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I have a DELL PRECISION M4400 running Windows 7 Professional.
Recently, the laptop started freezing and would go to sleep and would not be able to wake up unless a hard reset was given.
I downloaded and ran the DELL diagnostics from the DELL website which indicated a HDD failure. It was recommended to replace the HDD. I got the following (truncated) report (SMART) for the 320GB HDD.
WDC WD3200BEKT-75PVMT0-WD-WXL1A91U2336-TEST.mht HDDScan Drive Test Report Model: WDC WD3200BEKT-75PVMT0 Firmware: 01.01A01 Serial: WD-WXL1A91U2336 LBA: 625142448 Report By: HDDScan for Windows version 3.3 Report Date: 8/21/2015 1:08:33 AM Open Disk Test : RD-Read Executing Block start at 2428416 time 55ms . . Block start at 14633472 time 51ms Bad block found, start LBA : 19194880 Block start at 26177024 time 261ms . . Block start at 41292800 time 58ms Bad block found, start LBA : 46550528 Block start at 46551296 time 73ms Block start at 46551552 time 74ms Block start at 46554624 time 64ms Bad block found, start LBA : 46574592 Bad block found, start LBA : 46576384 Block start at 46576640 time 100ms . Block start at 46577920 time 112ms Bad block found, start LBA : 46578432 Bad block found, start LBA : 46582272 Block start at 46582528 time 273ms Block start at 46583040 time 64ms Bad block found, start LBA : 46586624 Block start at 46590720 time 84ms . . Block start at 46671104 time 59ms Bad block found, start LBA : 46672128 Bad block found, start LBA : 46675968 Block start at 46676224 time 154ms . . Block start at 618832128 time 107ms
From the report I understand that, only a portion of the hard drive has bad sectors only from the beginning (Bad block found, start LBA : 46675968 is the last one)
I'm planning to allocate till this as un-partitioned space and not use it. The question is how many GB's should I make as un-partitioned space so that I can continue to use my laptop.
I tried researching the internet for the meaning of LBA and its co-relation to hard drive size - all in vain. The Wiki page on LBA is of very little use in this context.
(Note: I do not mind losing data in case if the HDD fails suddenly. Just want to make the maximum out of this HDD)
Edit
From here, I understand that this formula which converts LBA to GB:
(LBA*512) / (1024^3)
By this formula: 46675968 / (1024^3) = 22.25GB - which I'd roundup as 25GB
Would this be correct?
All I'm looking for a is a *LBA Vs GB* table - so that I can cancel out so many inital GB's and use the rest of the HDD – Prasanna – 2015-08-30T18:25:33.280
1The thing about bad blocks, they continue to happen, based on the fact you have performance issues you really should just replace the drive. Based on the bad block positions, you would have to lose 90% of your drive... – Ramhound – 2015-08-30T18:30:25.097
@Ramhound: Please see the edit. I found this formula from some site. Is that even correct? I'm getting 295GB as the answer when I apply the same formula to my last LBA #. I'm willing to trade even 50GB to keep the HDD (300-50=250GB - which is pretty good) – Prasanna – 2015-08-30T18:39:24.407
Think of the disk as an old record player; the arm that holds the heads does swing over the surfaces (often two sides even for a single platter). The swing is likely to be over the entire surface even if your partition is at one end - the surface may be broken or worn, and the arm moving over it will affect that portion - no matter what you do. The drive is going to fail eventually, and that might be quite a bit sooner than you think. – Hannu – 2015-08-30T20:54:08.560