How to get access to the WEB-INF/views/some.jsp? spring mvc

I successfully deployed my webapp to the Tomcat localhost. My app has 2 pages: localhost:8080/spring-mvc and localhost:8080/home. The first page has a link to the second. When I start my app, it successfully opens the first page, but when I follow the link to the second page the error appears:

HTTP Status 404 – Not Found.

It seems like there is no access to the WEB-INF/view folder. Can you help me to resolve this problem?

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

</beans>

dispatcher-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
       http://www.springframework.org/schema/context
       http://www.springframework.org/schema/context/spring-context-3.0.xsd
       http://www.springframework.org/schema/mvc
       http://www.springframework.org/schema/mvc/spring-mvc.xsd">

        <context:component-scan base-package="com.stoliarenko"/>

        <mvc:annotation-driven/>
    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
              <property name="prefix" value="/WEB-INF/views/"/>
              <property name="suffix" value=".jsp"/>
          </bean>
</beans>

index.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
  <head>
    <title>Index Page</title>
  </head>
  <body>
  <a href="/home">Go To Home Page!!</a>
  </body>
</html>

home.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
    <title>${pageTitle}</title>
</head>
<body>
${message}
</body>
</html>

HomeController.java

package com.stoliarenko;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HomeController {

    @RequestMapping(value = "/home")
    public ModelAndView home(){
        ModelAndView modelAndView = new ModelAndView("home");
        modelAndView.addObject("pageTitle", "Home Page");
        modelAndView.addObject("message", "Hi, Welcome! This is HomePage!");
        return modelAndView;
    }
}

Nikolai Stoliarenko

Posted 2019-08-18T22:05:45.677

Reputation: 1

How to get access to the WEB-INF/views/some.jsp? spring mvc

No answers