0
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If I run this command,
# nmap -sP 192.168.0.120/25
which IP addresses are scanned?
How can I calculate the IP addresses that are in this range? I've been searching Google but I couldn't find something helpful.
ina
Posted 2013-11-11T21:34:00.820
Reputation: 1
4
There is a useful utility, in Linux, called ipcalc. If it is not installed by default, you may download it from your distro's repositories. In Mac OS, you can find the same utility here, while for Windows you find it here (careful with dependencies, it requires Microsoft .Network Framework 2.0).
Its output is like this, exactly for your case:
ipcalc 192.168.0.120/25
Address: 192.168.0.120 11000000.10101000.00000000.0 1111000
Netmask: 255.255.255.128 = 25 11111111.11111111.11111111.1 0000000
Wildcard: 0.0.0.127 00000000.00000000.00000000.0 1111111
=>
Network: 192.168.0.0/25 11000000.10101000.00000000.0 0000000
HostMin: 192.168.0.1 11000000.10101000.00000000.0 0000001
HostMax: 192.168.0.126 11000000.10101000.00000000.0 1111110
Broadcast: 192.168.0.127 11000000.10101000.00000000.0 1111111
Hosts/Net: 126 Class C, Private Internet
MariusMatutiae
Posted 2013-11-11T21:34:00.820
Reputation: 41 321
0
Enter "25" in the "Mask Bits" field and it will show all the details for the network: http://www.subnet-calculator.com/cidr.php
Jim G.
Posted 2013-11-11T21:34:00.820
Reputation: 2 794
Does this mean that the ip addresses scanned are from 192.168.0.1-- 192.168.0.126? Or from .120-.126? I am a little bit confused... – ina – 2013-11-11T21:47:16.383
1Note that you can simply use
nmapto answer this question by runningnmap -n -sL 192.168.0.120/25. The first valid host address is 192.168.0.1; the ".0" address for a network is not a valid host address. – larsks – 2013-11-11T21:48:37.667