In a for loop, how do I echo only the current file on a single(updating) line instead of EVERY file which will produce a list?

Question

My first question on this stackexchange, and I am sure there will be more as I venture farther into the world of what is Linux...

I have a for-loop in a shell-script that batch renames all files to a substring (the last n characters) of its original name.

It will echo every iteration on a new line to eventually produce a list of all files but how do I keep that echo on a single/updating line so it doesn't produce this (sometimes large) list?

echo "- Renaming file..."

for file in `find fldr -type f`
do
  newf=$(echo $file | rev | cut -c -6 | rev)
   mv -f $file fldr/$newpt
  echo "  * $file > $newf"
done

actual output...

- Renaming file...
  * file1a.txt > 1a.txt
  * file2a.txt > 2a.txt
  * file3a.txt > 3a.txt
  * ...

desired output...

- Renaming file...
  * file3a.txt > 3a.txt

I would like to see the one line always changing to show the current file only.

[BONUS] How would I get it to also display the n'th file it is renaming?

- 3 files renamed...
  * file3a.txt > 3a.txt

Where n is a cumulative sum/count of the files renamed.

Answer 1

Just change the echo line to this:

echo -ne "\r  * $file > $newf                         "

The spaces on the end clear old output from the line.