2013 Poznań Open – Singles

Jerzy Janowicz was the defending champion, but he did not participate that year.[1]
Andreas Haider-Maurer won the title, defeating Damir Džumhur in the final, 4–6, 6–1, 7–5.

Singles
2013 Poznań Open
Champion Andreas Haider-Maurer
Runner-up Damir Džumhur
Final score4–6, 6–1, 7–5
Main article: 2013 Poznań Open

Seeds
  1. Andreas Haider-Maurer (Champion)
  2. Guillaume Rufin (First Round)
  3. João Sousa (Quarterfinals)
  4. Pablo Carreño Busta (Semifinals)
  5. Stéphane Robert (Semifinals)
  6. Jesse Huta Galung (First Round)
  7. Simon Greul (Second Round)
  8. Peter Gojowczyk (Second Round)

Draw

Key

Finals
Semifinals Final
          
1 Andreas Haider-Maurer 6 6
4 Palbo Carreño Busta 2 2
1 Andreas Haider-Maurer 4 6 7
  Damir Džumhur 6 1 5
5 Stéphane Robert 77 61 3
  Damir Džumhur 63 77 6

Top half
First Round Second Round Quarterfinals Semifinals
1 A Haider-Maurer 6 6
  A Veić 3 3 1 A Haider-Maurer 6 6
Q T Monteiro 5 6 6 Q T Monteiro 2 3
WC Piotr Gadomski 7 4 3 1 A Haider-Maurer 6 5 77
WC K Majchrzak 4 6 2   H Laaksonen 3 7 62
  H Laaksonen 6 2 6   H Laaksonen 6 77
  L Kirche 4 4 7 S Greul 1 64
7 S Greul 6 6 1 A Haider-Maurer 6 6
4 P Carreño Busta 2 6 6 4 P Carreño Busta 2 2
Q F Krajinović 6 4 4 4 P Carreño Busta 7 6
  G Clezar 7 6   G Clezar 5 1
  N Gomboš 5 4 4 P Carreño Busta 3 6 77
Q A Kapaś 3 7 68   R Carballés Baena 6 0 65
  J Eysseric 6 5 710   J Eysseric 4 3
  R Carballés Baena 6 6   R Carballés Baena 6 6
6 J Huta Galung 4 1

Bottom Half
First Round Second Round Quarterfinals Semifinals
5 S Robert 6 77
  J Kovalík 1 62 5 S Robert 77 77
  J Mertl 6 7   J Mertl 64 61
WC Wojciech Lutkowski 2 5 5 S Robert 64 6 6
PR A Beck 4 65 3 J Sousa 77 2 4
  B Westerhof 6 77   B Westerhof 3 1
  R Albot 1 2 3 J Sousa 6 6
3 J Sousa 6 6 5 S Robert 77 61 3
8 P Gojowczyk 6 6   D Džumhur 63 77 6
Q D Smethurst 4 2 8 P Gojowczyk 3 7 3
WC G Panfil 6 6 WC G Panfil 6 5 6
  G Melzer 2 1 WC G Panfil 4 4
  B Phau 6 6   D Džumhur 6 6
  N Renavand 2 4   B Phau 2 1
  D Džumhur 77 6   D Džumhur 6 6
2 G Rufin 65 3
gollark: I totally would.
gollark: join flattens a nested monad thing into an unnested one.
gollark: bind/>>= is essentially just map and join.
gollark: Unironically, they're the principled™ functional™ way the Haskell people came up with to sequence side effects and state on top of lazy evaluation.
gollark: They're just monoids in the category of endofunctors, what's the problem?

References
  1. "Gemeldete Spieler". Archived from the original on 2013-06-17. Retrieved 2013-06-19.
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