The swapping apparently happened when the inactive RAM pages were actually active.
(Update: as it was clarified in a comment, this is not your case. So people with the same problem can skip forward to the horizontal rule.)
I.e. you had many programs running and the kernel swapped-out some pages. Then you quitted some programs. The kernel marks their RAM pages as inactive. But it won't swap-in pages back to RAM until these pages are needed. This results in having both inactive and swapped-out pages.
Why not preemptively swapping-in pages? Because that would be betting against the odds: in the long-run you lose. Let's think of a simplified example: Two programs A and B that don't fit in RAM at the same time. Program A is still running and all the swapped-out pages belong to A. Program B has quitted and all the inactive pages belong to B.
If kernel preemptively swaps-in A's pages and imediately after:
- program A needs to access it's pages -> You win - the pages are already in the RAM.
- you launch B again -> You lose - you "paid" the cost for bringing the pages to RAM and now you have to send them back.
- you launch another program C -> You lose if A and C don't fit in the RAM at the same time. If they fit, you are even.
Also take into account that swapping-out (writing to disk) is more expensive than swapping-in (reading from disk). Which makes this "bet" even more unatractive.
In short: trust your kernel and don't try to outsmart it.
Update:
Turns out that inactive memory doesn't work as the Using Activity Monitor to read System Memory article has led many people to believe it works. The definition given in the article for inactive memory is correct:
This information is in RAM but it is not actively being used, it was
recently used.
But the following example is totally misleading and over-simplified (like my example to be frank):
For example, if you've been using Mail and then quit it, the RAM that
Mail was using is marked as Inactive memory. Inactive memory is
available for use by another application, just like Free memory.
However, if you open Mail before its Inactive memory is used by a
different application, Mail will open quicker because its Inactive
memory is converted to Active memory, instead of loading it from the
slower drive.
I searched for more online resources and ended up to this thread in the darwin kernel mailing list which is quite informative. Quoting Jim Magee (from the darwin team - I think):
In short, the kernel VM system when dealing with memory pressure scans
through in-use pages and tries to keep them in a balance between
active and inactive markings. The inactive pages are scanned for reuse
while marked as inactive. If they have been reused, they are marked as
active and some other page must move from active to inactive state to
detect if it is in active use. So, inactive is a misnomer. It is
shorthand for "possibly inactive, lets try to verify that."
As you discovered, the internal balance we (currently) strive for is
approximately 2/3 active vs 1/3 inactive...
This explains the behaviour you observe. I.e. the inactive pages you see belong to running programs which haven't been recently used. So, when you fire-up a new program, inactive pages are swapped out. At the same time pages from other programs are marked as inactive to maintain the 2/1 ratio of active vs inactive.
The thread also contains some suggestions to learn more about the darwin internals. There are also some suggestions in case you started investigating the memory usage because of beachball problems (which usually have little to do with it).
The conclusion remains the same: Trust your kernel and don't try to outsmart it. :-)
Yea it is strange. Is it one application taking up all the RAM? Maybe OSX limits applications not to use more than 80% RAM at once. Inactive does not mean its free though. It is reserved for something. – Piotr Kula – 2012-08-17T10:36:24.450
No - many apps, Browsers, Eclipse and etc From what I read it is free since is a recently closed apps cache.There should be way to make OS X to not swap when there is inactive memory – Balchev – 2012-08-17T12:33:32.387
I can reproduce it anytime and can make a screen of the activity monitor if is needed – Balchev – 2012-08-17T12:43:23.573
2Inactive memory is not free memory. – kinokijuf – 2012-08-19T12:16:28.813
2@kinokijuf it should, however, act as free memory when there is no free memory left. If inactive memory is always swapped to disk anyway, there's no real point in making the active - inactive distinction. – Pieter – 2012-08-20T12:58:00.730
You should read this ServeFault answer. Swap isn't always bad, and there are different strategies an operating system might use: http://serverfault.com/questions/305295/why-does-windows-2008-use-swap-before-the-memory-is-full/305354#305354
– Joel Coehoorn – 2012-12-19T22:55:53.883