1860 United States presidential election in Georgia

The 1860 United States presidential election in Georgia took place on November 6, 1860, as part of the 1860 United States presidential election. Georgia voters chose 10 representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1860 United States presidential election

1860 United States presidential election in Georgia

November 6, 1860

Nominee John C. Breckinridge John Bell Stephen A. Douglas Party Southern Democratic Constitutional Union Democratic Home state Kentucky Tennessee Illinois Running mate Joseph Lane Edward Everett Herschel V. Johnson Electoral vote 10 0 0 Popular vote 52,176 42,960 11,581 Percentage 48.89% 40.26% 10.85%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

Georgia was won by the 14th Vice President of the United States John Breckenridge (SD–Kentucky), running with Senator Joseph Lane, with 48.89% of the popular vote, against Senator John Bell (CU–Tennessee), running with the Governor of Massachusetts Edward Everett, with 40.26% of the popular vote and Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 10.85% of the popular vote.

Republican Party candidate Abraham Lincoln was not on the ballot in the state. This was the last time until 1964 that Georgia did not vote for the national Democratic Party.

Results

1860 United States presidential election in Georgia[1]

Party		Candidate	Votes	%
	Southern Democratic	John C. Breckinridge	52,176	48.89%
	Constitutional Union	John Bell	42,960	40.26%
	Democratic	Stephen A. Douglas	11,581	10.85%
Total votes			106,717	100%

References

1. "1860 Presidential Election Results Georgia".