Russian Roulette, Reloaded

Question

Let's play Russian Roulette!

Normally, this would be a race to write the shortest MOD 6 program, but that's not very realistic, as the chance of winning decreases with each click. Here are the rules:

1. Emulate a real six-shooter:
   • A single bullet is placed into one of the six chambers, and the barrel is spun once, only before playing.
   • The chance of losing on the nth try is 1/6.
   • The chance of losing after n tries is 1/(6-n)
   • You are guaranteed to lose in, at most, 6 tries.
2. Losing:
   • Display the text *BANG!*
   • Terminate the program.
3. Winning:
   • "Winning" means the gun does not fire, but the bullet is one chamber closer to the hammer.
   • Display the text *click*
   • Present a "trigger" to the user, along with the ability to terminate the program (e.g. "ctrl+c", see below).
4. Program specific:
   • Pulling the trigger is some form of user input, including the first try. (This can be a keystroke, a mouse click, whatever; text prompts are not required.)
   • Only one instance of the program is allowed until it is terminated. (Running a new instance of the program is akin to giving the barrel a good spin, i.e. the probability of losing on the next click is reset to 1/6.)

Shortest code wins!

Leaderboard

<style>body { text-align: left !important} #answer-list { padding: 10px; width: 290px; float: left; } #language-list { padding: 10px; width: 290px; float: left; } table thead { font-weight: bold; } table td { padding: 5px; }</style><script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="language-list"> <h2>Shortest Solution by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr> </thead> <tbody id="languages"> </tbody> </table> </div> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr> </thead> <tbody id="answers"> </tbody> </table> </div> <table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr> </tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr> </tbody> </table><script>var QUESTION_ID = 66763; var ANSWER_FILTER = "!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe"; var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk"; var OVERRIDE_USER = 38512; var answers = [], answers_hash, answer_ids, answer_page = 1, more_answers = true, comment_page; function answersUrl(index) { return "https://api.stackexchange.com/2.2/questions/" + QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER; } function commentUrl(index, answers) { return "https://api.stackexchange.com/2.2/answers/" + answers.join(';') + "/comments?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + COMMENT_FILTER; } function getAnswers() { jQuery.ajax({ url: answersUrl(answer_page++), method: "get", dataType: "jsonp", crossDomain: true, success: function (data) { answers.push.apply(answers, data.items); answers_hash = []; answer_ids = []; data.items.forEach(function(a) { a.comments = []; var id = +a.share_link.match(/\d+/); answer_ids.push(id); answers_hash[id] = a; }); if (!data.has_more) more_answers = false; comment_page = 1; getComments(); } }); } function getComments() { jQuery.ajax({ url: commentUrl(comment_page++, answer_ids), method: "get", dataType: "jsonp", crossDomain: true, success: function (data) { data.items.forEach(function(c) { if (c.owner.user_id === OVERRIDE_USER) answers_hash[c.post_id].comments.push(c); }); if (data.has_more) getComments(); else if (more_answers) getAnswers(); else process(); } }); } getAnswers(); var SCORE_REG = /<h\d>\s*([^\n,<]*(?:<(?:[^\n>]*>[^\n<]*<\/[^\n>]*>)[^\n,<]*)*),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/; var OVERRIDE_REG = /^Override\s*header:\s*/i; function getAuthorName(a) { return a.owner.display_name; } function process() { var valid = []; answers.forEach(function(a) { var body = a.body; a.comments.forEach(function(c) { if(OVERRIDE_REG.test(c.body)) body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>'; }); var match = body.match(SCORE_REG); if (match) valid.push({ user: getAuthorName(a), size: +match[2], language: match[1], link: a.share_link, }); else console.log(body); }); valid.sort(function (a, b) { var aB = a.size, bB = b.size; return aB - bB }); var languages = {}; var place = 1; var lastSize = null; var lastPlace = 1; valid.forEach(function (a) { if (a.size != lastSize) lastPlace = place; lastSize = a.size; ++place; var answer = jQuery("#answer-template").html(); answer = answer.replace("{{PLACE}}", lastPlace + ".") .replace("{{NAME}}", a.user) .replace("{{LANGUAGE}}", a.language) .replace("{{SIZE}}", a.size) .replace("{{LINK}}", a.link); answer = jQuery(answer); jQuery("#answers").append(answer); var lang = a.language; lang = jQuery('<a>'+lang+'</a>').text(); languages[lang] = languages[lang] || {lang: a.language, lang_raw: lang.toLowerCase(), user: a.user, size: a.size, link: a.link}; }); var langs = []; for (var lang in languages) if (languages.hasOwnProperty(lang)) langs.push(languages[lang]); langs.sort(function (a, b) { if (a.lang_raw > b.lang_raw) return 1; if (a.lang_raw < b.lang_raw) return -1; return 0; }); for (var i = 0; i < langs.length; ++i) { var language = jQuery("#language-template").html(); var lang = langs[i]; language = language.replace("{{LANGUAGE}}", lang.lang) .replace("{{NAME}}", lang.user) .replace("{{SIZE}}", lang.size) .replace("{{LINK}}", lang.link); language = jQuery(language); jQuery("#languages").append(language); } }</script>

Answer 1

Pyth, 23 bytes

VO6"*click*" w;"*BANG!*

Really simple. A random number of iterations 0 - 5 display click and request a line of input, followed by a bang at the end.

Answer 2

Ruby, 51 bytes

[*['*click*']*rand(6),'*BANG!*'].map{|x|gets;$><<x}

Ungolfed:

[
  *(                        # Unwrap the following array into the outer one
    ['*click*'] * rand(6)   # An array of 0-5 clicks, see Array#*
  ),
  '*BANG!*'                 # The End
].map do |x| # Shortest way to iterate I was able to find
  gets       # Await input
  $> << x    # Shove the output string to `stdout`
end          # Return value is an array of several (0-5) `stdout`s. Who cares.

or

(['*click*']*rand(6)<<'*BANG!*').map{|x|gets;$><<x}

Ungolfing left for the readers. Not that difficult

• Again, kudos to Martin, this time for a trick with $><< as a puts replacement.
• Doesn't output newlines, but that was not required.
• The shorter, the simpler. The gist of the required behaviour is to do 0-5 clicks and then fire. For that, outputs are accumulated inside the array.
• 2 more bytes can be shaved off if outputs like "*click*" are okay (what's required is printed in the end), by replacing $><< with p . I wasn't sure if this would still follow the rules.

---

68 64 bytes

(another approach)

[*0..5].shuffle.find{|x|gets;x<1||puts('*click*')};puts'*BANG!*'

• Kudos to Martin Büttner for -4 extra bytes.

I didn't put much thought into the algorithm (it can possibly be even more compact, but not so clear), but I really like the model inside it:

• An array emulates a barrel with its elements being chambers' contents. Since only one element is a bullet, rotating it and shuffling it are equivalent.
• 0 is a bullet. Other numbers are not.
• find finds a first return value for which the block is neither false nor nil.
• ||-expression is implicitly returned from the block. It's a short-circuit: it returns its first operand (unless it's nil or false) or a second one (otherwise). So it either returns true (if x<1 or, clearer but longer x == 0) or the return value of puts, while...
• puts always returns nil. Yep.
• gets requests input. Merely hitting Enter suffices.
• Ctrl+C terminates the program

Answer 3

JavaScript, 64 bytes

for(i=6;i<7&&prompt();)alert(new Date%i--?"*click*":i="*BANG!*")

Explanation

To pull the trigger enter any text into the prompt. Enter nothing or click cancel to terminate.

for(
  i=6;             // i = number of chambers
  i<7              // i equals "*BANG!*" (not less than 7) if we lost
    &&prompt();    // see if we should do another shot
)
  alert(           // alert the result
    new Date%i--   // use the current time in milliseconds as a random number, this is safe
                   //     to use because the gap between shots is greater than i (max 6ms)
      ?"*click*"   // on win pass "*click*" to alert
      :i="*BANG!*" // on lose alert "*BANG!*" and set i to not less than 7
  )

Answer 4

Lua, 82 75 bytes

Pretty long, but there's lot of verbose in lua.

for a=math.random(6),1,-1 do io.read()print(a>1 and"*click*"or"*BANG!*")end

Answer 5

LabVIEW, 46 LabVIEW Primitives

Creates an Array of 0s and one 1, has a loop to wait for clicks and outputs the string. It initially says BANG becuase i forgot to reset the indicator before starting it.

Also note that this is a gif, if if does not play/load for you please reopen the page.

Answer 6

Pyth, 31 30 28 bytes

FN.S6 EI!N"*BANG!*"B"*click*

Almost certainly can be improved. Input any number to pull the trigger, blank input to terminate early (with an error).

Explanation:

FN                               for N in...
  .S6                            shuffle(range(6))...
      E                          get a line of input
       I!N                       if N is falsy (i.e. 0)
          "*BANG!*"              implicit output
                   B             break
                    "*click*     else, print click

Answer 7

Seriously, 27 25 bytes

"*BANG!*"6J"*click*"nW,X.

No online link because there is no way to do a prompt with piped input. The program can be CTRL-C'd at any time to chicken out terminate.

Explanation:

"*BANG!*"6J"*click*"nW,X.
"*BANG!*"                  push "*BANG!*"
         6J                push a random integer in [0,6) (n)
           "*click*"n      push "*click*" n times
                     W     while loop (implicitly closed at EOF):
                      ,X.    get input and discard, pop and print top of stack

Answer 8

Perl 5, 43 bytes

Run with perl -p. Stable bullet variant - i.e. bullet position is decided only once in very beginning.

$i//=0|rand 6;$_=$i--?'*click*':die'*BANG*'

Answer 9

PHP, 52 bytes

*<?=$n=&rand(0,6-$argi)?click:"BANG!*";$n||@\n?>*

Requires the -F command line option, counted as three. The trigger is pulled by pressing Enter.

Because -F literally runs the script again for every input (I kid you not), die and the like won't actually terminate, so we exit via suppressed runtime error instead, @\n.

---

Sample Usage

$ php -F primo-roulette.php

*click*
*click*
*BANG!*
$

Answer 10

C, 110 74 72 bytes

Thanks to Dennis for getting rid of the includes and a lot less bytes.

main(r){for(r=time(0)%6;getchar(),r--;)puts("*click*");puts("*BANG!*");}

main(r)
{
    for(r=time(0)%6;getchar(),r--;)
        puts("*click*");
    puts("*BANG!*");
}

Answer 11

Candy, 36 bytes

About half the program is the text to print out :(

:6H_(=b"*click*"(;):=)"*BANG!*\n"(;)

long form:

getc
digit6 rand range0  # build a range from 0 .. rand#
while
  popA              # these are the *click* instances  
  stack2
  "*click*"
  while
    printChr
  endwhile
  getc
  popA
endwhile
"*BANG!*\n"         # out of luck
while
  printChr
endwhile

Answer 12

Python 3, 95 bytes

Also my first golf attempt, also in Python 3. I swear Bruce and I aren't the same person.

from random import*
for a in range(randint(0,5)):input();print("*click*")
input();print("*bang*")

Ungolfed:

from random import*
for a in range(randint(0,5)):
    input()
    print("*click*")
input()
print("*bang*")

Generate a random number between 0 and 5 inclusive, print click that many times, then print bang. Press enter/return to pull the trigger.

Answer 13

PlatyPar, 26 25 bytes

6#?;wT"*click*"O;"*BANG!*

Explanation:

6#?;                        ## random integer [0,6)
    w           ;           ## while stack.last
     T                      ## stack.last--
      "*click*"O            ## alert "*click*"
                 "*BANG!*   ## alert "*BANG!*"

Try it online!

Answer 14

Emacs Lisp, 94 89 bytes

(set'b(%(random)6))(dotimes(a(+ b 1))(read-string"")(message(if(eq a b)"BANG""*click*")))

Ungolfed:

(set 'b (% (random) 6))
(dotimes (a (+ b 1))
  (read-string"")
  (message (if (eq a b) "BANG" "*click*")))

Answer 15

R, 86 80 77 bytes

As usual, R has awesome features to code golfing but looooooong function names.

sapply(sample(0:5),function(n){!n&&{cat('*BANG!*');q()};readline('*click*')})

Answer 16

Python 2, 108 104 102 100 98 bytes

My first attempt at golfing:

from random import*
a=[1]+[0]*5
shuffle(a)
for i in a:input();print("*click*","*BANG!*")[i];" "[i]

Maybe I should add that the program doesn't terminate correctly when you lose, it just throws an exception (which results in termination):

Traceback (most recent call last):
  File "russian_roulette.py", line 4, in <module>
    for i in a:input();print("*click*","*BANG!*")[i];" "[i]
IndexError: string index out of range

Answer 17

Perl 5, 40 bytes

<>,print"*$_*"for(click)x rand 5,'BANG!'

Run without command line options, the trigger is pulled by pressing Enter.

Answer 18

Python, 81 Bytes

import time
for i in["*click*"]*(int(time.time())%6)+["*BANG!*"]:input();print(i)

inspired by the Ruby(51) and Python solutions

Answer 19

Common Lisp, 109

(do(g(b(nthcdr(random 6)#1='(t()()()()() . #1#))))(g)(read-char)(princ(if(setf g(pop b))"*BANG!*""*click*")))

Not very competitive, but I like circular lists:

(do (;; auxiliary variable x
     x
     ;; initialize infinite barrel, rotate randomly
     (b (nthcdr (random 6) #1='(t()()()()() . #1#))))

    ;; we end the loop when x is T (a bullet is fired)
    (x)

  ;; press enter to shoot
  (read-char)

  ;; pop from b, which makes b advance down the list. The popped value
  ;; goes into x and is used to select the appropriate string for
  ;; printing.
  (princ
   (if (setf x(pop b))
       "*BANG!*"
       "*click*")))

Answer 20

Perl 5, 43 bytes

42 bytes + -p command line option. Just press enter to trigger.

$_=0|rand 7-$.<++$i?die"*BANG!*":"*click*"

Thanks to Dom Hastings for his help! Original answer was 67 bytes:

$i++;$a=$i>=int(rand(6));print$_=$a?'*BANG!*':'*click*';last if($a)

Answer 21

MATL, 41 bytes

6Yr`j?t@=?'*BANG!*'DT.}'*click*'DT]}T.]]x

To pull the trigger, input a non-empty string (such as 'try').

To terminate, input an empty string

Examples

In this case the trigger was pulled once and... bad luck:

>> matl
 > 6Yr`j?t@=?'*BANG!*'DT.}'*click*'DT]}T.]]x
 > 
> try
*BANG!*

In this case the user stopped (note the final empty input) after two lucky pulls:

>> matl
 > 6Yr`j?t@=?'*BANG!*'DT.}'*click*'DT]}T.]]x
 > 
> try
*click*
> try
*click*
> 

Explanation

6Yr                  % random avlue from 1 to 6    
`                    % do...while  
  j                  % input string
  ?                  % if nonempty
    t                % duplicate the orignal random value
    @                % loop iteration index  
    =                % are the equal?
    ?                % if so             
      '*BANG!*'D     % display string
      T.             % unconditional break                                     
    }                % else
      '*click*'D     % display string
      T              % true value, to go on with do...while loop
    ]                % end if               
  }                  % else                                                    
    T.               % unconditional break
  ]                  % end                                                     
]                    % end                                                     
x                    % delete original random value

Answer 22

Python 2, 88 84 bytes

This solution is inspired by the python 3 solutions already given. I chose python 2 to remove the print parenthesis even though this changes the behavior of input().

import time
for i in[0]*int(time.time()%6)+[1]:input();print("*click*","*BANG!*")[i]

• I am using modulo of the time as a random function (good enough for russian roulette)
• the player input should be "i" then Enter (otherwise input() will throw an error), this trick relies on the fact that the input can be "whatever".

Answer 23

Perl 6,  58   53 bytes

for ^6 .pick(*) {get;say <*BANG!* *click*>[?$_];!$_&&last} # 58 bytes

$ perl6 -pe '$///=^6 .pick;$_=$/--??"*click*"!!say("BANG!")&&last' # 52+1= 53 bytes

Press enter to pull the trigger, or ctrl+c to put it down.

Answer 24

Perl 5, 69 51 49 bytes

map{<>;print"*click*"}1..rand 6;<>;print"*BANG!*"

There is probably some more golfing potential, I will look into this.

Changes:

• Saved 8 bytes by removing $l and some semicolons, and 10 bytes by changing <STDIN> to <>
• Saved 2 bytes thanks to Oleg V. Volkov

Answer 25

Ruby, 45+1=46

Not as clever as D-side's but slightly shorter.

With command-line flag p, run

rand(7-$.)<1?(puts'*BANG*';exit):$_='*click*'

The user can pull the trigger with return and leave with control-c. p causes the program to run in a loop, reading lines from STDIN and outputting $_. Each time it runs, it increments $.. So on the first run, it chooses a random positive integer less than 6, then 5, then 4, and so on. On the first 0, we output manually and exit, until then we output implicitly.

(and now I notice that there's already a very similar Perl. Oh well.)

Answer 26

VBA, 126 bytes

Golf Version for Minimal Bytes

Sub S()
r=Int(5*Rnd())
e:
a=MsgBox("")
If a=1 Then: If i=r Then MsgBox "*BANG!*" Else: MsgBox "*click*": i=i+1: GoTo e
End Sub

Fun Version that Makes The Buttons more Clear for Increased User Acceptance.

Sub RR()
r = Int(5 * Rnd())
e:
a = MsgBox("Are you Feeling Lucky?", 4)
If a=6 Then: If i=r Then MsgBox "*BANG!*", 16 Else: MsgBox "*click*", 48: i=i+1: GoTo e
End Sub

Some Fun with Custom Forms and You could make a pretty Slick Game in VBA.

Answer 27

APL, 39/65 bytes

{⍞⊢↑⍵:⍞←'*BANG*'⋄∇1↓⍵⊣⍞←'*click*'}6=6?6

Pretty straightforward answer.

Answer 28

C, 180 Bytes

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main(){srand(time(NULL));int r,i=6;while(i!=1){getchar();r=rand()%i;if(r){puts("CLICK");}else{puts("BANG");exit(0);}i--;}}

My first attempt at code golf, there's probably a lot of room for improvement :)

Answer 29

Julia, 71 bytes

b=rand(1:6);while b>0 readline();print(b>1?"*click*":"*BANG!*");b-=1end

Press Enter to fire or Ctrl+C to quit. The latter ends with an InterruptException.

Ungolfed:

# Set an initial bullet location
b = rand(1:6)

while b > 0
    # Read user input
    readline()

    # Check the location
    if b > 1
        print("*click*")
    else
        print("*BANG!*")
    end

    b -= 1
end

Answer 30

Lua, 73 bytes

q=io.read q()for i=2,math.random(6)do print"*click*"q()end print"*BANG!*"

Answer 31

R, 79 bytes

code

readline();for(n in 6:1)ifelse(1/n>=runif(1),cat("*Bang*"),readline("*click*"))

ungolfed

readline()                    # Waits for user to press [Enter] if [Esc] is pressed exits    
for(n in 6:1) {               # for n=6 to n=1
  ifelse(1/n >= runif(1),     # if 1/n >= a random float from 0 to 1 (uniform dist)
     cat("*Bang*"),           # *You're dead*
     readline("*click*")    # else you have another chance, waits for [Enter] again
  )                           
}

The program will wait for an [Enter] before every try, if the user press [Esc] instead the program will end. If the *Bang* happens the program will print it and throw an error, thus terminating itself (is this correct?).

Answer 32

C, 96 bytes (Without counting comment)

#define R 4//chosen by playing russian roulette, guaranteed to be random
int main(){for(;c++<R&&puts(c<R?"Fire?":"☠Bang!☠");getchar(),puts("*click*"));}

Formatted :

#define R 4 // chosen by playing russian roulette, guaranteed to be random
int main(int c) {
    for( ; c++ < R && puts(c < R ? "Fire?" : "☠Bang!☠") ; getchar(), puts("*click*") );
}

Explanation :

There also is a click when it fires, that's the sound of the hammer being released.

After the bang you need to hit enter to take the gun out of the dead man's hand, rigor mortis squeezed his finger around the trigger. While you are prying his hand open you hear another click as the trigger snaps back into normal position.