Decimal Digit Truncating

Question

Input:

A decimal

Output:

The input truncated

How to truncate them?

The integer part of the input will remain the same. The decimal part of the input will be truncated based on the lowest digit in consecutive order. The two step-by-step examples below should clarify what I mean by that:

Example 1: Input: 17.46940822

Step 1: Leave the integer part unchanged: 17
Step 2: Look at the first decimal digit, and truncate it to that many decimal digits: 4 → .4694
Step 3: Look at the next decimal digit. If it's lower, adjust the truncation accordingly. If not, continue to the next decimal digit: 6 → remains .4694
Step 3 again: 9 → remains .4694
Step 3 again: 4 → remains .4694

So the output will be: 17.4694.

Example 2: Input: 10.4521084

Step 1: Leave the integer part unchanged: 10
Step 2: Look at the first decimal digit, and truncate it to that many decimal digits: 4 → .4521
Step 3: Look at the next decimal digit. If it's lower, adjust the truncation accordingly. If not, continue to the next decimal digit: 5 → remains .4521
Step 3 again: 2 → truncation adjusted to: .45

So the output will be: 10.45

Challenge rules:

• You are allowed to take the input as decimal, string, list/array/stream of characters, etc. (Same applies to the output, although I doubt there are a lot of languages that have the proper truncation while remain working with decimal values.)
  You are also allowed to use a comma , instead of a dot . (perhaps useful for regex-based solution/languages).
• If the decimal part is not long enough for the truncation, you are optionally allowed to add trailing zeros. I.e. 123.4 can be both 123.4 or 123.4000
• If you have to truncate to 0 decimal digits we omit the decimal digits. The dot/comma may remain optionally if you use strings. I.e. 847.3072 → 847 (or 847.)
• You can assume the input will always contain at least one decimal digit, so 123 won't be an input, but 123.0 can be an input.

General rules:

• This is code-golf, so shortest answer in bytes wins.
  Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.
• Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.
• Default Loopholes are forbidden.
• If possible, please add a link with a test for your code (i.e. TIO).
• Also, adding an explanation for your answer is highly recommended.

Test cases:

Input:          Output:

17.46940822     17.4694
10.4521084      10.45
123.4           123.4000 (or 123.4)
-847.3072       -847 (or -847.)
123.0           123 (or 123.)
98.76543210     98.7654
0.3165          0.3
-0.1365         -0.1
82937.82937     82937.82
-0.1010101      -0.1
-1.0101010      -1 (or -1.)
28.684297       28.68
13.35           13.350 (or 13.35)
0.99999999999   0.999999999
28.321          28.32
0.56462         0.5646

Answer 1

05AB1E, 18 bytes

2 bytes extra due to a bug with £ not handling 0 correctly.

'.¡`DvÐgsNè-F¨]'.ý

Try it online! or as a Test Suite

Explanation

    '.¡                 # split input on "."
       `                # push int and decimals separately to stack
        D               # duplicate decimal digits
         v              # for each
          Ð             # triplicate the current decimal digits
           g            # get the length
            sNè         # get the Nth digit
               -        # subtract from the total length
                F¨]     # drop that many digits from the end
                        # end loop
                   '.ý  # join on "."

Answer 2

Python 2, 103 101 98 94 93 87 bytes

a,b=input().split('.');i,w=0,len(b)
while w>i:w=min(int(b[i]),w);i+=1
print a+'.'+b[:w]

Try it online!

---

Saved:

• -2 bytes, thanks to Kevin Cruijssen
• -3 bytes, thanks to Vedant Kandoi
• -4 bytes, thanks to Lynn

Answer 3

JavaScript (Node.js), 58 bytes

f=(s,p=1/0,q=1,c=s[q])=>c?f(s.slice(0,p-~c),++c?p:q,q+1):s

Try it online!

Answer 4

Charcoal, 28 bytes

≔⪪Ｓ.θＷ⊟ＥθΦκ‹ΣμＬκ⊞θ…⊟θＩ§ι⁰⪫θ.

Try it online! Link is to verbose version of code. Explanation:

≔⪪Ｓ.θ

Split the input on ..

Ｗ⊟ＥθΦκ‹ΣμＬκ

Filter each part on those digits that are less than the string's length. Then take the last result. (This saves 1 byte over filtering on just the decimals.) Loop until that is empty.

⊞θ…⊟θＩ§ι⁰

Take the first filtered digit and truncate the decimals to that length.

⪫θ.

Join the parts back together and implicitly print.

Answer 5

C (gcc), 84, 78 bytes

Takes input as a pointer to a string buffer, outputs by modification. Note that providing a pointer to a buffer that is too small (intPartLen + 1 + 9 > bufSize) can cause SEGFAULT.

If assuming the size of the buffer to be sufficient is not allowed, +7 to the score.

l,M;f(char*F){F=strchr(F,46);for(l=47,M=57;*++F&&++l<M;*F<M?M=*F:0);F[M-l]=0;}

Try it online!

Degolf

l,M;f(char*F){
    F=strchr(F,46); // Find the pointer to the period.
    for(l=47,M=57;  // Initialize variables (48='0', 57='9')
            *++F&&++l<M;  // Check for null terminator, and that we're not
                          // going through too many decimals
            *F<M?M=*F:0); // Keep smaller of M and the char pointed to by F.
        F[M-l]=0; // Explained below.
}

At the end of the loop, F is a pointer to the nth decimal after the decimal point (ptr). M is the smallest digit observed as its ASCII value. l is '0'+n-1 (or 47+n). Thus:

F[M-l] == *(F + M - l)
F[M-l] == *(ptr + n + M - '0' - n + 1)
F[M-l] == *(ptr + M - '0' + 1)

Which gives us a pointer to the first character to truncate; replacing this character with a \0 results in the truncation of the remaining digits for most intents and purposes. This is also where the SEGFAULT happens; for example, if the input is 123.4, the smallest digit is 4, and the pointer will point to the character * in 123.4\0??*.

Answer 6

Ruby -pl, 48 bytes

c=i=j=$_=~/,/;$_=$_[0,c.to_i-~j]while c=$_[i+=1]

Try it online!

Uses a decimal comma instead of a dot.

Answer 7

PHP, 92 bytes

several solutions, same length:

# any PHP:
for($n=$argn,$t=9;~$d=$n[$i+++$p=1+strpos($n,46)];$n=substr($n,0,$p+$t))$t<$d||$t=$d;echo$n;
for($t=9;$i<$t&&~$d=$n[$i+++$p=1+strpos($n=$argn,46)];)$t<$d||$t=$d;echo substr($n,0,$p+$t);
for($t=9;$i<$t&&~$d=$n[++$i+$p=strpos($n=$argn,46)];)$t<$d||$t=$d;echo substr($n,0,$p+$t+1);

# PHP 7:
for($t=9;~$d=($n=&$argn)[$i+++$p=1+strpos($n,46)];$n=substr($n,0,$p+$t))$t<$d||$t=$d;echo$n;
for($n=$argn;~$d=$n[$i+++$p=1+strpos($n,46)];$n=substr($n,0,$p+$t))($t??9)<$d||$t=$d;echo$n;

Run as pipe with -nR or try (most of) them online.

Answer 8

JavaScript, 58 bytes

Input and output as a string, using a comma as the decimal separator.

s=>s.replace(/,.+/,g=d=>d[++n]?g(d.slice(0,-~d[n])):d,n=0)

Try it online

Answer 9

JavaScript (Node.js), 78 68 bytes

-10 bytes from @tsh

a=>eval('for([x,y]=a.split`.`,i=0;c=y[i++];y=y.slice(0,c));x+`.`+y')

Try it online!

Answer 10

Perl 6 -p, 57 41 bytes

$!=m/\./.to;.=substr(0,$!+$/)while m:c/./

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Explanation

$!=m/\./.to;       # Store position of decimal point in $!
.=substr(0,$!+$/)  # Truncate string to length $!+$/
while m:c/./       # while there's a match for the next digit

Answer 11

Python 3, 77 bytes

g,h=input().split(".")
for i in h:h=h[:int(i)]if i in h else h
print(g+"."+h)

Try it online!

Somehow, despite slicing past the end of a string and modifying while iterating on that same string, the interpreter doesn't complain.

This answer has a similar structure to the other Python one, but uses a different method to find where to truncate and works in newer versions of Python.

Answer 12

Clean, 115 bytes

import StdEnv,Text
$s#[i,d:_]=split['.']s
=i++['.':iter 9(\p=hd([take n\\n<-map digitToInt p|n<length p]++[id])p)d]

Try it online!

Defines the function $ :: [Char] -> [Char]. Link includes test suite.