Show the matching count of all files that contain a word

What is the single command used to identify only the matching count of all lines within files under the /etc directory that contain the word "HOST"?

I should list only the files with matches and suppress any error messages.

Debora

Posted 2010-10-31T21:59:28.783

Reputation:

1man grep, look for count – mykhal – 2010-10-31T23:11:58.400

you should add grep as a tag, it's quite relevant! – barlop – 2010-11-01T01:05:28.860

Answers

To count the matches, listing only the filename(s) and count:

grep -src HOST /etc/*

Example output:

/etc/postfix/postfix-files:1
/etc/security/pam_env.conf:6
/etc/X11/app-defaults/Ddd.3.3.11:1
/etc/X11/app-defaults/Ddd:1
/etc/zsh/zshrc:0
/etc/zsh/zshenv:0

The -c option supresses normal output and prints a match count for each file.

If you'd like to suppress the files with zero counts:

grep -src HOST /etc/* | grep -v ':0$'

To print the line number (-n) and file name (-H) for each matching line for any number of input files:

grep -srnH HOST /etc/*

Example output:

/etc/lynx-cur/lynx.cfg:254:.h2 LYNX_HOST_NAME
/etc/lynx-cur/lynx.cfg:255:# If LYNX_HOST_NAME is defined here or in userdefs.h, it will be
/etc/X11/app-defaults/Ddd.3.3.11:8005:    DDD 3.3.11 (@THEHOST@) gets @CAUSE@\n\
/etc/X11/app-defaults/Ddd:8010:    DDD 3.3.12 (@THEHOST@) gets @CAUSE@\n\

The option -r causes grep to recursively search files in each subdirectory at all levels under the specified directory. The -s option suppresses error messages.

To suppress matches of binary files, use the -I option.

See man grep for more information.

Paused until further notice.

Posted 2010-10-31T21:59:28.783

Reputation: 86 075

You can also use the -l flag to suppress files with zero counts, like so: grep -c -l HOST /etc/* – Achal Dave – 2017-03-17T14:10:08.283

@AchalDave did you try it? – Yola – 2019-01-18T16:31:21.597

@AchalDave: Using -l prevents the counts from being displayed. – Paused until further notice. – 2019-01-18T19:19:33.773

Its not one command, but it is one line

something like

 grep -r ',,HOST' . | wc -l

hvgotcodes

Posted 2010-10-31T21:59:28.783

Reputation: 748

grep -c HOST *

… should do it.

Visage

Posted 2010-10-31T21:59:28.783

Reputation: 111

The question is worded a little odd. First it asks for the amount of lines that match in all the files, then it wants you to list the file names.

To count the matching lines in all files:

grep -R "HOST" /etc 2> /dev/null | wc -l

To list the file names:

grep -Rl "HOST" /etc 2> /dev/null

John T

Posted 2010-10-31T21:59:28.783

Reputation: 149 037