print 1 to 100 without using recursion and conditions

Question

can we print 1 to 100 without using any if conditions and loops in c&c++?

Conditon: main point is you must not use recursion...and doesnt hardcode code in it for e.g

print(1 2 3..etc);

Answer 1

C (90) (79) (59) (47) (42) (40)

static int

x=1;a(){char b[8];printf("%d\n",x++);b[24]-=5*(1-x/101);}main(){a();return 0;}

The function a which prints the numbers does not call itself! I exploited a buffer overflow and changed the return address to make the program counter go over function a again as long as I need.

I don't know if this is considered to be a recursion, but I thought it would worth trying. This code works on my 64-bit machines with gcc 4.6, for other platforms the last statement of function a, could be a little different.

Exp1: I allocated a dummy buffer on stack b, and then addressed a passed-by-end location, which is the location of return address. I anticipated the distance between start of buffer and return address location from disassembly of function a.

Exp2: Expression 5*(1-x/101), is 5 for all x<=100 and 0 for x=101. By looking at disassembly of main (in my case), if you decrease the return address by 5, you will set the PC to calling point of a again. In the updated codes, the return value of printf is used for checking loop condition.

Update: After applying ugoren's suggestions and some other changes:

x;a(){int b[2];b[3*(printf("%d\n",++x)&2)]-=5;}main(){a();}

Update2: After Removing function a:

x;main(){int b[2];b[6^printf("%d ",++x)&4]-=7;}

Update3:

x;main(b){(&b)[1|printf("%d ",++x)&2]-=7;}

Update4: Thanks to mbz :)

x;main(b){(&b)[3|printf("%d ",++x)]-=7;}

Answer 2

85

C (gcc)

#define c printf("%d ",i++);
#define b c c c c c
#define a b b b b b
main(i){a a a a}

Assuming no command line arguments were passed.

Answer 3

C++ (159 136)

With templates.

#include<cstdio>
#define Z(A,B,C,D)template<A>struct P B{P(){C;printf("%d ",D);}};
Z(int N,,P<N-1>(),N)Z(,<1>,0,1)int main(){P<100>();}

Answer 4

C 71 70

Assuming the ? operator is allowed.

#define f(a)a a a a a
int main(i){f(f(f(printf(i<102?"%d ":0,i++);)))}

Edit: ""->0

If ? is too similar to an if statement, then use this instead (78)

#define f(a)a a a a
#define g(a)f(a)a
int main(i){f(g(g(printf("%d ",i++);)))}

Answer 5

PowerShell (6 characters)

1..100

Answer 6

267

this is the best I can think of, assuming using the preprocessor is fine.

#include <stdio.h>
#define a(i)i,i+1,i+2,i+3
#define b(i)a(i),a(i+4),a(i+8),a(i+12)
#define c(i)b(i),b(i+16)
#define e c(1),c(33)
#define f %d %d %d %d
#define g f f f f f f f f
#define r(m) #m
#define s(m) r(m)
int main(){printf(s(g g g f),e,c(65),a(97));return 0;}

Answer 7

C++ (115)

#include <cstdio>
template<int i>void p(){printf("%d ",i);p<i+1>();}
template<>void p<101>(){}
int main(){p<1>();}

Answer 8

MATLAB/Octave, (5 chars)

1:100

Answer 9

Python 2 (12)

>>> range(1,101)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]

Answer 10

Python 3 (25)

print(list(range(1,101)))

Answer 11

Ruby (11) [non-competitive]

p *(1..100)

(Thanks to histocrat)

Previous 14-character solution:

p *1.upto(100)

This is a non-competitive answer (not C/C++ as requested)

Answer 12

Python 2 (39 chars)

p=lambda d:print d+1,;map(p,range(100))

Python 3 (53 chars)

p=lambda d:print(d+1,end=' ');set(map(p,range(100)))

or print numbers on separate lines (28 char)

set(map(print,range(1,101)))

or (tested in Python 3.3.2, set items printing in ascending order - 24 chars)

print(set(range(1,101)))

Answer 13

Bash 13

echo {1..100}

Some more text so it posts.

Answer 14

JavaScript (ES6), 38 bytes

alert([...Array(101).keys()].slice(1))

Creates an array of length 101, uses the spread operator to put the array keys (0 to 100) into an array, removes the first element (0) then alerts the numbers within the array.

Answer 15

Scala (22)

1 to 100 foreach print

Answer 16

Perl 6 (10)

print ^101

If one wants to be able to read the numbers and therefore spaces between the numbers would be nice, the following will do the trick.

say ~ ^101

Answer 17

Perl (65)

Here's a non-trivial Perl approach (not like say for 1 .. 100). The program uses perl's regular expression engine to count its own characters (two times), and that's the reason why I couldn't golfify the content of $k. It tries to find a (minimal, non-greedy) group of arbitrary single characters until (*FAIL).

$k='$k =~ /^(.+?)(?{print length($1) . "\n"})(*FAIL)/#'x2;eval$k;

The output is a list of all integers from 0 to 100 with newlines.

Answer 18

Pygmy, (18 characters)

alert|[1 100].fill

Answer 19

JAVA, 52 chars

IntStream.range(1,101).forEach(System.out::println);

Answer 20

Python - 61

Looping? No this is list comprehension.

d=[0,1,2,3,4,5,6,7,8,9];print[x*10+y+1 for x in d for y in d]

Answer 21

Hassium, 31 Bytes

func main()print(range(1, 100))

Run online and see expanded here