-1
0
Your task is to print a number. Simple, right? It is simple, but not as simple as this. The first answer is to print the number 1, the second answer is to print the number 2, etc.
Rules
- The first answer must print 1, and the
n
th answer must printn
. - The first answer may be of any length.
- Whitespace, comments, etc. are permitted.
- The next answer's submission's length must within 1 unit of the previous answer's length. That is, if a submissions length is
L
, the next submission must be of lengthL + 1
orL - 1
. The length is measured in characters, not bytes. - No language may be used more than once.
- No person may answer earlier than eight hours after their most recent answer.
- No person may answer twice in a row.
- You may not use a REPL environment.
To win, you must have the most valid answers to this question. You may use a language updated after/ made later than this challenge so long as the language was not intended to answer this challenge.
Answer template
All answers must conform to this template.
# Answer N, Lang name, M characters
program
optional description
Leader board
A leader board will be maintained here in this section. (If anyone wants to create a leader board counting the number of submissions a person has, I will give them a 50 rep bounty on any answer to this question.)
3I'm voting to close this as too broad, as, quote: "There are either too many possible answers..." – Addison Crump – 2016-03-09T20:33:54.263
@CoolestVeto How? – LegionMammal978 – 2016-03-09T20:42:18.800
5How can you win? This can go on forever. The winner just changes constantly? – Rɪᴋᴇʀ – 2016-03-09T20:43:29.863
@RikerW I guess that it's a question of who can find the most languages to answer in. However, another plausible criterion is the person with the most answers after <x amount of time> without any new answers. – LegionMammal978 – 2016-03-09T20:47:01.403
8The idea is good, but it needs something to make it harder after each answer. This would have benefited from some time in the sandbox. – James – 2016-03-09T20:48:30.537
@LegionMammal978 I think that is a good idea. – Rɪᴋᴇʀ – 2016-03-09T20:55:46.967
3This is far too broad in my opinion. You can basically fill your code with no-ops until the desired number of bytes is reached. – Adnan – 2016-03-09T21:08:12.323