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I need to get the contents of a line by its number I heard of grep and researched the whole forum but got no luck what is the command? E.g I enter a cmd like 'viewlinecontent linenumber file.php' and i will get the line contents.
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I need to get the contents of a line by its number I heard of grep and researched the whole forum but got no luck what is the command? E.g I enter a cmd like 'viewlinecontent linenumber file.php' and i will get the line contents.
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sed works well here:
linenumber=42 # or whatever
sed -n "${linenumber}p" file
use -n
to prevent printing every line.
${linenumber}
specifies the "address range" (a single line), and
p
to print that line.
If you want your specific syntax, create a shell function:
viewlinecontent() {
sed -n "${1}p" "$2"
}
viewlinecontent 42 file.php
Someday I need to come to terms with sed... – Frank Thomas – 2018-02-13T20:53:48.670
sed has cryptic one-character commands, no variables, no arithmetic, etc. Most things can be done more readably/maintainably in awk or perl. I only use sed for very short filters:
sed q
==head -1
;sed -n '$p'
==tail -1
;sed 's/search/replace/g'
;sed -i 's/\r$//'
==dos2unix
– glenn jackman – 2018-02-13T21:17:51.843