Generate a random floating point number between 2 limits

Question

This challenge is to generate a random floating-point number between 2 limits. You may use any language so long as it can be called from the command line, and runs on linux. It must also be able to work with negative numbers.

Due to the comment below: You may use fixed point math to come up with a result in-fact fixed point math is preferable in this case.

Input Requirements

Accept a lower and upper limit, no verification required.

Output Requirements

• Must be between the 2 specified limits
• Print it out to the console
• or come up with a way to return it to the shell.

Example

$ prog -1 1
-.445

The program would not spit out a result that is not between those 2 limits. And it would be inclusive of the 2 limits

Win Condition

As with all of these challenges the smallest number of bytes wins.

Answer 1

Cjam, 9 bytes

q~1$-dmr+

Assumes that the first input number is the lower limit and the second one is the upper limit.

Pretty straight forward code:

q~          "Read the input as a string and evaluate it. This puts the two input";
            "integers on stack";
  1$        "Copy the first smaller integer and put it on top of stack";
    -       "Take difference of smaller and larger integer";
     d      "Convert the integer to double";
      mr    "Get a random double float from 0 to the difference of two integers";
        +   "Add the random double to the smaller integer to get random in range";

Try it online here

Answer 2

Ruby, 34 bytes

a,b=$*.map &:to_f
$><<a+(b-a)*rand

Takes inputs via command-line argument as in the usage example.

Answer 3

Pyth - 9 bytes

Works the obvious way like all the others.

+*-vzQOZQ

Pyth's random range function when called with zero as the argument acts as a [0, 1) floating point generator.

+          Add and implicitly print
 *         Times
  -        Difference
   vz      Input 1
   Q       Input 2
  OZ       Float RNG
 Q         Input 2

Try it here.

Answer 4

R, 34

Setup for running from command-line

i=scan('stdin');runif(1,i[1],i[2])

Takes input from STDIN

Example on windows

C:\Program Files\R\R-3.1.3\bin\x64>rscript -e "i=scan('stdin');runif(1,i[1],i[2])"
1
2
^Z
Read 2 items
[1] 1.249665

C:\Program Files\R\R-3.1.3\bin\x64>

Answer 5

C#, 142 141 bytes

C# has too much boilerplate...
Anyways, it is the only language I know and am sure can be compiled and run in Linux.

using System;class A{static void Main(string[]a){var b=double.Parse(a[0]);Console.Write(new Random().NextDouble()*(double.Parse(a[1])-b)+b);}

Ungolfed:

using System;
class A
{
    static void Main(string[] a)
    {
        var b = double.Parse(a[0]);
        Console.Write(new Random().NextDouble() * (double.Parse(a[1]) - b) + b);
    }
}

Also, I just noticed that every example's input was integral. In that case...

C#, 135 bytes, integral input

using System;class A{static void Main(string[]a){int b=int.Parse(a[0]);Console.Write(new Random().NextDouble()*(int.Parse(a[1])-b)+b);}

Ungolfed:

using System;
class A
{
    static void Main(string[] a)
    {
        int b = int.Parse(a[0]);
        Console.Write(new Random().NextDouble() * (int.Parse(a[1]) - b) + b);
    }
}