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VSCode 1.25 version, XDebug 2.6, php-fpm 72, Windows 10 (1803).
I have installed xdebug itself and vscode xdebug extension using this info: https://marketplace.visualstudio.com/items?itemName=felixfbecker.php-debug
Now when i run debugger, i immediately get an error in a DEBUG console:
spawn php ENOENT
Despite this thing - everything seems to be working (debugging itself) as intended. Should i ignore this message/error?
I am using php inside WSL, in VSCode (installed in Windows) settings i've set correct (working) path to my php.
Alexander Kim
Posted 2018-08-09T08:02:08.807
Reputation: 318
Vscode in Windows or in Linux? – Biswapriyo – 2018-08-09T09:03:21.660
in Windows, php is inside WSL – Alexander Kim – 2018-08-09T11:08:57.683
Voting to migrate this to Stack Overflow. – slhck – 2018-08-09T11:40:07.263
I need it in Windows. so no way. – Alexander Kim – 2018-08-09T15:55:41.893