Solaris 11.1 x86 installing Weblogic 12.11

Question

Ive been looking everywhere for a way to install Weblogic on Solaris. According to Oracle's documentation, all you need to install Weblogic Graphical Mode is

• Login on Unix
• Go to the directory that contains the installation program.

• Launch the installation by entering the following command:

  -chmod a+x file_name.bin ./file_name.bin
  

So, this are my file attributes

-rwxr-xr-x   1 dbncourt staff    850362368 Jul 22 23:29 wls1211_linux32.bin

So i go and type:

chmod a+x wls1211_linux32.bin ./wls1211_linux32.bin

and absolutely nothing happens, and it says in the oracle's documentation that the window should appear. Then i go and try to open it in console mode since it said that if your console doesnt support "i dont remember what" the window wont show.

chmod a+x wls1211_linux32.bin ./wls1211_linux32.bin -mode=console

according to the documentation, that should do it. And i get this error

chmod: WARNING: can't access --
chmod: WARNING: can't access -mode=console

I know this is maybe a stupid question, but ive been trying for a while now with no result. Is my very first time working with Solaris and Weblogic.

What im i doing wrong?¿ Im i lacking some package? is it the wrong wls to install?

BTW: I downloaded this wls because there was 3 options, Linux (.bin), Windows (.exe) and MacOs (.jar). And according to the documentation, to install on Unix platform using Graphical Mode, i need the .bin file.

Also im not runing root because they say you should not.

Srry for my English btw^^

Answer 1

Those are separate commands you need to enter separately:

chmod a+x file_name.bin
./file_name.bin

The first changes the permission on file_name.bin to make it executable, the second runs that program. Entering them as one command just causes the file permissions to be changed twice as both file_name.bin and ./file_name.bin would be used as arguments to the chmod command.