What's on the TV?

Question

Challenge

Write a program which, using the XML data from the site here, display the name of the programme which is currently showing on BBC 1.

Information

All times are given at London time (GMT+1 at the time of posting and GMT+0 after the 30th October). Therefore, you should convert your local time to London time.

Each programme is given a start and end time. If the current time is after the start time and before the end time of a programme, that programme is currently showing. Your programme may handle overlaps in anyway you wish.

Your output must be the programme title, like so:

BBC News

However, if the programme has a subtitle (shown by the presence of the subtitle tag), the output should be like so:

Steptoe and Son: The Piano

Where Steptoe and Son is the title and The Piano is the subtitle. An example programme with a subtitle is as follows:

<programme>
    <subtitle>Newcastle</subtitle>
    <title>Flog It!</title>
    <end>1710</end>
    <start>1610</start>
    <desc>
      Antiques series. Paul Martin presents from the Discovery Museum in Newcastle. The items uncovered include a book of autographs with a local connection. Also in HD. [S]
    </desc>
</programme>

URL shorteners are disallowed but XML parsing libraries are allowed.

Winning

The shortest code in bytes wins.

Answer 1

Bash + curl + XMLStarlet, 166 characters

d=`TZ=Europe/London date +%H%M`
curl -s bleb.org/tv/data/listings/0/bbc1.xml|xmlstarlet sel -t -m "//programme[start<=$d and end>$d]" -v title -m subtitle -o :\  -v .

Sample run:

bash-4.3$ date 
Mon Aug 22 14:17:07 EEST 2016

bash-4.3$ bash bbc.sh 
Bargain Hunt: Carmarthen

Answer 2

Python, 440 428 426 398 395 Bytes

-31 Bytes thanks to @Loovjo

Throws an error when it found the date.

import re,pytz,urllib
from datetime import*
x=urllib.urlopen("http://www.bleb.org/tv/data/listings/0/bbc1.xml").read().split("</p")[:-1]
for m,n in enumerate(re.search("\d*</s",i).group()for i in x):
 if n>datetime.strftime(datetime.now(pytz.utc).astimezone(pytz.timezone('Europe/London')),"%H%M"):print re.search(">.*?</t",x[m-1]).group()[1:-3],": "+re.search("e>.*?</s",x[m-1]).group()[2:-3],_

Please don't hurt me for parsing xml with regex.

version using a xml parser, 398 Bytes

import re,pytz,urllib
import xml.etree.ElementTree as ET
from datetime import*
x=list(ET.parse(urllib.urlretrieve("http://www.bleb.org/tv/data/listings/0/bbc1.xml")[0]).getroot())
for m,n in enumerate(i.find("start").text for i in x):
 if n>datetime.strftime(datetime.now(pytz.utc).astimezone(pytz.timezone('Europe/London')),"%H%M"):print x[m-1].find("title").text,": "+x[0].find("subtitle").text,_