in the final.
Doubles | |
---|---|
2019 Little Rock Challenger | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 7–5, 1–6, [12–10] |
This was the first edition of the tournament.[1]
Seeds
Roberto Maytín / Jackson Withrow (Quarterfinals) Luis David Martínez / Roberto Quiroz (Quarterfinals) Harri Heliövaara / Alex Lawson (First round) Arjun Kadhe / Volodymyr Uzhylovskyi (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
PR | ![]() ![]() | 3 | 4 | 1 | ![]() ![]() | 4 | 79 | [15] | |||||||||||||||||||
WC | ![]() ![]() | 6 | 6 | WC | ![]() ![]() | 6 | 67 | [17] | |||||||||||||||||||
![]() ![]() | 1 | 1 | WC | ![]() ![]() | 3 | 6 | [10] | ||||||||||||||||||||
4 | ![]() ![]() | 2 | 5 | ![]() ![]() | 6 | 3 | [5] | ||||||||||||||||||||
PR | ![]() ![]() | 6 | 7 | PR | ![]() ![]() | 1 | 2 | ||||||||||||||||||||
![]() ![]() | 4 | 3 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||
![]() ![]() | 6 | 6 | WC | ![]() ![]() | 5 | 6 | [10] | ||||||||||||||||||||
WC | ![]() ![]() | 77 | 77 | ITF | ![]() ![]() | 7 | 1 | [12] | |||||||||||||||||||
WC | ![]() ![]() | 63 | 63 | WC | ![]() ![]() | 7 | 4 | [2] | |||||||||||||||||||
![]() ![]() | 6 | 77 | ![]() ![]() | 5 | 6 | [10] | |||||||||||||||||||||
3 | ![]() ![]() | 4 | 64 | ![]() ![]() | 6 | 66 | [10] | ||||||||||||||||||||
![]() ![]() | 3 | 64 | ITF | ![]() ![]() | 0 | 78 | [12] | ||||||||||||||||||||
ITF | ![]() ![]() | 6 | 77 | ITF | ![]() ![]() | 7 | 6 | ||||||||||||||||||||
ITF | ![]() ![]() | 6 | 4 | [8] | 2 | ![]() ![]() | 5 | 3 | |||||||||||||||||||
2 | ![]() ![]() | 2 | 6 | [10] |
gollark: However, you must generate integers for the output format.
gollark: I see.
gollark: Which still involves dealing with integers slightly.
gollark: Well, you have to deal with the integers from the input, and output integers.
gollark: I can tell you that my entry:- will be submitted- will be written in C or Python- will contain integers for at least the I/O part- will multiply square n * n matrices- will run in either less than, more than or equal to O(n²²¹¹³¹³¹³⁴) time and O((log n)⁶) space- may or may not invoke certain dark bee gods- will be compatible with Linux and potentially other OSes- could contain instances of SCP-3443- will be between (inclusive) 0KB and 20KB (main code file)- may utilize electromagnetic, logical or philosophical induction
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.