2013 Open Harmonie mutuelle – Singles

Grégoire Burquier was the defending champion but decided not to participate.
Jesse Huta Galung won the final 7–6(7–4), 4–6, 7–6(7–3) against Kenny de Schepper.

Singles
2013 Open Harmonie mutuelle
Champion Jesse Huta Galung
Runner-up Kenny de Schepper
Final score7–6(7–4), 4–6, 7–6(7–3)
Main article: 2013 Open Harmonie mutuelle

Seeds
  1. Kenny de Schepper (Final)
  2. Andreas Haider-Maurer (Second Round)
  3. Marc Gicquel (First Round)
  4. Josselin Ouanna (First Round)
  5. Dustin Brown (Second Round)
  6. Nicolas Mahut (First Round)
  7. Boris Pašanski (First Round)
  8. Michał Przysiężny (First Round)

Draw

Key

Finals
Semifinals Final
          
1 Kenny de Schepper 77 6  
Q Martin Fischer 64 3  
1 Kenny de Schepper 64 6 63
  Jesse Huta Galung 77 4 77
  Jesse Huta Galung 6 7  
  Jan Mertl 4 5  

Top Half
First Round Second Round Quarterfinals Semifinals
1 K de Schepper 6 6  
WC R Jouan 2 2   1 K de Schepper 7 6  
  D Meffert 6 6     D Meffert 5 3  
  I Navarro 1 3   1 K de Schepper 4 6 6
WC F Martin 6 6     O Nedovyesov 6 3 3
Q D Petrović 3 2   WC F Martin 4 0  
  O Nedovyesov 6 6     O Nedovyesov 6 6  
7 B Pašanski 2 1   1 K de Schepper 77 6  
4 J Ouanna 62 2   Q M Fischer 64 3  
  D Guez 77 6     D Guez 6 6  
  B Westerhof 65 6 1   K Kravchuk 2 3  
  K Kravchuk 77 4 6   D Guez 6 3 4
  A Brugués-Davi 6 6   Q M Fischer 4 6 6
  M Middelkoop 2 4     A Brugués-Davi 1 0  
Q M Fischer 6 77   Q M Fischer 6 6  
6 N Mahut 4 63  

Bottom Half
First Round Second Round Quarterfinals Semifinals
5 D Brown 6 4 6
  N Desein 4 6 4 5 D Brown 4 3  
WC M Rodrigues 64 2     S Robert 6 6  
  S Robert 77 6     S Robert 2 64  
WC C Lestienne 2 2     J Huta Galung 6 77  
  M Bašić 6 6     M Bašić 65 65  
  J Huta Galung 7 78     J Huta Galung 77 77  
3 M Gicquel 5 66     J Huta Galung 6 7  
8 M Przysiężny 3 4     J Mertl 4 5  
  V Millot 6 6     V Millot 0r    
Q H Nys 4 1     J Mertl 3    
  J Mertl 6 6     J Mertl 4 6 6
  N Renavand 6 6     N Renavand 6 4 4
  V Crivoi 1 4     N Renavand 77 6  
Q A Bossel 4 3   2 A Haider-Maurer 61 3  
2 A Haider-Maurer 6 6  
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gollark: I'd probably try and do it based on grammatical nesting level and commonness of words.
gollark: ddg! Analytic vs infinitely differentiable

References
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