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I've read that AES can work with three key sizes: 128 bits, 192 bits and 256 bits.
I'm trying to set up a LUKS partition with CryptSetup, using “aes-xts-plain64” cipher.
Why can I create keys of any length with CryptSetup, except for the fact they have to be a multiple of 8?
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This question appears to be off-topic because it is not about cryptography as defined in our help-center. “If your question is about usage of a specific cryptographic software (not its cryptographic internals), Super User is the right site.”. I have flagged the question for moderator attention with an according migration request. (So, please don’t cross-post your question; it will be moved accordingly by a mod if applicable.)
– e-sushi – 2014-08-06T15:05:10.857man cryptsetup (LUKS uses PBKDF2) – otus – 2014-08-06T15:13:41.233
And if you have any questions related to what’s explained in the man-pages that @otus pointed you to, you might want to take a look at the “CryptSetup FAQs”…
– e-sushi – 2014-08-06T15:20:50.547