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I ran lshw
from a LiveUSB, but I'm not entirely clear how to understand one part of the output. In the first part, it says width: 32 bits
, but just a few lines down in the CPU details it says width: 32 bits
.
There are several slightly different models under the category of Dell Dimension E521, so it's been a bit tricky trying to research this, but it seems like the version I have is a 64 bit system.
What does lshw
mean in the first part of the output by width: 32 bit
?
Here are the relevant parts of the output (emphasis added):
sysresccd
description: Desktop Computer
product: Dimension E521 ()
vendor: Dell Inc
[width: 32 bits] <-----------
capabilities: smbios-2.4 dmi-2.4 smp-1.4 smp vsyscall32
configuration: boot=normal chassis=desktop cpus=2 uuid=44454C4C-4400-1050-8052-C7C04F574331
*-core
description: Motherboard
product: 0UW457
vendor: Dell Inc
physical id: 0
version: A03
*-cpu:0
description: CPU
product: AMD Athlon(tm) 64 X2 Dual Core Processor 3600+
vendor: Advanced Micro Devices [AMD]
physical id: 8
bus info: cpu@0
version: 15.11.1
slot: Socket M2
size: 1GHz
capacity: 3GHz
[width: 64 bits] <-----------
clock: 1GHz
capabilities: boot fpu fpu_exception wp vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ht syscall nx mmxext fxsr_opt rdtscp x86-64 3dnowext 3dnow rep_good nopl extd_apicid pni cx16 lahf_lm cmp_legacy svm extapic cr8_legacy 3dnowprefetch lbrv vmmcall cpufreq
I wasn't sure whether to post this on SuperUser because it's a hardware question, or on Unix & Linux StackExchange because it's a question about the output of the Linux command
– IQAndreas – 2016-01-05T13:15:22.607lshw
.It means the OS your running is 32-bit running on a 64-bit processor. – Ramhound – 2016-01-05T13:27:23.690