Print "N NE E SE S SW W NW"

Question

This seems almost trivial, but since after some effort I was not able to beat the literal solution in J, I thought it might make a decent challenge (though, to be clear, this is not a J-specific challenge).

Title says it all. You simply need to write a program, or function (taking no arguments) that returns or prints:

N NE E SE S SW W NW

You may use newlines in place of spaces.

A no-argument function returning an array of strings such as

['N', 'NE', 'E', 'SE', 'S', 'SW', 'W', 'NW']

is also acceptable.

The letters may be upper or lower case, but may not be mixed.

Answer 1

Canvas, 12 bytes

＞X½+Ｔ）ＡuS{⁹‟

Try it here!

The string, simply compressed.

Answer 2

bash (24 bytes)

using brace expansion

echo N {N,,S}E S {S,,N}W

is the same length as hard coding

echo N NE E SE S SW W NW

however it becomes more interesting when outputing more points of the compass

echo N NNE NE ENE E ESE SE SSE S SSW SW WSW W WNW NW NNW

brace expansion

echo N {{N,,E}N,,{E,,S}S}E S {{S,,W}S,,{W,,N}N}W

otherwise if order could be changed, (17 bytes), the trick is that without quotes the empy string parameter disappears

echo {N,,S}{W,,E}

Answer 3

Mornington Crescent, 4395 3823 bytes

Take Northern Line to Bank
Take District Line to Parsons Green
Take District Line to Paddington
Take Bakerloo Line to North Wembley
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Northern Line to Bank
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Barbican
Take Circle Line to Bank
Take Circle Line to Aldgate
Take Circle Line to Embankment
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Bakerloo Line to Charing Cross
Take Northern Line to Bank
Take Circle Line to Hammersmith
Take Circle Line to Bayswater
Take Circle Line to Hammersmith
Take Circle Line to Baker Street
Take Circle Line to Bank
Take Circle Line to Embankment
Take Northern Line to Stockwell
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Bank
Take Circle Line to Hammersmith
Take Circle Line to Farringdon
Take Circle Line to Hammersmith
Take Circle Line to Blackfriars
Take Circle Line to Bank
Take Circle Line to Moorgate
Take Northern Line to Waterloo
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Bank
Take Circle Line to Hammersmith
Take Circle Line to Westminster
Take Circle Line to Hammersmith
Take Circle Line to Tower Hill
Take Circle Line to Bank
Take Circle Line to Edgware Road
Take Circle Line to Liverpool Street
Take Central Line to Mile End
Take District Line to Victoria
Take Victoria Line to Seven Sisters
Take Victoria Line to Victoria
Take Circle Line to Victoria
Take District Line to Mile End
Take District Line to Bank
Take Circle Line to Bank
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Charing Cross
Take Northern Line to Bank
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Barbican
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Bayswater
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Baker Street
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Farringdon
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Embankment
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Blackfriars
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Moorgate
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Westminster
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Tower Hill
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Hammersmith
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Aldgate
Take Circle Line to Paddington
Take Circle Line to Paddington
Take Circle Line to Edgware Road
Take Circle Line to Paddington
Take Circle Line to Bank
Take Circle Line to Bank
Take Northern Line to Mornington Crescent

Try it online!

Since it's a bit much to expect you to read all that, let me give a quick overview of my approach. The main idea is to store 3 copies of the characters N,E,S,W at various stations on the Circle line, via Bank - Hammersmith. These characters are constructed from the start of a station name at Charing Cross. Then, construct   from the middle of a well-chosen station name using Mile End and Charing Cross, and store it at Bank so that it can be collected at Hammersmith in the concatenation. Finally, concatenate the characters one by one at Paddington, copying them again via Bank - Hammersmith if they are need to be reused later.

---

I think the current solution is fairly close to optimal with this strategy, at least in terms of number of stations visited: just 2 times I used a station only for transit:

1. to get to Seven Sisters (via Victoria station)
2. and to get back to Mornington Crescent (via Bank).

All other station visits were, if I didn't forget one, either storing/retrieving something useful or (part of) using the stations ability.

As for the line lengths, I've tried to pick the shortest names on Circle Line, but there may be a minor improvement there. It's possible that storing something on District can shave off a few bytes.

Answer 4

PHP, 19 bytes

N NE E SE S SW W NW

Try it online!

Getting this out of the way. Someone will do it eventually.

Answer 5

brainfuck, 142 139 131 119 bytes

++++++++++[>+++>+++++++>++++++++>+++++++++<<<<-]>>>--.<<++.>>.<-.<.>.<.>>+++++.<.<.>>.<<.>>.>---.<<<.>>>.<<<.>>-----.>.

Try it online!

Simply loops 10 times to fill the cells with 30, 70, 80 and 90 then steps backward and forwards and adjusts the cell values to print out the required characters. Not much different from the standard "Hello world!".

Answer 6

Brain-Flak, 204 bytes

((((((((((((((((()()()){}()){}){}())){}{}))<([([][]){}()]{})(([][]){}[])>)<([][]
()())>)[[]]()())<([]()()())>)<((([]())[][]){}[][()])>)<([][()()])>[[]()])<([][((
)()){}])>)((()()())){}{})<((()()()()()){})>)

Try it online!

Answer 7

MarioLANG, 249 221 bytes

+
+
+
+
+
+
+
+
+  ((+++++++++)))<
+>==============="
)++++++++)+++((-[!)--.)++.(.---------.).(.).)++.((.).).(.).++++.(.).(.(+++++++++.))
=================#================================================================.

Try it online!

Answer 8

Deadfish~, 188 183 bytes

-5 thanks to squid

iiissdddc{ddddd}iiiicdddd{iiiii}c{d}ic{dddd}iiicddd{iiii}c{dddd}iiic{iiiii}ic{d}ddddc{dddd}iiic{iiiii}ic{ddddd}dci{iiiii}ciiiic{ddddd}dddddciiiii{iiiii}c{ddddd}dddddcdddd{iiiii}c{i}dc

Try it online!

Answer 9

Excel Formula, 59 57 bytes

The following should be entered as an array formula (Ctrl+Shift+Enter):

=SUBSTITUTE(ADDRESS(1,{14,369,5,499,19,517,23,387},4),1,)

After entering the formula as an array formula, highlight it in the formula bar and evaluate it using F9 to return the result, for example:

Before:

After:

How it works

The ADDRESS function returns a string representing a reference based on two parameters, row and col. The third parameter controls what type of reference is returned, an absolute or relative reference. For example, =ADDRESS(1,2,4) returns "B1".

We can supply an array to ADDRESS and use it as an array formula to return multiple results, for example =ADDRESS(1,{1,2,3},4) returns "A1","B1","C1".

Therefore, in my answer, the array supplied to ADDRESS are just the column numbers relating to the required compass points, e.g. Column 14 is column N, Column 369 is column NE.

However, we are not finished here since all the returned references have the row included, for example, N1, NE1. Therefore, we simply use SUBSTITUTE to remove the 1 from all references.

Answer 10

Triangularity, 71 bytes

..... .....
...."W"....
..."W N"...
.." SW "+..
." SE S"++.
"N NE E"+  

Try it online!

There are two spaces on the last line to hit the byte count Triangularity requires.

Answer 11

Charcoal, 14 bytes

”{⊟“�_Ｚn↖⦄ＲüΦ≦

Try it online! Link is to verbose version of code... which is just the string to be printed, as the auto-deverbosifier takes care of the string compression.

Printing the string uncompressed takes 19 bytes, since Charcoal prints printable ASCII literally. The best algorithmic answer I could come up with unfortunately takes 20 bytes:

Ｅ⁸ΦSNWE›³﹪⁻﹪⁺⁵×⁶μχι⁸

Try it online! Outputs using array format (would cost two bytes to join the elements on spaces). Works by noticing that the letters of the string SNWE are used only when the current outer index equals or is 1 away (modulo 8) in either direction from the corresponding element of the list of indices 4,0,6,2.

Answer 12

brainfuck, 117 bytes

+++++[>++++++>+>+++>>++++>+++++<<<<<<-]>++[>++>++>+>++>++[<]>-]>>-.>.<.<.>>.<<.>>.>-.<<<.>>.>.<.>.>--.<<.>>.<<.<.>>>.

Try it online!

This code will first create the characters "EN SW" into the memory and then move back and forth to print them. The space is in the middle, because it is printed most often. N and S and W and E never appear together so they are on opposite sides of the memory. For optimization some of the final decrements happen during the output phase.

Answer 13

Python 2, 62 61 58 53 bytes

i=8
while i:print'NESESWNW'[~i+(i==4):][:1+i%2],;i-=1

Try it online!

Not great, but at least not a plain print..

Answer 14

Jelly,  16  15 bytes

“¤œỵpq⁵’ṃ“NESW 

A full program printing the text

Try it online!

---

16...

“¥Þ¡¦¢¬£æ‘ṃ“¡ɱ⁻»

A niladic Link which yields a list of lists of (lowercase) characters.

Try it online!

---

Alternative 15 as a niladic Link which yields a list of (lowercase) characters (with spaces): “¡XÇŀqỵÑ’ṃ“¡⁴ṁ».

Answer 15

Commodore BASIC (TheC64Mini, C64, C128, VIC-20 etc.) 28 Tokenized BASIC bytes used

 0 PRINT"N NE E SE S SW W NW

In Commodore BASIC, you do not require the closing quotation mark on PRINT or LET statements as the interpreter will auto-close it, this saves one BASIC token.

Alternatively, one may simply use direct mode as follows:

Commodore BASIC 23 PETSCII characters (+ RETURN to execute)

?"N NE E SE S SW W NW

I'm not sure how to count the number of bytes used in this instance as according to the interpreter ? and PRINT use the same number of bytes, and there is no program stored in memory.

Answer 16

Deadfish~, 138 bytes

{{i}i}c{{d}}cs{i}c{d}ic{{d}}iisicsic{{d}}iisicisddddddc{d}ddddc{{d}}iisicisddddddc{{iiii}}sicisddddddciiiic{{d}d}icisddc{{d}d}ics{i}c{i}dc

Try it online!

So, outputting in lower-case with newlines is better than default (upper-case with spaces).

This code was generated by my optimizer, written in C++ (thanks to squid for another optimization idea!):

#include <iostream>
#include <string>
#include <queue>
#include <vector>


int eval(const std::string& actions, int result)
{
    int mult = 1;

    for (int i = 0; i < (int)actions.length(); ++i)
    {
        switch (actions[i])
        {
        case 's':
            result *= result;
            if (result == 256)
                result = 0;
            break;

        case '{':
            mult *= 10;
            break;

        case '}':
            mult /= 10;
            break;

        case 'd':
            if (result > 256 && result - mult <= 256)
                result = (result - mult) % 256;
            else
                result -= mult;
            break;

        case 'i':
            if (result < 256 && result + mult >= 256)
                result = (result + mult) % 256;
            else
                result += mult;
            break;
        }
    }

    return result;
}

struct worse
{
    bool operator()(const std::string& a1, const std::string& a2)
    {
        return a1.length() > a2.length();
    }
};

std::string BestStr(int accumulator, int target)
{
    std::priority_queue<std::string, std::vector<std::string>, worse> actions;
    actions.push(std::string(""));
    while (true)
    {
        std::string a = actions.top();
        int new_acc = eval(a, accumulator);
        if (new_acc == target)
            return a + "c";

        actions.pop();

        int last_braces = 0;
        int i = a.length() - 1;
        while (i >= 0 && a[i] == '}' && last_braces < 2)
        {
            ++last_braces;
            --i;
        }
        bool is_last_i = (i >= 0 && a[i] == 'i');
        bool is_last_d = (i >= 0 && a[i] == 'd');
        bool may_add_braces = (i < 0 || a[i] == 's');
        bool may_add_c = (new_acc > 1 && new_acc < 30);

        if (may_add_c)
        {
            actions.push(a + "s");
        }
        if (may_add_braces)
        {
            actions.push(a + "{{}}");
            actions.push(a + "{}");
        }
        for (int braces_back = 0; braces_back <= last_braces; ++braces_back)
        {
            for (int c = 'd'; c <= 'i'; c += 'i' - 'd')
            {
                if ((!is_last_i || c == 'i') &&
                    (!is_last_d || c == 'd') ||
                    braces_back == 0)
                {
                    std::string new_actions = a;
                    new_actions.insert(new_actions.length() - braces_back, 1, (char)c);
                    actions.push(new_actions);
                }
            }
        }
    }
}

std::string DeadfishConvert(std::string s)
{
    std::string result;
    int accumulator = 0;

    for (int c: s)
    {
        result += BestStr(accumulator, c);
        accumulator = c;
    }
    return result;
}

int main()
{
    std::string s1 = DeadfishConvert("N NE E SE S SW W NW");
    std::cout << s1 << '\n';
    std::cout << s1.length() << '\n' << '\n';
    std::string s2 = DeadfishConvert("n ne e se s sw w nw");
    std::cout << s2 << '\n';
    std::cout << s2.length() << '\n' << '\n';
    std::string s3 = DeadfishConvert("N\nNE\nE\nSE\nS\nSW\nW\nNW");
    std::cout << s3 << '\n';
    std::cout << s3.length() << '\n' << '\n';
    std::string s4 = DeadfishConvert("n\nne\ne\nse\ns\nsw\nw\nnw");
    std::cout << s4 << '\n';
    std::cout << s4.length() << '\n' << '\n';
}

Answer 17

Japt, 16 bytes

Returns an array of lowercase strings. The compressed string was 18 bytes but using a as the delimiter instead and then splitting on that worked out shorter.

`nÂà!Z°°nw`qa 

Try it - footer formats the output.

Answer 18

K (ngn/k), 23 22 bytes

-1 byte thanks to ngn!

"WNES"@5\7108085518230

Try it online!

J, 34 30 bytes

echo(#:3510)<;.1'NNEESESSWWNW'

Try it online!

Answer 19

Batch File, 19 bytes

The question never stated that you had to output N NE E SE S SW W NW and nothing else, nor that it couldn't exit due to error after doing so this code only throws an error but does not exit due to it.

N NE E SE S SW W NW

Output

>N NE E SE S SW W NW
'N' is not recognized as an internal or external command,
operable program or batch file.

---

Batch File, 25 bytes

Only N NE E SE S SW W NW output with no errors or crashes.

@echo N NE E SE S SW W NW

Answer 20

Python2, 59 bytes

''.join(' SEWN'[0xe0619042210504>>i*3&7]for i in range(19))

The magic number is the joined three-bit indexes into the character string, reverse order so we can start iterating at the LSB.

---

I spent a while trying to shrink the magic number, but repeating the character string via multiply to allow for extra indexes doesn't work out due to needing to encode for space - best I got for overlapping indexes in the lookup added more characters to the string than digits removed from the magic number (including a couple of unfortunate don't-cares in the middle):

''.join('WN S ES W xxE '[0x423659711>>i*2&15]for i in range(19))

Answer 21

05AB1E, 14 bytes

.•2Àβ‡yÞJŒ¾oÒ8

Try it online!

This prints out the string except lowercase.

Answer 22

Brachylog, 19 bytes

"NNEESESSWWNW"ḍ₄ḍᵐc

Try it online!

Outputs as a list. ḍ₄ḍᵐc saves two bytes over writing out seven spaces and making the entire predicate a string literal, so at least it ties PHP...

"NNEESESSWWNW"         The string "NNEESESSWWNW"
              ḍ₄       split into quarters
                 ᵐ     with each quarter
                ḍ      split in half
                  c    and concatenated
                       is the output.

I tried to be clever with 3⟦{;"NESW"↺₍h₂a₀ᶠ}ᵐc, but it couldn't get SE or NW right, and is a byte longer anyhow.

Answer 23

MathGolf, 20 17 bytes

ÿnesw▒∙╫m+mÉîÄ╪^─

-3 bytes thanks to @maxb.

Try it online.

Explanation:

ÿnesw      # Push 4-char string "nesw"
           #  STACK: "nesw"
     ▒     # Split to a list of characters
           #  STACK: ["n","e","s","w"]
      ∙    # Triplicate it
           #  STACK: ["n","e","s","w"],["n","e","s","w"],["n","e","s","w"]
╫          # Rotate the top one once towards the left
           #  STACK: ["n","e","s","w"],["n","e","s","w"],["e","s","w","n"]
 m+        # Append the top two together
           #  STACK: ["n","e","s","w"],["en","se","ws","nw"]
   m       # Map the strings in the top list to:
    ÉîÄ╪   #  Rotate the string the 1-based index amount of times towards the right
           #   STACK: ["n","e","s","w"],["ne","se","sw","nw"]
^          # Zip; creating pairs with the top two lists
           #  STACK: [["n","ne"],["e","se"],["s","sw"],["w","nw"]]
 ─         # Flatten this list
           #  STACK: ["n","ne","e","se","s","sw","w","nw"]
           # (after which the entire stack is output implicitly as result)

Answer 24

Whitespace, 151 bytes

[S S S T    T   N
_Push_3_W][S S T    T   T   S N
_Push_-6_N][S S T   T   T   S T S S N
_Push_-52_space][S S S T    T   N
_Push_3_W][S T  S S T   N
_Copy_0-based_1st_(space)][S S S T  T   N
_Push_3_W][S S T    T   N
_Push_-1_S][S T S S T   S N
_Copy_0-based_2nd_(space)][S S T    T   N
_Push_-1_S][S T S S T   N
_Copy_0-based_1st_(space)][S S T    T   T   T   T   N
_Push_-15_E][S S T  T   N
_Push_-1_S][S T S S T   S N
_Copy_0-based_2nd_(space)][S T  S S T   S N
_Copy_0-based_2nd_(E)][S T  S S T   N
_Copy_0-based_1st_(space)][S T  S S T   N
_Copy_0-based_1st_(E)][S S T    T   T   S N
_Push_-6_N][S T S S T   S N
_Copy_0-based_2nd_(space)][S S T    T   T   S N
_Push_-6_N][N
S S N
_Create_Label_LOOP][S S S T S T S T S S N
_Push_84][T S S S _Add][T   N
S S _Print_as_character][N
S N
N
_Jump_to_Label_LOOP]

Letters S (space), T (tab), and N (new-line) added as highlighting only.
[..._some_action] added as explanation only.

Try it online (with raw spaces, tabs, and new-lines only).

Explanation:

1. Push the unicode values minus constant 84 for the characters "WN W WS S ES E EN N" to the stack (note that the string is pushed in reversed). In addition, I use a few copies of previously pushed values to save bytes where possible.
2. Then start an infinite loop, which does the following:
   1. Add the constant 84 to the current unicode value
   2. Print it as character to STDOUT

The constant 84 is generated by this Java program which I wrote for another challenge I answered in Whitespace.

Answer 25

CSS, 42 39 bytes

(thanks to a stone arachnid for the revised version)

body:after{content:"N NE E SE S SW W NW"

Answer 26

Seed, 6014 bytes

27 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Generates following befunge program:

"WN W WS S ES E EN N">:#,_@

Answer 27

Hodor, 177 bytes

hodor.hod("HoOodoOorhodor  HoOodoOorhodor HooodorrHodor  HooodorrHodor  HODOR?!? HooodorrHodor  HODOR?!?  HODOR?!? Hooodorrhodor  Hooodorrhodor  HoOodoOorhodor Hooodorrhodor ");

Try it online!

Answer 28

Assembly (x86, Linux), 68 bytes

$ od -x a
0000000 457f 464c 0001 0000 0000 0000 0000 0500
0000020 0002 0003 001b 0500 001b 0500 0004 0000
0000040 13b2 31b9 0000 cd05 2580 0020 0001 cd40
0000060 4e80 4e20 2045 2045 4553 5320 5320 2057
0000100 2057 574e
0000104
$ ./a
N NE E SE S SW W NW$

Source:

BITS 32
org 0x05000000
db 127,"ELF"
dd 1,0
dd $$
dw 2,3
dd 0x0500001B,0x0500001B
dd 4
mov dl,19
mov ecx,m
int 128
db 37
dw 32,1
inc eax
int 0x80
m db 'N NE E SE S SW W NW'

Code mostly taken from Shortest ELF for "Hello world\n"?

Answer 29

Jelly, 16 bytes

“æṖØq’ḃ⁴ḃ4ị“NESW

Try it online!

With footer to print separated by space

A niladic link which returns a list of strings. 2 bytes shorter (and arguably more interesting) than the compressed string in Jelly.

Answer 30

Java, 24 bytes

Quick, gotta do it before anyone else

v->"N NE E SE S SW W NW"

Null is equivalent to no input
TIO

Answer 31

C# (Visual C# Interactive Compiler), 24 bytes

_=>"N NE E SE S SW W NW"

Try it online!

Answer 32

PowerShell, 21 bytes

'N NE E SE S SW W NW'

Try it online!

Answer 33

R, 26 bytes

cat('N NE E SE S SW W NW')

Try it online!

Answer 34

As input to Commodore BASIC, you can get it even shorter: (23 bytes)

0 ?"N NE E SE S SW W NW

? is shorthand for PRINT.

Answer 35

><>, 25 24 bytes

This is a pretty simple answer. Push the string in reverse, then print the stack. Exits with an error due to stack underflow.

"WN W WS S ES E EN N">o<

Try it online!

Answer 36

Assembly (MIPS, SPIM), 71 70 bytes

.data
t:.ascii"N NE E SE S SW W NW"
.text
main:li $2,4
la $4,t
syscall

Try it online!

I haven't done anything with MIPS in a while, so if there's a shorter way please tell me!

Edit: used an ascii and not an asciiz string

Answer 37

k, 23 bytes

1_,/'$,/``N`S,/:\:``E`W

Answer 38

Keg, 19 bytes

Simply hard-coding the answer.

N NE E SE S SW W NW

Answer 39

SQL, 28 26 bytes

On behalf of BradC:

PRINT'N NE E SE S SW W NW'

SELECT 'N NE E SE S SW W NW'

Answer 40

Stax, 16 bytes

Ä\8←ΘåÑ¥▒Nx╚ø┼Çt

Run and debug it

Answer 41

Haskell, 21 bytes

I don't think it gets any shorter than this in Haskell.

"N NE E SE S SW W NW"

Try it online!

Answer 42

Ruby, 22 bytes

p'N NE E SE S SW W NW'

Try it online!

Answer 43

One more Python example:

for i in range(8):print''.join(c*((i+m)%8<3)for c,m in zip('NSEW',(1,5,7,3))),

I tried to use no cryptic operations, just normal math + boolean logic. Try it

Answer 44

Stax, 16 bytes

Æ+góïr!½*ÄJ╓╨°╩Æ

Run and debug it

Answer 45

Assembly (x86, GCC), 151 bytes

$ cat foo.s
.global _start
.text
_start:mov $1,%rax
mov $1,%rdi
mov $m,%rsi
mov $19,%rdx
syscall
mov $60,%rax
xor %rdi,%rdi
syscall
m:.ascii "N NE E SE S SW W NW"
$ gcc -c foo.s && ld foo.o && ./a.out
N NE E SE S SW W NW$

Answer 46

DC, 79 bytes

78sn7Dss69se87swAsblblwlnlblwlblwlslblslblelslblelblelnlblnPPPPPPPPPPPPPPPPPPPP

It loads the characters NESW and newline into registers, then loads them onto the stack and prints them all

Answer 47

Underload, 22 bytes

(N NE E SE S SW W NW)S

Pretty self explanatory

Try it online!

Answer 48

Befunge-93, 45 bytes

"WN W":" "\"S":" "\" ES E":" "\"N":" "\>:#,_@

Try it online!