Rearrange a number into alphabetical order

Question

Given a non-negative integer (n), create a function that returns n in alphabetical order, according to the literal spelling of each digit in n.

Examples:

Input: 101
>> one, zero, one
>> one, one, zero
Output: 110

Input: 31948
>> three, one, nine, four, eight
>> eight, four, nine, one, three
Output: 84913

Input: 5544
>> five, five, four, four
>> five, five, four, four
Output: 5544

Input: 1234567890
Output: 8549176320

Note: the operations in the example are illustrative only and do not need to be included in the output. Only the alphabetically-sorted number needs to be returned.

This is code-golf, so the shortest code in bytes wins.

Edit: the input can be taken in any desired format that best suits your language, and the output can be produced similarly by returning from the function or printing. The input will always be a natural number (including 0) and will not contain leading 0's.

Relevant OEIS entry (A057846) found by @DomHastings

Answer 1

Perl 6,  32  28 bytes

{+[~] .comb.sort: *.Str.uniname}
{+[~] .comb.sort: *.uniname}

Explanation:

{
  # turn the following into a Numeric
  +

  # fold the following list using string concatenation operator
  [~]

    # split $_ into individual characters
    # (implicit method call on implicit parameter)
    .comb

    .sort:
    *.uniname # sort by the Unicode name of the character (digit)
}

Test:

#! /usr/bin/env perl6
use v6.c;
use Test;

my @tests = (
  101 => 110,
  31948 => 84913,
  5544 => 5544,
  1234567890 => 8549176320,
);

# give the lambda a lexical name for clarity
my &int-sort = {+[~] .comb.sort: *.uniname}

plan 3 * @tests;

for @tests -> $_ ( :key($input), :value($expected) ) {
  put '';
  isa-ok $input, Int, "input ($input) is an Int";

  my $output = int-sort $input;

  is $output, $expected, .gist;
  isa-ok $output, Int, "output ($output) is an Int"
}

1..12

ok 1 - input (101) is an Int
ok 2 - 101 => 110
ok 3 - output (110) is an Int

ok 4 - input (31948) is an Int
ok 5 - 31948 => 84913
ok 6 - output (84913) is an Int

ok 7 - input (5544) is an Int
ok 8 - 5544 => 5544
ok 9 - output (5544) is an Int

ok 10 - input (1234567890) is an Int
ok 11 - 1234567890 => 8549176320
ok 12 - output (8549176320) is an Int

Answer 2

05AB1E, 12 11 10 bytes

•OWÿ¾•vy†J

Explained

•OWÿ¾•        # push sortorder (236719458)
      v       # for each number in sortorder
       y†     # filter to the front
         J    # join
              # implicitly print

Try it online

Saved 1 byte thanks to Adnan

Answer 3

JavaScript (ES6), 54

Edit same char count, but avoiding the global variable z

Input / output as strings

n=>[...n].sort((a,b)=>n[a]-n[b],n='9487216503').join``

Test

f=n=>[...n].sort((a,b)=>n[a]-n[b],n='9487216503').join``

function test() {
  O.textContent=f(I.value)
}

test()

<input id=I type=number value=31948 oninput='test()'>
<pre id=O></pre>

Answer 4

Haskell, 62 51 44 bytes

As @nimi suggested, using a list comprehension is shorter than composing functions:

f x=0+read[a|a<-"8549176320",b<-show x,a==b]

For reference my version:

f n=read.(=<<)(\x->filter(==x)$show n)$"8549176320"

The pointfree version is a bit longer:

f=flip(read.)"8549176320".(=<<).flip(filter.(==)).show

Straightforward: Filter the digits in the correct order and then concatenate the result.

Answer 5

Pyth, 12 10 bytes

ox`C" Ȁ\0

Not sure if it can be golfed further. Input needs to be enclosed in quotes.

2 bytes saved thanks to @isaacg!

In pythonic pseudocode:

                Q = input()
o          Q    sort(Q, key = lambda N:
  `C" Ȁ\0        repr(base256toDec(" Ȁ\0"))
 x        N         .index(N)     # 8 being absent from the number yields -1
                )

Test it here.

Answer 6

Perl, 37 bytes

36 bytes code + 1 byte command line (-F)

say sort{8549176320=~/$b.*$a/||-1}@F

Usage example:

echo -n "04823" | perl -F -M5.010 entry.pl

Answer 7

Mathematica 35 78 47 bytes

31 bytes saved thanks to a suggestion by LIAMnYP!

FromDigits@SortBy[IntegerDigits@#,IntegerName]&

IntegerDigits breaks up the number into digits which are then sorted according to their names in English. FromDigits assembles the digits into a base-10 number.

---

FromDigits@SortBy[IntegerDigits@#,IntegerName]&[1234567890]

8549176320

Answer 8

C, 142 141 117

Pass parameter as long long * to f(); the function modifies the parameter:

f(long long*n){char*c="8549176320",g[10]={0};for(;*n;*n/=10)++g[*n%10];for(;*c;++c)for(;g[*c-48]--;*n=*n*10+*c-48);}

long long is necessary since the last test case overflowed an int when sorted.

Answer 9

MATL, 19 bytes

Vt'8549176320'&m2$S

Try it online!

Explanation

V              % Implicitly input number. Convert to string (¹)
t              % Push copy of (¹)
'8549176320'   % Push this string (²), which defines order
&m             % Indices (³) of each element of (¹) in (²)
2$S            % Sort copy of (¹) according to (³). Implicitly display

Answer 10

Jelly, 11 bytes

“U1°ŀ”OṾf@€

Try it here.

Explanation

“U1°ŀ”O       Get the Unicode ordinals of “U1°ŀ”
                (all of which are coincidentally single bytes
                in the Jelly code page!)
              The result is [85, 49, 176, 320].
       Ṿ      Uneval. This gets us the string “85,49,176,320”.
        f@€   For each char in this string, extract all chars
                from the first command line argument that
                equal it.

Answer 11

Python 2 - 95 bytes

def s(n):
    l=list("8549176320")
    return "".join(sorted(list(n),key=lambda x: l.index(x)))

Attempting further golfing...I think the line 2 is unnecessary and this can become 1 lambda.

EDIT: 49 char version in comments, thx to xnor and vaultah for help.

Answer 12

-- Oracle 11 (SQL): 164 bytes

  SELECT LISTAGG(DECODE(s,0,'zero',TO_CHAR(TO_DATE(s,'j'),'jsp')),',')WITHIN GROUP(ORDER BY 1)FROM(SELECT SUBSTR(&1,level,1)s FROM dual CONNECT BY LEVEL<=LENGTH(&1));

Long form and explanation

  SELECT LISTAGG(DECODE(s,0,'zero',TO_CHAR(TO_DATE(s,'j'),'jsp')),',') WITHIN GROUP (ORDER BY 1)
  FROM ( SELECT SUBSTR(&1,level,1)s FROM dual
           CONNECT BY LEVEL <= LENGTH(&1)
        );

Get the input as parameter to script:

  SELECT &1 FROM dual

"create" rows by using connect by based on length of input:

  CONNECT BY LEVEL <= LENGTH(&1)

Rip out each digit from the string for each position:

  SELECT SUBSTR(&1,level,1)s FROM dual

Convert the digit to Julian date, and back to Char to get spelling:

  TO_CHAR(TO_DATE(s,'j'),'jsp')

Check for zero - special case.

  DECODE(s,0,'zero'

Use LISTAGG function to concatenate rows back into a single row list, comma delimited, ordered alphabetically

  LISTAGG(DECODE(s,0,'zero',TO_CHAR(TO_DATE(s,'j'),'jsp')),',') WITHIN GROUP (ORDER BY 1)

Always fun trying to tweak SQL for things like this ... :) really tests my knowledge of the bugger ...

Answer 13

Racket, 142 130 bytes

(λ(n)(string->number(list->string(sort(string->list(~a n))char<? #:key(λ(m)(string-ref "9487216503"(-(char->integer m)48)))))))

Of which conversions are more than almost half of the length (76 64 bytes).

Answer 14

Ruby, 60 bytes

->n{n.to_s.chars.sort_by{|c|'8549176320'.index c}.join.to_i}

Answer 15

TSQL, 260 bytes

Used reversed bubble sort to avoid refering to the length, to save some bytes

Golfed:

DECLARE @ varchar(99)=101

,@i INT=99,@j INT=98WHILE @i>1SELECT
@=IIF(CHARINDEX(x,'598327614')>CHARINDEX(y,'598327614'),STUFF(STUFF(@,@j,1,x),@i,1,y),@),@i-=IIF(@j=1,1,0),@j=IIF(@j=1,@i,@j-1)FROM(SELECT
SUBSTRING(@,@i,1)x,SUBSTRING(@,@j,1)y)z
PRINT @

Ungolfed:

DECLARE @s BIGINT=1234567890

DECLARE @ char(99)=@s,@i INT=99,@j INT=98
WHILE @i>1
  SELECT 
    @=IIF(CHARINDEX(x,'236719458')>CHARINDEX(y,'236719458'),
        STUFF(STUFF(@,@j,1,x),@i,1,y),@), 
    @i-=IIF(@j=1,1,0),
    @j=IIF(@j=1,@i,@j-1)
  FROM(SELECT SUBSTRING(@,@i,1)x,SUBSTRING(@,@j,1)y)z
PRINT CAST(@ as bigint)

Insisting on using integer types as input and output added 37 bytes

Answer 16

ClojureScript, 45 bytes

#(apply str(sort-by(vec"9487216503")(str %)))

Uses some screwy string->int conversion from Javascript leak through, so it's not valid Clojure.

Answer 17

Firebird, 317 bytes

Golfed:

select list(s,'')from(with recursive q as(select 1 p,substring(:a from 1 for 1)s from rdb$database q union all select q.p+1 p,substring(:a from q.p+1 for 1)s from q where q.p<char_length(:a))select s from q order by iif(s=8,0,iif(s=5,1,iif(s=4,2,iif(s=9,3,iif(s=1,4,iif(s=7,5,iif(s=3,7,iif(s=2,8,iif(s=0,9,6))))))))))

Ungolfed:

select list(s, '')
from (
   with recursive q as (
      select 1 as p, substring(:a from 1 for 1) s
      from rdb$database q
      union all
      select q.p + 1 as p, substring(:a from q.p + 1 for 1) as s
      from q
      where q.p < char_length(:a)
   )
   select s
   from q
   order by iif(s = 8, 0,
               iif(s = 5, 1,
                  iif(s = 4, 2,
                     iif(s = 9, 3,
                        iif(s = 1, 4,
                           iif(s = 7, 5,
                              iif(s = 3, 7,
                                 iif(s = 2, 8,
                                    iif(s = 0, 9, 6)))))))))
)

There's no split functionality in Firebird. Instead I created a recursive query to get the next character over and over. Then reselect those while sorting by our proper order. Finally concatenate those results back together in a list. Override the default comma delimiter with blank. I could save 11 bytes by creating a new dummy table instead of rdb$database but I thought that may be against the rules.

Answer 18

ZX Spectum, machine code, 53 48 47 45 44 bytes

    org 49200 ; #c030

; table converts ascii to alfabetical order
; start from BASIC with any number as : PRINT "1234567890" AND USR 49208

convtab defb 249 ; zero defb 244 ; one defb 248 ; two defb 247 ; three defb 2+205 ; four defb 1+205 ; five defb 246 ; six defb 245 ; seven ; defb 0 ; eight ; defb 3 ; nine ; last 2 conversions hidden in call-command

start Call #2bf1    ; fetch stackindex
    call #2ab2 ; store back
    ld h,#c0    ; set highbyte of table


Sort Push de
loop ld b,d
    ld c,e
    inc de
    ld a,(bc)   ; fetch number
    Ld l,a
    ld a,(de)
    cp 34       ; endmarker "
    Jr z,exit   ; end reached?
    push hl     ; save number
    ld l,a
    Ld a,(hl)   ; convert second number
    pop hl
    cp (hl)     ; compare numbers
    jr nc,loop  ; in order, no swap
swap ld a,(bc)  ; swap original numbers
    ld l,a
    ld a,(de)
    ld (bc),a
    ld a,l
    ld (de),a
Exit pop de
    Ret z
    jr sort     ; check number for order

Answer 19

PHP, 107 bytes

function($a){usort($a,function($a,$b){return($z=array_flip([8,5,4,9,1,7,6,3,2,0]))[$a]-$z[$b];});return$a;}

Try it online!

Uses a user-defined comparison function to adjust the sorting order.

Output

101         110
31948       84913
5544        5544
1234567890  8549176320

Answer 20

Factor, 128

[ 10 base> [ 48 - ] { } map-as dup [ number>text ] map zip [ second first ] sort-with [ first ] map [ 48 + ] ""map-as 10 >base ]

Hooray for builtins! :D

Answer 21

PHP, 126 bytes

As far as I know php doesn't have any builtins that would really help with this (the best I could do using a usort(str_split()) was 5 bytes longer) so the only thing I'm happy within this answer is the games played with $i to save a couple of bytes on the itteration.

<?php for($i=-1;$i<9;)$a[++$i]=preg_replace("/[^$i]/","",$argv[1]);array_multisort([9,4,8,7,2,1,6,5,0,3],$a);echo implode($a);

Answer 22

APL, 23 bytes

{⍎n['8549176320'⍋n←⍕⍵]}

Explanation:

• n←⍕⍵: get the string representation of n and store it in n
• '8549176320'⍋: find a permutation of n that sorts n given the order 8549176320.
• n[...]: reorder n by that permutation
• ⍎: evaluate the result (to turn it back into a number)

Answer 23

Clojure, 53 bytes

Well, list comprehension idea from Haskell solution seems to be the shortest:

#(apply str(for[p"8549176320"b(str %):when(= p b)]p))

My original approach is 1 byte longer:

#(apply str(sort-by(zipmap"549176320"(range))(str %)))

You can see both function online here: https://ideone.com/afac5n

Answer 24

Common Lisp, 104

(lambda(n)(#1=parse-integer(sort(format()"~A"n)'string<= :key(lambda(u)(format()"~R"(#1#(string u)))))))

Ungolfed

(lambda (n)
  (parse-integer
   (sort (format nil "~A" n)
         #'string<=
         :key (lambda (u) (format nil "~R" (parse-integer (string u)))))))

Convert integer as string, sort characters using the string<= comparison while using a custom :key function which converts a given character as the English representation of the numerical value it represents. Usually I would not use a key function which does as much as this one, but it costs less in bytes than decorate/sort/undecorate.

Answer 25

Python 3, 234 bytes

This is a direct translation of my Factor answer, just for fun.

def f(n):
 s=list(map(int,str(n)))
 return int("".join(list(map(str,list(map(lambda x:x[1],sorted(list(zip(list(map(lambda t:{0:"zero",1:"one",2:"two",3:"three",4:"four",5:"five",6:"six",7:"seven",8:"eight",9:"nine"}[t],s)),s)))))))))

The semantics of the evaluation of "lazy" map and zip objects is the most subtle hard-to-find-bug-inducing piece of genuine horse excrement in the universe. Sometimes, s = map(f, x) won't allow s to be used properly or at all.

Answer 26

Python 3, 74 bytes

lambda x:''.join(i[1]for i in sorted(['9487216503'[int(j)],j]for j in x))

Answer 27

Pyke, 14 bytes

.#uЀB`@

Try it here!

Answer 28

Python 2.7.11, 67 bytes

lambda n:''.join(sorted(list(n),key=lambda s:"9487216503"[int(s)]))

Takes a string as input and outputs a string.

Answer 29

C, 80 bytes

Takes a string containing a number in base 10 and prints to stdio:

F(char*i){for(char*p,d,*o="8549176320";*o;++o)for(p=i;d=*p++;d-*o||putchar(d));}