Split into three!

Question

Given a string, you've to split it into groups of three characters (by padding _ at the end).

Related, but still it's different.

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Sample I/O:

• 'abcde' -> 'abc', 'de_'

• '1234' -> '123', '4__'

• '' -> [] or falsey value

• 'Three spree!' -> 'Thr', 'ee ', 'spr', 'ee!'

• 6 MB string

This is a code-golf, so fewest bytes will win!

Edit: Finally, output is unrestricted.

Answer 1

05AB1E, 9 8 bytes

…___«3ô¨

Try it online! or as a Test Suite

Explanation

…___«      # append "___" to input
     3ô    # split into groups of 3
       ¨   # discard the last group

Answer 2

Python 3, 58 47 34 bytes

I'm sure someone else can do better Someone else did better. Thanks Jo King for -11 -24 bytes!

Output is unrestricted, welcome to tuple hell. Returns empty list (falsy) on empty input

lambda x:[*zip(*[iter(x+"__")]*3)]

TIO

Answer 3

JavaScript, 25 bytes

s=>`${s}__`.match(/.../g)

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Answer 4

Perl 5, 16 15 bytes

"@_\__"=~/.../g

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Answer 5

APL+WIN 36 24 22 bytes

12 bytes saved as a result of output now being de-restricted and using the code in @Adám's first comment modified to work in APL+WIN and a further 2 with his second comment. Thanks.

(⌈(↑⍴s)÷3)3⍴(s←⎕),'__'

Prompts for input of the string and outputs the result as a nx3 array

Try it online! Courtesy of Dyalog Classic

Answer 6

JavaScript, 51 50 48 27 25

b=>(b+"__").match(/.../g)

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Answer 7

Perl 6, 19 bytes

{$_~"__"~~m:g/.../}

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Pads the string by two underscores then splits the string into chunks of three characters. Returns as an array of Match objects.

Answer 8

Japt, 8 bytes

+1 byte to special case the empty string. Can save 2 if we can choose our padding character.

©ò3 ú'_3

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©ò3 ú'_3     :Implicit input of string
©            :Logical AND with
 ò3          :Split into chunks of 3
    ú'_3     :Right pad each with "_" to length 3

Answer 9

Stax, 7 bytes

é☻εgP▀╪

Run and debug it

For an empty string input, the result is an empty array, which is a falsey value in stax.

Answer 10

CJam, 11 bytes

q'_3*+3/);p

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For empty input this gives an empty string, which is falsy.

How it works

q     e# Read input as a string
'_    e# Push char '_'
3*    e# String formed by that char repeated 3 times
+     e# Concatenate to input string
3/    e# Split in groups of 3, the last of which may be shorter. Gives array of strings
);    e# Detach last string from the array and delete it
p     e# Print string representation of the array

Answer 11

Retina 0.8.2, 10 bytes

$
__
!`...

Try it online! Link includes test cases. Explanation:

$
__

Append two _s, in case the last group needs to be padded.

!`...

Match as many groups of three as possible, outputting the matches themselves rather than the count. (In Retina 1 this would be L instead of !.)

Answer 12

Wolfram Language (Mathematica), 28 21 bytes

-7: No longer requires falsy (False) value on empty input

Partition[#,3,1,1,_]&

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Takes a list of characters as input. Returns a list of 3-tuples of characters padded with Blanks (_).

---

34 27 bytes

StringPartition[#<>"__",3]&

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String input, list of strings output

Answer 13

C (gcc), 67 bytes

i;f(char*_){for(;*_;puts(""))for(i=3;i--;)putchar(*_?*_++:95);_=0;}

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Always returns a falsey value (0).

Answer 14

C (clang), 128 126 94 67 bytes

67 bytes thanks to @ceilingcat

f(char*k){for(;*k;k++)printf("%c%c%c\n",*k,*++k?*k:95,*++k?*k:95);}

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Answer 15

Jelly, 9 bytes

s3o€“___”

A monadic Link accepting a list of characters which yields a list of lists of characters (an empty input yields empty output).

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How?

s3o€“___” - Link: list of characters
s3        - split into chunks of three
   €      - for each chunk:
  o       -   OR (vectorises):
    “___” -     list of characters = ['_', '_', '_']

Notes:
The € is only necessary to handle the edge case of an empty input.
A full program can drop a trailing ”, but here we can't do that as the printing behaviour of a full program smashes everything together.

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Equivalent 9:

o3ÐƤ“___”

Try it

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Alternative 9:

;“___”s3Ṗ

Try it

Answer 16

J, 16 bytes

[:}:_3]\'___',~]

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K (oK), 19 17 bytes

-2 bytes thanks to ngn!

{-1_0N 3#x,"___"}

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Answer 17

Java 10, 116 113 bytes

s->{s+="__";int l=s.length()/3,i=l;var r=new String[l];for(;i-->0;)r[i]=s.substring(i*3,i*3+3);return l<1?0>1:r;}

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Or 104 101 bytes if an empty array instead of false is allowed as output..

s->{s+="__";int l=s.length()/3;var r=new String[l];for(;l-->0;)r[l]=s.substring(l*3,l*3+3);return r;}

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Explanation:

s->{                             // Method with String as both parameter and return-type
  s+="__";                       //  Append two "_" to the input-String
  int l=s.length()/3;            //  Get the length, integer-divided by 3
  var r=new String[l];           //  Create a string-array with that many parts
  for(;l-->0;)                   //  Loop `l` in the range (l, 0]:
    r[l]=                        //   Set the `l`'th value of the array to:
         s.substring(l*3,l*3+3); //   Get the substring of size 3 from index `l*3` from `s`
  return r;}                     //  Return the array

Answer 18

Ruby, 73 42 bytes

a=gets
a.length!=0?a.scan(/.{1,3}/).map{|s|(s+'_'*3)[0,3]}:'falsey value'

Edit: As falsey value looks like it's not required:

gets.scan(/.{1,3}/).map{|s|(s+'_'*3)[0,3]}

Answer 19

C# (Visual C# Interactive Compiler), 74 bytes

Just append two underscores '_' at the end of the input to make sure they get printed if the length of the input isn't a factor of 3.

s=>Enumerable.Range(0,(s.Length+2)/3).Select(i=>(s+"__").Substring(i*3,3))

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Answer 20

Kotlin, 34 bytes

{"${it}__".chunked(3).dropLast(1)}

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Answer 21

C (gcc), 55 bytes

i;f(char*s){for(;i%4|*s;)putchar(++i%4?*s?*s++:95:10);}

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Answer 22

Bash, 90 bytes

This uses Bash features rather than a combination of more traditional Bourne shell plus *nix commands (which one version I created ended up at 205 bytes). I cheated by using the dodge of adding two _ characters to the string.

c=;read a;a=${a}__;while (($(echo ${#a})>2));do b=${a:0:3};c=$c\ $b;a=${a#$b};done;echo $c

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Answer 23

PowerShell, 58 35 bytes

$args-split'(...)'-ne''|% *ht 3 '_'

-23 bytes thanks to mazzy.

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Answer 24

GNU sed, 27 bytes

s:$:__:
s:...:& :g
s: _*$::

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It gets a bit tricky regarding the empty string input, since sed has no meaning of a falsy value. So to deal with this, I provide you with two possible interpretations of the rules to validate my submission:

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A. You essentially provide nothing as input, not even a trailing newline (as it is the case with all the examples, including that 6 Mb file).

Usage:

echo -n ""|sed -f script

Output: nothing is printed, because sed doesn't even run the script without input.

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B. One could consider as falsy value for sed to be an unique string, i.e., returned only when the input is an empty string.

Usage:

echo ""|sed -f script

Output:

__

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I prefer the first interpretation so much more, as I believe it to be the closest to the intended rule, but the last one helps if you run the script using that TIO link.

Answer 25

JavaScript (Babel Node), 45 bytes

_=>_.match(/.{1,3}/g).map(a=>a.padEnd(3,`_`))

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Answer 26

Jelly, 10 bytes

s3;€⁾__ḣ€3

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It feels like an 8 or 9 should be possible, but haven’t found one yet.

Answer 27

Pyth, 10 9 bytes

Pc+z*3\_3

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-1 from u_ndefined.

Is it ok if it throws an error on empty input? (does that count as falsey)

Answer 28

Attache, 34 23 bytes

PadRight&"_"&3=>@Chop&3

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Explanation (outdated)

{On[#_-1,PadRight&"_"&3,_]}@Chop&3
                           @Chop&3    chop the input string into groups of 3s
{On[#_-1               ,_]}           on the last group
        ,PadRight                         pad it
                     &3                   to length three
                 &"_"                     with underscores

Answer 29

Charcoal, 10 bytes

Ｅ⪪Ｓ³…⁺ι__³

Try it online! Link is to verbose version of code. Explanation:

  Ｓ         Input string
 ⪪ ³        Split into groups of up to 3 characters
Ｅ           Map over each group
      ι     Current group
     ⁺      Concatenated with
       __   Literal `__`
    …    ³  Moulded to length 3
            Each group implicitly printed on its own line

Answer 30

Scala, 31 bytes

(s+"___").grouped(3).toSeq.init

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Explanation

(s+"___")       // add "___"
  .grouped(3)   // make groups of 3
  .toSeq        // change to Seq
  .init         // take all but last

Answer 31

Befunge-93, 30 29 bytes

~:1+%,~:1+!"`"*+,~:1+!"`"*+,,

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Outputs nothing for an empty input, otherwise outputs strings of length 3 separated by NUL characters.

Explanation:

~                               Push character of input to stack
 :1+                            Duplicate input and add 1
    %                           Modulo top 2 values of stack and push result
                                If input was -1 (end of stream), calculate -1%0 -> halt
                                Otherwise calculate input%(input+1) -> input
     ,                          Pop and output character
      ~                         Push character of input to stack
       :1+!                     Duplicate input, add 1 and perform logical NOT
           "`"*                 Multiply by 96 (ASCII code for '`')
                                This returns 96 or 0 depending on the result of the NOT
               +                Add the top 2 values from the stack and push the result
                                If the input was -1 (end of stream), pushes -1+96=95, or the ASCII code for '_'
                                Otherwise pushes input+0
                ,               Pop and output character
                 ~:1+!"`"*+,    Same block again to handle the third character
                            ,   Output a NUL character (stack is empty, so popping from stack just returns 0)

The instruction pointer wraps around at the end, looping the entire line.

Answer 32

Haskell, 62 61 59 bytes

z(a:b:c:d)=[a,b,c]:z d
f s=takeWhile(/="___")$z$s++cycle"_"

Infinite lists and strings!

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Answer 33

Rust, 93 bytes

Works for ASCII input strings. Empties the input string and returns a Vec<String>.

|mut s:String|{s+="__";let mut v=vec![];while s.len()>2{let t=s.split_off(3);v.push(s);s=t}v}

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Answer 34

GoLang, 84 bytes

func(x string)[]string{return regexp.MustCompile("...").FindAllString(x+"__",-1)}(s)

Try it !

Answer 35

SNOBOL4 (CSNOBOL4), 93 bytes

	S =INPUT
	S =S DUPL('_',REMDR(3 - REMDR(SIZE(S),3),3))
R	S LEN(3) . OUTPUT REM . S	:S(R)
END

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SNOBOL has a size limit on the length of its input (1023 bytes).

Answer 36

Julia 1.0, 40 bytes

s->[(s*"__")[i:i+3] for i=1:3:length(s)]

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Answer 37

APL(NARS), 30 chars, 60 bytes

{(3/⍳3÷⍨≢v)⊂v←⍵,'_'⍴⍨3∣3-3∣≢⍵}

test:

  f←{(3/⍳3÷⍨≢v)⊂v←⍵,'_'⍴⍨3∣3-3∣≢⍵}
  ⎕fmt f 'abcde'
┌2────────────┐
│┌3───┐ ┌3───┐│
││ abc│ │ de_││
│└────┘ └────┘2
└∊────────────┘
  ⎕fmt f '1234'
┌2────────────┐
│┌3───┐ ┌3───┐│
││ 123│ │ 4__││
│└────┘ └────┘2
└∊────────────┘
  ⎕fmt f ''
┌0──┐
│┌0┐│
││ ││
│└¯┘2
└∊──┘
  ⎕fmt f 'Three spree!'
┌4──────────────────────────┐
│┌3───┐ ┌3───┐ ┌3───┐ ┌3───┐│
││ Thr│ │ ee │ │ spr│ │ ee!││
│└────┘ └────┘ └────┘ └────┘2
└∊──────────────────────────┘