Print the content of /etc/passwd with constant creation limit

Question

Rules/Objectives:

1. The program must be executed using ./program-name without shell parameter/arguments.

2. the program-name may not contain any of characters in /etc/passwd, that is acdepstw

3. You may not open any other file, including own's source code, only /etc/passwd that should be read.

4. The program must print the content the /etc/passwd file.

5. Total score of the code equal to number of characters in the code added with constant literal declaration point. Each byte of constant declaration literal equal to +100 to the score, after 3 declaration, each byte adds +200 to the score. So the program should not contain too many constant declaration, but you may use predeclared constants (M_PI for example) or exploit the reflection of the function/variable/class name (function, variable or class names in this case are not considered as constant). Counting example:

   int x = 12;       // counted as 1 byte (12 can fit to 8-bit)
   x += 345;         // counted as 2 bytes (345 can fit to 16-bit)
   #define Y 'e'     // counted as 1 byte ('e')
   #define X Y       // counted as 0 (not considered as constant)
   string s = "abc"; // counted as 3 bytes ("abc")
   :foo              // counted as 3 bytes (:foo) 
                     //  ^ EACH characters in atom (Elixir, etc) 
                     //    or characters in symbol (Ruby, etc) 
                     //    are counted as 1 byte constant
   ''                // counted as 0 (not considered as constant)
   [0xAC, 12, 114]   // counted as 3 bytes (0xAC, 12, 114)
   

Clarification:

things that counted as constant literal:

• numbers, each byte, depends on size
• strings/symbols, each character = 1 byte
• chars, one byte

things that not counted as constant literal:

• class declaration
• function declaration
• variable declaration
• operators, brackets
• predefined symbols
• predefined constants

Answer 1

CJam, 49 characters + 0 bytes constant = 49

W[JCJFJIJBEIDHDHDHJBKGIJDHKCIHKFKFKJJA]Y/f+Afb:cg

It doesn't work in the online interpreter for obvious reasons.

Answer 2

NodeJS - 179 characters + 1 byte constant declaration = 279

#!/usr/bin/env node
fs=function fs(){};fs=require(fs.name);x=function etc(){};y=function passwd(){};z='/';fs.readFile(z+x.name+z+y.name,function(err,data){console.log(''+data);});

Readable version:

#!/usr/bin/env node    
fs = function fs(){};
fs = require(fs.name);
x = function etc(){};
y = function passwd(){};
z = '/'; // 1 declaration
fs.readFile(z+x.name+z+y.name,function(err,data){
  console.log(''+data);
});