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I'm scanning documents of different sizes and am trying to crop them in such a way that they will fit in a Letter size paper when printed (without stretching a small image, or resizing a larger image to fit in the paper).
If I know the DPI of my image (300 DPI), and the DPI that my printer prints in (600 DPI), and the size of the paper (Letter size is 8.5 by 11 inches [215.9 mm × 279.4 mm]), can I compute for the size of an image (in pixels) so that it will not need to be resized to fit the paper's width when printed, and just fit the paper width exactly? How do I do this?
In the screenshot below, what I would like to happen is for the image to fit the paper's width when I choose 'Original size (from image DPI)', so that I'll have no need to choose 'Best fit to page (aspect ratio)' or 'Stretch to page (no aspect ratio)'. This will ensure that I don't save images with resolutions higher than what my printer can print in Letter size, but high enough so that I won't need to stretch a small image.
My software for image printing will be Irfanview. My OS is windows-7.
If the original image is 8.5 x 11, then it will fit properly when you print it on 8.5 x 11 paper. The pixels will automatically be scaled up by a factor of two by the printer since it has twice the dpi. – psusi – 2012-05-12T19:26:08.590
@psusi I would like to know how to make my image be 8.5 x 11 inches in size, or just have 8.5 inches width (i.e. how to compute for the equivalent of 8.5 x 11 inches paper size in pixels?) – galacticninja – 2012-05-13T05:21:40.220
If the page you originally scan is 8.5 x 11 inches, then the image will be 8.5 x 11 inches. If you crop it, then you will need to resize it, in inches. Don't worry about the pixel count, that's just an implementation detail. – psusi – 2012-05-13T21:06:38.413