The only way to do this is with a Macro:
Public Sub ReplaceHyperlinkURL(FindString As String, ReplaceString As String)
Dim LinkURL, PreStr, PostStr, NewURL As String
Dim FindPos, ReplaceLen, URLLen As Integer
Dim MyDoc As Worksheet
Dim MyCell As Range
On Error GoTo ErrHandler
Set MyDoc = ActiveSheet
For Each MyCell In MyDoc.UsedRange
If MyCell.Hyperlinks.Count > 0 Then
LinkURL = MyCell(1).Hyperlinks(1).Address
FindPos = InStr(1, LinkURL, FindString)
If FindPos > 0 Then 'If FindString is found
ReplaceLen = Len(FindString)
URLLen = Len(LinkURL)
PreStr = Mid(LinkURL, 1, FindPos - 1)
PostStr = Mid(LinkURL, FindPos + ReplaceLen, URLLen)
NewURL = PreStr & ReplaceString & PostStr
MyCell(1).Hyperlinks(1).Address = NewURL 'Change the URL
End If
End If
Next MyCell
Exit Sub
ErrHandler:
MsgBox ("ReplaceHyperlinkURL error")
End Sub
The ReplaceHyperlinkURL code must be placed in a VBA code module. From a spreadsheet, Press Alt+F11 to open the VBA Editor. Then select Insert - Module from the menu. Copy the code and paste it into the module. Then save the module.
In order to run the procedure, create a macro that contains following line and run the macro in Excel. Be sure to replace the FindText with the portion of the address you want to find and ReplaceText with the text you want to replace it with.
Call ReplaceHyperlinkURL("FindText", "ReplaceText")
Source
I'm in stuck the macro part. I don't know how to create the macro and run it. How can do this? – Karolinger – 2013-10-11T05:22:57.367
1
@Karolinger Create or delete a macro - Microsoft Office Support
– Moses – 2013-10-11T05:25:23.630Holy Moses, @Moses. You saved my life! Thank you very much, man! – Karolinger – 2013-10-11T05:38:47.817
1@Karolinger Glad I could help :) – Moses – 2013-10-11T05:43:00.490