How do I unset or get rid of a bash function?

37

2

If you set or export an environment variable in bash, you can unset it. If you set an alias in bash, you can unalias it. But there doesn't seem to be an unfunction.

Consider this (trivial) bash function, for example, set in a .bash_aliases file and read at shell initialization.

function foo () { echo "bar" ; }

How can I clear this function definition from my current shell?
(Changing the initialization files or restarting the shell doesn't count.)

quack quixote

Posted 2010-06-19T03:16:08.420

Reputation: 37 382

All that being said, unfunction would be a nice name for a command :-) – Joey – 2010-06-19T18:00:04.203

@Johannes Rössel: zsh has it. – Chris Johnsen – 2010-06-19T20:57:58.170

Hm, indeed. Still, I find PowerShell's way of dealing with all this slightly more intuitive and consistent :-) – Joey – 2010-06-20T02:12:37.717

Answers

58

The unset built-in command takes an option, -f, to delete functions:

unset -f foo

Form the unset entry in the bash manpage:

If -f is specified, each name refers to a shell function, and the function definition is removed.

Note: -f is only really necessary if a variable with the same name exists. If you do not also have a variable named foo, then unset foo will delete the function.

Chris Johnsen

Posted 2010-06-19T03:16:08.420

Reputation: 31 786

that's what i was missing. i'd found the -f parameter in export but hadn't found it in unset. thanks. – quack quixote – 2010-06-19T03:57:36.730

2

@XavierStuvw: unset is not an external command, it is part of the shell (bash in this case); try man bash and find the entry for unset (the manage is quite large, unset is under the Shell Builtin Commands section).

– Chris Johnsen – 2017-03-05T21:39:55.617

4

See help unset:

unset: unset [-f] [-v] [-n] [name ...]

Unset values and attributes of shell variables and functions.

For each NAME, remove the corresponding variable or function.

Options:
  -f    treat each NAME as a shell function
  -v    treat each NAME as a shell variable
  -n    treat each NAME as a name reference and unset the variable itself
    rather than the variable it references

Without options, unset first tries to unset a variable, and if that fails,
tries to unset a function.

Some variables cannot be unset; also see `readonly'.

Exit Status:
Returns success unless an invalid option is given or a NAME is read-only.

There is neither unset --help nor man unset unfortunately.

XavierStuvw

Posted 2010-06-19T03:16:08.420

Reputation: 309

4There is not man unset because it is a built-in command and for the built-in commands there is instead help. For some built-in command it exists an external executable too. In case of doubt try e.g. type mycommnad. For example type unset and it will answer you unset is a shell builtin. If you want to know if it exists the executable too try which echo (another buikt-in) and it will say where it is. The --option_long is typical of the executable command. Try echo --help and /bin/echo --help. :-). – Hastur – 2017-03-06T11:46:30.587

@Hastur Feel free to add your comment to the answer by editing its tail. If the reviewers approves of it, you'll be awarded 2 points. – XavierStuvw – 2017-03-06T18:28:21.523

1...thanks for the thought Xavier: it was more for you than to complete the answer; I guess you missed that it was a built-in command and for them you have to use help instead of man. (Not really true because you find them in man bash in the chapter SHELL BUILTIN COMMANDS or directly with man BASH-BUILTINS...). It's cosy that under a bash shell you can simply ask for help and you will receive the list of built-in command :-). (Try help help and man man too). – Hastur – 2017-03-07T14:56:40.380

1@Hastur You may well complete the answer for the benefit of all readers. Then we can delete the comments to make good riddance of small-print clutter. – XavierStuvw – 2017-03-07T15:14:17.303

Yes @Hastur, please do. I was about to do it but since I didn't write the comment I can't easily get the markup for it => too much manual effort for me to make it feel worthwhile. :) – Per Lundberg – 2020-01-22T07:54:04.457

0

I recently wanted to completely uninstall nvm and reinstall it, and get rid of any of its environments. Turns out that getting rid of it does not seem to because much of nvm is in part implemented as a boatload of shell functions that are sourced into your shell via .bash_profile or .bashrc, or wherever you added those sourcing commands it told you to when you first installed it.

Baffled at first by which nvm returning nothing yet clearly the nvm command and others were still being found, I eventually discovered via declare -F that it's a bunch of shell functions. I didn't want to just kill the shell and start a new one (for reasons not relevant here), so I cleared nvm functions out of that shell with this:

for F in `declare -F | grep -e nvm | cut -f 3 -d\ `; do unset -f $F; done

Some variations on that might be helpful to someone out there that for whatever reason wants to do something similar and can't restart a new shell or doesn't want to.

slowkoni

Posted 2010-06-19T03:16:08.420

Reputation: 1