2016 Reinert Open – Singles

Carina Witthöft was the defending champion, but chose not to participate.

Singles
2016 Reinert Open
Champion Antonia Lottner
Runner-up Tereza Smitková
Final score3–6, 7–5, 6–3

Antonia Lottner won the title, defeating Tereza Smitková in the final, 3–6, 7–5, 6–3.

Seeds

  1. Anna Karolína Schmiedlová (Second round)
  2. Sorana Cîrstea (Semifinals)
  3. Irina Khromacheva (Quarterfinals)
  4. Richèl Hogenkamp (First round)
  5. Alizé Lim (First round)
  6. İpek Soylu (Quarterfinals)
  7. Isabella Shinikova (Second round)
  8. Lesley Kerkhove (Quarterfinals)

Main draw

Key

Finals

Semifinals Final
          
  Karolína Muchová 5 1
  Tereza Smitková 7 6
  Tereza Smitková 6 5 3
  Antonia Lottner 3 7 6
  Antonia Lottner 1 7 6
2/WC Sorana Cîrstea 6 5 3

Top half

First round Second round Quarterfinals Semifinals
1 AK Schmiedlová 2 6 6
  A Rus 6 3 3 1 AK Schmiedlová 6 5 4
  N Stojanović 6 6 N Stojanović 1 7 6
  P Özgen 4 3 N Stojanović 3 1
Q J Terziyska 4 5 K Muchová 6 6
  N Dzalamidze 6 7 N Dzalamidze 77 3 0
  K Muchová 7 6 K Muchová 63 6 6
5 A Lim 5 4 K Muchová 5 1
3 I Khromacheva 6 6 T Smitková 7 6
  M Melnikova 3 2 3 I Khromacheva 3 6 7
  V Strakhova 6 6 V Strakhova 6 1 5
WC K Gerlach 4 3 3 I Khromacheva 4 2
  T Smitková 6 6 T Smitková 6 6
  A Raina 3 3 T Smitková 6 6
  J Lu 3 4 7 I Shinikova 3 4
7 I Shinikova 6 6

Bottom half

First round Second round Quarterfinals Semifinals
6 İ Soylu 7 6
Q L Schaeder 5 4 6 İ Soylu 6 6
  D Khazaniuk 4 2 Q Y Morderger 2 1
Q Y Morderger 6 6 6 İ Soylu 6 4 3
  A Lottner 6 6 A Lottner 4 6 6
  A Vrljić 2 0 A Lottner 78 6
WC J Wachaczyk 6 3 6 WC J Wachaczyk 66 2
4 R Hogenkamp 1 6 4 A Lottner 1 7 6
8 L Kerkhove 2 6 77 2/WC S Cîrstea 6 5 3
  A Schäfer 6 3 65 8 L Kerkhove 6 77
LL A Klasen 2 1 V Ivakhnenko 3 63
  V Ivakhnenko 6 6 8 L Kerkhove 66 3
WC K Hobgarski 3 5 2/WC S Cîrstea 78 6
  N Podoroska 6 7 N Podoroska 2 6 5
Q A Gámiz 2 64 2/WC S Cîrstea 6 1 7
2/WC S Cîrstea 6 77
gollark: I bet your proof relied on ridiculous axioms like the "law of the excluded middle" and "peano arithmetic".
gollark: I even had a truth cuboid validate it.
gollark: I checked, though.
gollark: GTech™ intellectual cuboids, which are insentient because yes, can do those, though.
gollark: But what if nonsentient "apio beeoids" try and access their account?

References

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