Shortest way to get a TypeError

Question

It's simple, simply write the shortest code to raise a TypeError.

In Python you can do:

raise TypeError

However it should be shorter with a code that gives a TypeError without raising it.

Answer 1

for chr1 in range(32, 128):
  for chr2 in range(32, 128):
    for chr3 in range(32, 128):
      code = chr(chr1) + chr(chr2) + chr(chr3)
      try:
        output = exec(code, {})
      except TypeError:
        print(code)
      except:
        pass

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A naive search may result that you cannot trigger a TypeError within 2 characters. You may get a TypeError with 3 characters. All solutions including:

1. Math operator, non-numeric types

• Math operator including +, -, ~
• Non-numeric types including "", (), [], id, {}

+[]
-""
~id

2. Invoke number as function

0()

3. Matrix multiplication between numbers

@ is __matmul__ in python, read more here

0@0

4. Binary operator with float / complex number

~0.
~.0
~0j

5. Iterate over number

Thanks to @Dennis to point out this.

You may iterate some variable by star operator. And () for a tuple may be omitted.

*0,

Answer 2

Python 3, 3 bytes

+''

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Answer 3

Python, 3 bytes

This is self-explanatory. The unary - operator does not take a string argument. This was covered in @tsh's solution above.

-""

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Another one:

~id

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Answer 4

JavaScript (V8), 4 bytes

1.()

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[Output]

.code.tio:1: TypeError: 1 is not a function 1.() ^ TypeError: 1 is not a function at .code.tio:1:3

Answer 5

Japt, 1 byte

Throws TypeError: U.í is not a function

í

Test it (Errors are displayed below the output field)

---

Or, a bit less trivial:

Japt, 2 bytes

Throws TypeError: (U++) is not a function

°(

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