-1
I want to find the particular file name in particular directory in ruby.
I tried the following Dir.glob()
file = Dir.glob("/home/prakash/Desktop/*.uploaded")
output:
/home/prakash/Desktop/abc.uploaded
But I just want only the file name in output. I don't want file name with fully path.
So how can I do this?
Prakash V Holkar
Posted 2014-04-29T07:07:55.320
Reputation: 119
0
In Ruby, there is a file class.
File.basename("/home/prakash/Desktop/abc.uploaded")
The above will return abc.uploaded
Since I'm not sure if you want the extention or not, you can remove it using
File.basename("/home/prakash/Desktop/abc.uploaded", ".uploaded")
The above will return abc
Or you could perform a string manipulation
'/home/prakash/Desktop/abc.uploaded'.split('\\').last
Dave
Posted 2014-04-29T07:07:55.320
Reputation: 24 199
Actually I don't know the file name on particular directory, I just know the extension of that file i.e. .uploaded, by using this extension i want to find the file name only without full path in prefix – Prakash V Holkar – 2014-04-29T07:38:51.457
So, the name abc could be anything? If so, the code above will work! – Dave – 2014-04-29T07:40:25.577
yes name abc could be anything. In you code you have given the fully path upto fine name to "File.basename()" class. But i don't know the file name, I know only the file extension then how can i do? – Prakash V Holkar – 2014-04-29T07:44:58.667
I'm sorry, I'm still a little lost - why don't you know the file name? If Dir.glob(... is returning the full path, then you do know it? – Dave – 2014-04-29T07:47:24.257
0
I got easy way to find only file name without full path:
file = Dir.glob("/file/path/*.uploaded").join(" ")
filename = file.split('/').last
And it's working great for me
Prakash V Holkar
Posted 2014-04-29T07:07:55.320
Reputation: 119
@ Dave Rook - abc.uploaded is the file name – Prakash V Holkar – 2014-04-29T07:20:04.077