2019 Lale Cup – Doubles

Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Doubles
2019 Lale Cup
Champions	Marie Bouzková Rosalie van der Hoek
Runners-up	Ilona Kremen Iryna Shymanovich
Final score	7–5, 6–7^(2–7), [10–5]

Main article: 2019 Lale Cup

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7^(2–7), [10–5].[1]

Seeds

1. Olga Doroshina / Polina Monova (First round, withdrew)
2. Raluca Șerban / Isabella Shinikova (Semifinals)
3. Berfu Cengiz / Jessy Rompies (Semifinals)
4. Valentini Grammatikopoulou / Ankita Raina (First round)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	O Doroshina P Monova
		Ç Büyükakçay A Vrljić	w/o						Ç Büyükakçay A Vrljić
		G Poznikhirenko S Sharipova	7	4	[8]				M Bouzková R van der Hoek	w/o
		M Bouzková R van der Hoek	5	6	[10]											M Bouzková R van der Hoek	7	7
	3	B Cengiz J Rompies	6	6											3	B Cengiz J Rompies	5	5
	WC	Z Erman Z Sönmez	3	4				3	B Cengiz J Rompies	1	6	[11]
		İ Soylu B Štefková	6	6					İ Soylu B Štefková	6	4	[9]
	WC	İ Öz M Sezer	3	3																			M Bouzková R van der Hoek	7	6^2	[10]
		I Kremen I Shymanovich	6	6																			I Kremen I Shymanovich	5	7^7	[5]
		Á Bukta V Juhászová	2	3					I Kremen I Shymanovich	4	6	[11]
		G Minnen P Özgen	7	6					G Minnen P Özgen	6	3	[9]
	4	V Grammatikopoulou A Raina	5	4												I Kremen I Shymanovich	6^6	6	[11]
		A Gasanova J Terziyska	6	7^7											2	R Șerban I Shinikova	7^8	3	[9]
		F Al-Nabhani C Anıl	1	6^3					A Gasanova J Terziyska	6	6^2	[7]
	WC	L Aiche BE Gümüşsoy	0	0				2	R Șerban I Shinikova	4	7^7	[10]
	2	R Șerban I Shinikova	6	6

References

• Main Draw

1. "W60 Istanbul". www.itftennis.com.