Display numbers lacking 2's

Question

Display numbers from one to one-hundred (in increasing order), but number 2 shouldn’t appear anywhere in the sequence. So, for example, the numbers two (2) or twenty-three (23) shouldn't be in the sequence.

Here is an example output, with newlines separating the numbers:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
36
37
38
39
40
41
43
44
45
46
47
48
49
50
51
53
54
55
56
57
58
59
60
61
63
64
65
66
67
68
69
70
71
73
74
75
76
77
78
79
80
81
83
84
85
86
87
88
89
90
91
93
94
95
96
97
98
99
100

Answer 1

05AB1E, 6 bytes

тLʒ2å_

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Explanation

тL       # push [1 ... 100]
  ʒ      # filter, keep only elements that
   2å_   # does not contain 2

Answer 2

Taxi, 2399 2391 2370 1783 1773 1706 bytes

-8 bytes for realizing that, instead of leaving a certain passenger at Sunny Side Park forever, it's more worth it to throw them off of Riverview Bridge. Ah, what a lovely town this is.

-21 bytes for taking out a comment I stupidly left in.

-587 bytes by simply changing the entire way I went about this (apparently a shorter way is by arithmetic; integer-dividing [17, 27, 37, 47,...] by 9 yields the sequence, but you gotta skip over the 20's yourself.)

-17 bytes for the realization that any quotes-encased string without a space doesn't need quotes after all (thanks Jo King!).

-67 bytes for the realization that linebreaks are optional.

17 is waiting at Starchild Numerology.Go to Starchild Numerology:w 1 l 2 r 1 l 1 l 2 l.Pickup a passenger going to Cyclone.Go to Cyclone:e 1 l 2 r.[B]Pickup a passenger going to Cyclone.Pickup a passenger going to Divide and Conquer.9 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Divide and Conquer.Go to Divide and Conquer:e 1 l 2 r 3 r 2 r 1 r.Pickup a passenger going to Trunkers.Go to Trunkers:e 1 r 3 r 1 l.Pickup a passenger going to The Babelfishery.Go to The Babelfishery:e 1 r 1 r.Pickup a passenger going to Post Office.\n is waiting at Writer's Depot.Go to Writer's Depot:n 5 l 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.Go to Cyclone:s 1 r 1 l 2 r.Pickup a passenger going to Addition Alley.Pickup a passenger going to Equal's Corner.177 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Equal's Corner.Go to Equal's Corner:w 1 l.Switch to plan C if no one is waiting.Pickup a passenger going to Sunny Skies Park.100 is waiting at Starchild Numerology.Switch to plan D.[C]10 is waiting at Starchild Numerology.[D]Go to Starchild Numerology:n 1 r.Pickup a passenger going to Addition Alley.Go to Sunny Skies Park:w 1 r.Go to Addition Alley:n 1 r 1 r 1 r.Pickup a passenger going to Cyclone.Go to Cyclone:n 1 l 1 l.Pickup a passenger going to Cyclone.Pickup a passenger going to Equal's Corner.917 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Equal's Corner.Go to Equal's Corner:w 1 l.Switch to plan E if no one is waiting.Switch to plan F.[E]Go to Go More:n 1 l.Go to Cyclone:w 1 r.Switch to plan B.[F]

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This one isn't winning me any code golf competitions anytime soon, but I decided to try out the esolang Taxi.

Taxi is an esolang in which all programming is done by picking up and dropping off passengers at various stops in the fictional town of Townsburg. Of course, your taxicab will sometimes run out of gas, so you also need to visit gas stations every so often, and pay using the credits you receive as fare (in this case, I only need to stop for gas - at Go More - once per loop iteration!).

I used some tricks that reduce the filesize a bit, such as rephrasing directions like east 1st left, 2nd right as e 1 l 2 r, removing the word the where it is optional, and using the least complicated route towards all of my destinations (not necessarily the shortest path).

I hate this shorter solution more than the one I originally came up with. This solution down here is a more general way of accomplishing the task, which could start and end anywhere you want. Here it is, in its entirety.

2245 bytes (way more general)

1 is waiting at Starchild Numerology.Go to Starchild Numerology:w 1 l 2 r 1 l 1 l 2 l.Pickup a passenger going to Cyclone.Go to Cyclone:e 1 l 2 r.[B]Pickup a passenger going to Addition Alley.Pickup a passenger going to The Babelfishery.Go to The Babelfishery:n 2 r 2 r.Pickup a passenger going to Cyclone.Go to Cyclone:n 5 l 2 l.Pickup a passenger going to Chop Suey.Go to Zoom Zoom:n.0 is waiting at Writer's Depot.Go to Writer's Depot:w.Pickup a passenger going to Narrow Path Park.Go to Narrow Path Park:n 3 r 1 l 1 r.Go to Chop Suey:e 1 r 1 l 1 r.[C]Switch to plan E if no one is waiting.Pickup a passenger going to Crime Lab.2 is waiting at Writer's Depot.Go to Writer's Depot:n 1 l 3 l.Pickup a passenger going to Crime Lab.Go to Crime Lab:n 3 r 2 r.Switch to plan D if no one is waiting.Pickup a passenger going to KonKat's.Go to Narrow Path Park:n 5 l.Pickup a passenger going to KonKat's.Go to KonKat's:e 1 r.Pickup a passenger going to Narrow Path Park.Go to Narrow Path Park:n 2 l.Go to Chop Suey:e 1 r 1 l 1 r.Switch to plan C.[D]Go to Chop Suey:n 5 r 1 l.Switch to plan C.[E]Go to Narrow Path Park:n 1 l 1 r 1 l.Pickup a passenger going to Crime Lab.0 is waiting at Writer's Depot.Go to Writer's Depot:w 1 l 1 r 2 l.1 is waiting at Starchild Numerology.Pickup a passenger going to Crime Lab.Go to Crime Lab:n 3 r 2 r.Switch to plan F if no one is waiting.Pickup a passenger going to Riverview Bridge.Go to Cyclone:n 4 l 2 l.Pickup a passenger going to Post Office.Go to Riverview Bridge:n 2 r.\n is waiting at Writer's Depot.Go to Writer's Depot:w 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.Go to Starchild Numerology:s 1 r 1 l 1 l 2 l.Switch to plan G.[F]Go to Cyclone:s 1 r 1 l 2 r.Pickup a passenger going to Riverview Bridge.Go to Riverview Bridge:n 2 r.Go to Starchild Numerology:w 2 l 3 l 2 r.[G]Pickup a passenger going to Addition Alley.Go to Addition Alley:e 1 l 2 r 3 r 1 r.Pickup a passenger going to Magic Eight.101 is waiting at Starchild Numerology.Go to Starchild Numerology:n 1 l 1 l 3 l 2 r.Pickup a passenger going to Magic Eight.Go to Magic Eight:w 1 r 2 r 1 r.Switch to plan H if no one is waiting.Pickup a passenger going to Cyclone.Go to Cyclone:n 1 l 2 r.Switch to plan B.[H]

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And if mega-cheating is allowed, this one is way shorter than either of the last two.

456 bytes (totally cheating)

1\n3\n4\n5\n6\n7\n8\n9\n10\n11\n13\n14\n15\n16\n17\n18\n19\n30\n31\n33\n34\n35\n36\n37\n38\n39\n40\n41\n43\n44\n45\n46\n47\n48\n49\n50\n51\n53\n54\n55\n56\n57\n58\n59\n60\n61\n63\n64\n65\n66\n67\n68\n69\n70\n71\n73\n74\n75\n76\n77\n78\n79\n80\n81\n83\n84\n85\n86\n87\n88\n89\n90\n91\n93\n94\n95\n96\n97\n98\n99\n100 is waiting at Writer's Depot.Go to Writer's Depot:w 1 l 2 r 1 l 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.

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Answer 3

Python 2, 39 bytes

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

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Uses arithmetic operations only to generate numbers without 2's.

The value k follows the arithmetic progression 17, 27, 37, 47, ..., which when floor-divided by 9 gives 1,3,4,5,6,7,8,9,10,11,13,14,... which counts up numbers not ending in 2. To skip 20 through 29, outputs are increased by 10 past a certain threshold.

Answer 4

JavaScript (ES6), 43 bytes

Returns the sequence as a comma-separated string.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

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Why doing it this way?

We could iterate from \$1\$ to \$100\$ and test each number with /2/.test(n), which is a rather concise statement. But in this scenario, we'd have to handle empty entries with something like (/2/.test(n)?'':...), which adds a couple more bytes.

For example, this would work for 45 bytes:

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Or this would work for 44 bytes, if a leading comma is acceptable:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

All in all (and until proven otherwise), it turns out to be shorter to skip right away all values of \$n\$ that contain a \$2\$.

Commented

f =                 // f is a recursive function taking:
(n = 98) =>         // n = counter, initialized to 98
  n ?               // if n is not equal to 0:
    f(              //   prepend the result of a recursive call:
      n -=          //     update n:
        n - 27 ?    //       if n is not equal to 27:
          n % 10 ?  //         if n is not a multiple of 10:
            1       //           subtract 1 from n
          :         //         else:
            2       //           subtract 2 from n
        :           //       else (n = 27):
          11        //         subtract 11 from n (--> 16)
    ) +             //   end of recursive call
    [, n + 3]       //   append a comma, followed by n + 3; notice that this is the value
                    //   of n *after* it was updated for the recursive call; at the first
                    //   iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
  :                 // else (n = 0):
    1               //   output the first term '1' and stop recursion

Answer 5

R, 19 bytes

grep(2,1:100,inv=T)

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Answer 6

Python 2, 44 bytes

print[n for n in range(1,101)if'2'not in`n`]

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Answer 7

Perl 6, 22 bytes

put grep {!/2/},1..100

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There's probably a better way to do the code block, but I couldn't find a regex adverb to invert the match

Answer 8

PowerShell, 22 16 bytes

1..100-notmatch2

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-6 bytes thanks to mazzy

Generates the range 1 to 100, then pulls out those objects where they do -notmatch the number 2. Running the -notmatch against an array like this acts like a filter on the array. Each item is left on the pipeline, and output is implicit.

Answer 9

Japt, 7 bytes

Lõs kø2

---

Lõs kø2     Full Program
Lõs         Range ["1"..."100"] (numbers are casted to string)
    k       Remove
     ø2     anything that contains "2"

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Answer 10

Haskell, 48 33 31 bytes

Thanks @JonathanFrech for fifteen bytes saved, and @xnor for another two! I missed a big golf and didn't realize main=print$ can be omitted.

filter(all(/='2').show)[1..100]

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Easily extended by changing the 100. Stringifies all the numbers and keeps only those without a '2'.

Answer 11

Bash + GNU utilities, 16

• 1 byte saved thanks to @Dennis.

seq 100|sed /2/d

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Answer 12

Retina, 19 17 bytes

100*
.
$.>`¶
A`2

Try it online! Edit: Saved 2 bytes thanks to @ovs, although the last line now includes a newline. Explanation:

100*

Insert 100 characters.

.
$.>`¶

Replace each character with the number of characters up to and including that character, plus a newline.

A`2

Remove all entries that contain a 2.

Answer 13

Java 10, 67 bytes

v->{for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);}

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Explanation:

v->{                           // Method with empty unused parameter and no return-type
  for(int i=0;++i<101;)        //  Loop `i` in the range (0, 101)
    if(i%10!=2                 //   If `i` modulo-10 is not 2
       &i/10!=2)               //   And `i` integer-divided by 10 is not 2 either
      System.out.println(i);}  //    Print `i` with a trailing newline

Answer 14

Tcl, 44 bytes

time {if ![regexp 2 [incr i]] {puts $i}} 100

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---

Tcl, 47 bytes

time {if [incr i]%10!=2&$i/10!=2 {puts $i}} 100

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Tcl, 50 bytes

time {if {2 ni [split [incr i] ""]} {puts $i}} 100

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Answer 15

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ  10 squared
f   output each value in [1 .. n] satisfying the following filter
 E  get array of decimal digits in number
 2#     count the number of 2s
 !  logical not

Run this one

Answer 16

Wolfram Language (Mathematica), 42 bytes

Print@⌈Range[1,100,10/9]~Drop~{18,26}⌉

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The arithmetic sequence 1, 19/9, 29/9, 39/9, ... grows at just the right rate that taking the ceiling skips all the numbers ending in 2. Then we get rid of 20 through 29 by Dropping the values at indices 18 through 26.

Answer 17

C (GCC), 62 55 Bytes

• 7 Bytes thanks to Jonathan Frech

f(n){for(n=0;++n-101;n/10-2&&n%10-2&&printf("%d,",n));}

Loops from 1 to 100 and prints the number only if 2 is not in the ones or tens place.

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Answer 18

Powershell, 19 bytes

1..100-split'.*2.*'

This script show null-value instead 'numbers with 2 inside' and completely solves the task 'number 2 shouldn’t appear anywhere in the sequence'.

Output:

1


3
4
5
6
7
8
9
10
11


13
14
15
16
17
18
19




















30
31


33
34
35
36
37
38
39
40
41


43
44
45
46
47
48
49
50
51


53
54
55
56
57
58
59
60
61


63
64
65
66
67
68
69
70
71


73
74
75
76
77
78
79
80
81


83
84
85
86
87
88
89
90
91


93
94
95
96
97
98
99
100

Powerhsell (output does not contain null-values), 24 bytes

1..100-split'.*2.*'-ne''

Answer 19

Python 3, 53 51 50 49 46 bytes

['2'in str(n)or print(n)for n in range(1,101)]

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Not the strongest language for this task, but I'm new to golfing.

Thanks to the commenters for their tips!

Answer 20

sh + coreutils, 16 chars

seq 100|sed /2/d

Generates sequence from 1 to 100 (inclusive) and deletes any lines that have '2' in them.

Answer 21

Z80Golf, 49 48 bytes

00000000: 1630 2e0a 5faf f57b fe02 2818 82ff f182  .0.._..{..(.....
00000010: ff92 3cf5 7dff f1bd 280a fe02 2803 f518  ..<.}...(...(...
00000020: e63c 18fa 7b3c bd20 db3e 31ff 3dff ff76  .<..{<. .>1.=..v

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Assembly:

ld d, 30h			; ascii '0' character
ld l, 0Ah			; number 10 and ascii newline
tens:
	ld e,a			; store tens digit
	xor a			; reset ones digit to 0
	push af			; store initial ones digit 0
	ones:
		ld a,e		; get stored tens digit
		cp 2
		jr z,cont	; if tens digit==2(e.g.20-29),skip loop
		add d
		rst 38h 	; print tens digit
		pop af		; get stored ones digit
		add d
		rst 38h 	; print ones digit
		sub d
		inc a		; increment ones digit
		push af		; store ones digit
		ld a, l
		rst 38h 	; print newline
		pop af		; get stored ones digit again
		cp l
		jr z,cont	; if ones digit==10, break loop
		cp 2
		jr z,inc_again	; if ones digit==2, incr again
		repeat_loop:
		push af		; store ones digit again
		jr ones		; repeat print loop
		inc_again:
			inc a
			jr repeat_loop
		
	cont:
	ld a,e			; get stored tens digit
	inc a			; increment tens digit
	cp l
	jr nz, tens		; if tens place!=10, continue loop
ld a,31h
rst 38h				; print '1'
dec a
rst 38h				; print '0'
rst 38h				; print '0'
halt

Saved one byte with the repeat_loop jump

Answer 22

Kotlin, 32 bytes

{(1..100).filter{'2' !in ""+it}}

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Answer 23

Bash, 31 bytes

printf %d\\n {1..100}|grep -v 2

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Thanks to Digital Trauma for short loop.

Answer 24

ORK, 1092 bytes

There is such a thing as a t
A t can w a number
A t can d a number
A t has a t which is a number

When a t is to w a number:
I have a mathematician called M
M's first operand is the number
M's second operand is 1
M is to add
The number is M's result
My t is 0
I have a number called n
n is the number
I am to d n
M's first operand is my t
M's second operand is 1
M is to compare
I have a scribe called W
If M says it's less then W is to write the number
If M says it's less then W is to write " "
M's first operand is the number
M's second operand is 100
M is to compare
If M says it's less then I am to loop

When a t is to d a number:
I have a mathematician called M
M's first operand is the number
M's second operand is 10
M is to modulo
I have a mathematician called N
N's first operand is M's result
N's second operand is 2
N is to compare
If N says it's equal then my t is 1
M is to divide
The number is M's result
M's first operand is the number
M's second operand is 0
M is to compare
If M says it's greater then I am to loop

When this program starts:
I have a t called T
T is to w 0

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Objects R Kool. Output is a space-delimited list of numbers.

This translates (approximately) to the following pseudocode:

class t {
	int t;
	
	void w(number) {
		label T_W;
		mathematician M;
		M.first_operand = number;
		M.second_operand = 1;
		M.add();
		number = M.result;
		t = 0;
		int n = number;
		d(n);
		M.first_operand = t;
		M.second_operand = 1;
		M.compare();
		scribe W;
		if M.its_less { W.write(number); }
		if M.its_less { W.write(" "); }
		M.first_operand = number;
		M.second_operand = 100;
		M.compare();
		if M.its_less { goto T_W; }
	}
	
	void d(number) {
		label T_D;
		mathematician M;
		M.first_operand = number;
		M.second_operand = 10;
		M.modulo();
		mathematician N;
		N.first_operand = M.result;
		N.second_operand = 2;
		N.compare();
		if N.its_equal { t = 1; }
		M.divide();
		number = M.result;
		M.first_operand = number;
		M.second_operand = 0;
		M.compare();
		if M.its_greater { goto T_D; }
	}
}

void main() {
	t T;
	T.w(0);
}

As you can see, everything is done using objects, including basic math and IO functions (through the built-in mathematician and scribe classes). Only whole functions can loop, which explains the need for an object with two functions to do the work.

Answer 25

PHP 7.1, 40 bytes

while($i++<100)strstr($i,50)||print$i._;

prints numbers separated by underscores. Run with -nr or try it online.

Answer 26

MathGolf, 7 6 bytes

♀╒Ç{2╧

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Explanation

♀╒       Push 100 and convert to 1-based range ([1,2,...,100])
  Č{     Inverse filter by block
    2╧   Does the number contain 2?

Answer 27

C (clang), 56 bytes

f(i){for(i=0;i++<100;i%10^2&&i/10^2&&printf("%d\n",i));}

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Answer 28

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

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Uses unless instead of if not, because why not? :)

Answer 29

Ruby, 35 31 bytes

100.times{|e|p e if/2/!~e.to_s}

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Thanks to Conor O'Brien for -4 bytes

Answer 30

brainfuck, 176 bytes

---------[[-<]-[>]>[>]-[-<]<++]-[>-<+++++++++]>--[>[->]<[<<<]>>[->]>-]<<,<-[-<]>[>]<[.[->+<]++++++++++.,<]>>[>]>>->-<<<<[>>>[<<[<]<.>>[>]>.[-<+>]++++++++++.,>]<<[<]<,<]>>>>.<..

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Shorter is definitely possible. This generates the numbers 1,3,4,5,6,7,8,9 and 0,1,3,4,5,6,7,8,9. First it outputs each number in the first list, then it outputs every combination of the first and second list, then finally prints just 100.

Explanation:

---------   Push minus 9
[           Repeat 9 times
  [-<]-[>]    Add the negative of the number to the first list
  >[>]-[-<]<  Add the negative of the number to the second list
  ++          Increment the counter
]
Tape: 255 254 253 252 251 250 249 248 247 0' 0 246 247 248 249 250 251 252 253 254
-[>-<+++++++++]>--  Push 197
Tape: 255 254 253 252 251 250 249 248 247 0 197' 246 247 248 249 250 251 252 253 254
[
  >[->]<    Subtract 197 from every element in both lists to convert to digits
  [<<<]>>
  [->]>-
]
Tape: 58 57 56 55 54 53 52 51 49 0' 49 50 51 52 53 54 55 56 57
<<,<-[-<]>[>]<  Remove the 0 and the 2 from the first list
Tape: 58 57 56 55 54 53 52 51 0 0 0' 49 50 51 52 53 54 55 56 57
[  Loop over the first list
  .[->+<]        Print digit
  ++++++++++.,<  Print a newline
]
>>[>]>>->-   Remove the 2 from the second list
<<<<      
[  Loop over first list
  >>>
  [  Loop over second list
    <<[<]<.        Print first digit
    >>[>]>.        Print second digit
    [-<+>]         Move second digit over one
    ++++++++++.,>  Print a newline
  ]
  <<[<]<,<  Remove the digit from the first list and move to the next
]
>>>>.<..  Print 100 using the second list

Answer 31

SimpleTemplate, 51 bytes

This was a fun challenge! And it is a challenge where my language can do well.

{@forfrom 1to100}{@if_ is notmatches"<2>"}{@echol_}

Cycles through all values from 1 to 100, outputting the ones that don't have 2, separated by a newline.

You can try it on http://sandbox.onlinephpfunctions.com/code/2c97a2b6954c29844f1079938da771d51e2e0d99

Ungolfed:

{@for i from 1 to 100}
    {@if i is not matches "<2>"}
        {@echo i, "\n"}
    {@/}
{@/}

The {@/} is used to close the {@for ...} and {@if ...}, but is optional.
When compiling to PHP, it adds the needed closing.

---

If you're curious, the golfed code results in this PHP code:

// {@forfrom 1to100}
// ~ optimization enabled ~ inlining the results
foreach(array(...) as $DATA['_']){

    // {@if_ is notmatches"<2>"}
    if(!(preg_match("<2>", (isset($DATA['_'])?$DATA['_']:null)))) {

        // {@echol_}
        echo implode('', $FN['array_flat']((isset($DATA['_'])?$DATA['_']:null)));echo PHP_EOL;


// AUTO-CLOSE
};};

Where $FN['array_flat'] is defined outside of this code.

Answer 32

K4, 15 bytes

Solution:

1_&~"2"in'$!101

Example:

q)k)1_&~"2"in'$!101
1 3 4 5 6 7 8 9 10 11 13 14 15 16 17 18 19 30 31 33 34 35 36 37 38 39 40 41 43 44 45 46 47 48 49 50 51 53 54 55 56 57 58 59 60 61 63 64 65 66 67 68 69 70 71 73 74 75 76 77 78 79 80 81 83 84 85 86 87 88 89 90 91 93 94 95 96 97 98 99 100

Explanation:

1_&~"2"in'$!101 / the solution
           !101 / range 0..100
          $     / string
    "2"in'      / is "2" in each?
   ~            / not
  &             / indices where true
1_              / drop the first

Extra:

TIO for 16 byte K (oK) answer: Try it online!

Answer 33

Jelly, 7 bytes

³D2eṆƲƇ

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Answer 34

Pyth, 17 bytes

VS100I!}\2%"%s"NN

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My first code golf submission, also my first time using Pyth, this took way longer to put together than I expected.

Explanation

VS100 for loop from 1 to 100

I!}\2%"%s if the string "2" is in the string conversion of N

%"%sN convert N to a string. This is the only way I could figure out how to do this. If there is a shorter way to do int -> string conversion please let me know. I'm honestly just looking for a way to call str() or repr() on it with less chars.

N print n

EDIT: Looks like someone else beat me to it with Pyth. Turns out to convert N to a str I could do `N`, I'm going to leave mine the same because if I change it its almost the exact same solution.

Answer 35

Scala, 56 48 47 45 42 bytes

1 to'd'filter(_+""forall(50!=))map println

Prints the elements separated by a line.

Here is a 38 bytes version that calls toString (technically allowed by the rules):

print(1 to'd'filter(_+""forall(50!=)))

Resulting in:

Vector(1, 3, 4, ..., 100)

Answer 36

Pip, 9 bytes

2NI_FI\,h

Use any of the flags -l, -n, -s, -p to get nice-looking output. Try it online!

Explanation

        h  Preset variable: 100
      \,   1-based range: [1 2 3 ... 100]
    FI     FIlter on this function:
2NI_        2 is Not In the argument
           Print the resulting list (implicit)

Answer 37

JavaScript (ES6), 51 bytes

After reading Arnauld's answer, I wanted to try a non-recursive approach. Sure enough, it's longer, but it may be of some interest.

_=>[...Array(101).keys()].filter(n=>n*!/2/.test(n))

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[...Array(101).keys()] creates a list of the numbers 0 through 100. We then filter to get rid of 0 and any number that contains a 2.

Answer 38

Whitespace, 121 bytes

[S S S N
_Push_0][N
S S N
_Create_Label_LOOP][S S S T N
_Push_1][T  S S S _Add][S N
S _Duplicate][S S S T   T   S S T   S T N
_Push_101][T    S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_EXIT][S N
S _Duplicate][S S S T   S T S N
_Push_10][T S T T   _Modulo][S S S T    S N
_Push_2][T  S S T   _Subtract][N
T   S N
_If_0_Jump_to_Label_LOOP][S N
S _Duplicate][S S S T   S T S N
_Push_10][T S T S _Integer_divide][S S S T  S N
_Push_2][T  S S T   _Subtract][N
T   S N
_If_0_Jump_to_Label_LOOP][S N
S _Duplicate][T N
S T _Print_integer_to_STDOUT][S S S T   S T S N
_Push_10][T N
S S _Print_character_to_STDOUT][N
S N
N
_Jump_to_Label_LOOP]

Letters S (space), T (tab), and N (new-line) added as highlighting only.
[..._some_action] added as explanation only.

Try it online (with raw spaces, tabs and new-lines only).

Pseudo-code:

Integer i = 0
Label LOOP:
  i = i+1
  If(i == 101):
    Exit program
  If(i modulo-10 == 2):
    Go to next iteration of LOOP
  If(i integer-divided by 10 == 2):
    Go to next iteration of LOOP
  Print i to STDOUT
  Print a newline to STDOUT
  Go to next iteration of LOOP

Answer 39

APL(NARS), 17 chars, 34 bytes

a/⍨∼'2'∊¨⍕¨a←⍳100

test

  a/⍨∼'2'∊¨⍕¨a←⍳100
1 3 4 5 6 7 8 9 10 11 13 14 15 16 17 18 19 30 31 33 
  34 35 36 37 38 39 40 41 43 44 45 46 47 48 49 50 
  51 53 54 55 56 57 58 59 60 61 63 64 65 66 67 68 
  69 70 71 73 74 75 76 77 78 79 80 81 83 84 85 86 
  87 88 89 90 91 93 94 95 96 97 98 99 100

Answer 40

Gol><>, 19 bytes

`dFLP:aSD2=$2=+ZN|;

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Explanation:

`dFLP:aSD2=$2=+ZN|;

`d                  //Push 100 to the stack
  F                 //For loop from 0 to 99
   LP               //  Push the loopcounter+1 to the stack,achieving a range [1..100]
     :              //  Double for potential output later (saves 1 byte compared to pushing it again)
      aSD           //  Push division & modulus of current number by 10
         2=         //  Check if (num % 10) == 2 , pushes either 0 or 1
           $2=      //  Check if (num / 10) == 2 , "
              +     //  Add the results acting as a logical or for is zero question
               ZN   //  If neither the mod nor the div are equal to 2 output the number
                 |; //Exit after loop

Answer 41

Ruby, 28 characters

puts [*?1..'100'].grep_v /2/

Thanks to:

• G B, as I borrowed the idea of not using a proc from his deleted answer

Sample run:

bash-4.4$ ruby -e 'puts [*?1.."100"].grep_v /2/' | head -15
1
3
4
5
6
7
8
9
10
11
13
14
15
16
17

Try it online!

Answer 42

V, 14 13 bytes

Saved 1 byte thanks to @oktupol

á199ñÄj<C-a>ñç2/d

Try it online! <C-A> represents the start of heading character (0x01)

Explanation

á1            Insert a 1 on the first line
99ñ           Repeat 99 times:
 Ä             Duplicate the last line
 j<C-A>        Increment the last line by one
ñç2/          For every line containing a 2:
 d             Remove the line

Answer 43

Forth (gforth), 58 bytes

: f 101 1 do i 10 /mod 2 <> swap 2 <> * if i . then loop ;

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Explanation

Loops from 1 to 100 (inclusive) and if both the ones and tens place of the index are not equal to 2, print it

Code explanation

: f                    \ start a new word definition
  101 1 do             \ start a loop from 1 to 100 inclusive
    i 10 /mod          \ get the quotient and remainder of dividing i by 10
    2 <>               \ check if the the tens place is not equal to 2
    swap               \ move the result down the stack one
    2 <>               \ check that the ones place is not equal to 2
    *                  \ multiply results (cheaper AND)
    if i . then        \ if true, output i
  loop                 \ end counted loop
;                      \ end word definition

Answer 44

Pyth, 13 11 bytes

f!}`2`TS100

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-2 with many thanks (nearly a year later!) to @ar4093

Original version:

VS*TTI!}\2`NN

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I'm still a Pyth beginner so this could probably be improved on.

Explanation

for N in num_to_range(Psorted(times(T,T))):   # For N in range 1 to 10*10
 if Pnot(Pin("2",repr(N))):                   # If "2" is not in `N`
  imp_print(N)                                # Print N

Answer 45

MBASIC, 59 bytes

1 FOR I=1 TO 100:IF INSTR(STR$(I),"2")=0 THEN PRINT I
2 NEXT

There's probably a mathematical way to do this, but this approach is what first came to mind.

Answer 46

T-SQL, 65 bytes

DECLARE @ INT=1a:IF @ NOT LIKE'%2%'PRINT @;SET @+=1IF @<101GOTO a

I'm a bit annoyed that this variable loop is shorter than the best set-based SQL variant I could find (91 bytes):

SELECT DISTINCT number FROM spt_values WHERE number>0and number<101AND number NOT LIKE'%2%'

This one even has the additional restriction of needing to be run in the master database (since it uses an undocumented system table).

The best set-based solution I could find without that requirement was 94 bytes:

WITH t AS(SELECT 1n UNION ALL SELECT n+1FROM t WHERE n<100)SELECT*FROM t WHERE n NOT LIKE'%2%'

Answer 47

Perl 5 (5.12+), 25 bytes

$,=$/;say grep!/2/,1..100

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Pretty straightforward. The $,=$/ makes the following print put a newline between list elements, which is shorter than using join.

Answer 48

Attache, 24 bytes

Output!2&`!in@List\1:100

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Alternatively, Print=>2&`!in@List\1:100.

Filters (\) from 1:100 values whose digits (@List) do not contain (`!in) a 2 (2&), which is then Outputted.

Answer 49

Ruby, 31 bytes

p$.if"#{$.+=1}"!~/2/ until$.>99

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A different, iterative approach than other ruby answers. This uses the not-match operator !~ as well as the implicitly-zero input line number variable $. as the iterator. The TIO link shows my golfing progress, from 48 bytes to 31 bytes.

Answer 50

F#, 66 bytes

Solution

Seq.filter(fun i->i%10<>2&&i/10<>2){1..100}|>Seq.iter(printfn"%d")

Explanation

Filters a sequence of numbers 1 to 100 by retaining those whose modulus of 10 is not 2, and which integer-divided by 10 do not result in 2, then prints the sequence with newlines between items.

This works for numbers up to and including 199. A more general solution is slightly longer (74 bytes):

Seq.filter(fun i->(string i).IndexOf '2'<0){1..100}|>Seq.iter(printfn"%d")

With proper spacing, and rearranged for readability, this looks as follows:

{1 .. 100}
|> Seq.filter (fun i -> (string i).IndexOf '2' < 0)
|> Seq.iter (printfn "%d")

Answer 51

C# with only Linq, 170/184 bytes

using System.Linq;class a{static void Main(string[]b)=>Enumerable.Range(1,100).ToList().ForEach(x=>System.Console.Write(x.ToString().Contains("2")?"":x.ToString()+" "));}

while this code does work, dotnetfiddle requires both the class and the main method to be public, so that the total is 14 bytes more.

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Answer 52

[C# (.NET Core)], 63 62 bytes

Thanks to milk for saving one byte in the for loop.

for(int i=0;++i<101;)if(i%10!=2&&i/10!=2)Console.WriteLine(i);

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Ungolfed:

for (int i = 0; ++i < 101;)         // all integers from 1-100 (starts from zero, increments before code runs)
    if (i % 10 != 2                 // all numbers not ending with '2'
                    && i / 10 != 2) // all numbers not starting with '2'
        Console.WriteLine(i);       // write to console

Answer 53

Rust, 65 bytes

fn main(){for i in 1..101{if i%10!=2&&i/10!=2{println!("{}",i)}}}

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Similar to the answers by Meerkat and dumetrulo, just iterate through and print only those whose ones digit and tens digit are not 2.

Answer 54

Ohm v2, 7 9 bytes

⁸#u⁇2εX

Explanation:

⁸#u⁇2εX
⁸        Push 100
 #       Push range 0..a
  u      Turn to string (vectorizes)
   ⁇     Filter only those that match conditional
    2εX  Match those that do not contain "2"

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Answer 55

LUA, 113 68 47 45 bytes

Thanks to LUA's rather loose dynamic typing, can straight-up search the integer.

Thanks to @manatwork (twice)

Thanks to @Jo King

for x=1,100 do n=("").find(x,2)or print(x)end

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Answer 56

Crystal, 65 bytes

(1..100).each do |x|
    x.to_s().includes?('2') ? 0 : puts x
end

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Answer 57

Tidy, 27 bytes

{{x:"2"!in x.0}from[1,100]}

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Function which returns the appropriate range. x.0 concatenates x and 0 as a string.

Answer 58

JavaScript (Node.js), 45 44 bytes

-1 byte thanks to Neil

for(i=0;i++<100;)/2/.test(i)||console.log(i)

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Answer 59

Windows Batch, 49 48 bytes

@for /l %%G in (1,1,100)do @echo %%G|find /v "2"

Loops from 1 to 100, and for each number looped, only output those who does not contain any "2".

1 byte is saved by @Neil.

Answer 60

Haskell, 57 Bytes

Solution

import Data.List
unlines.nub.map(filter(/='2').show).$[1..100]

or

import Data.List
nub.map(filter(/='2').show)$[1..100]

if you just want the list.

Output

Prelude Data.List> unlines.nub.map(filter(/='2').show)$[1..]
"1\n\n3\n4\n5\n6\n7\n8\n9\n10\n11\n13\n14\n15\n16\n17\n18\n19\n0\n30\n31\n33\n34\n35\n36\n37\n38\n39\n40\n41\n43\n44\n45\n46\n47\n48\n49\n50\n51\n53\n54\n55\n56\n57\n58\n59\n60\n61\n63\n64\n65\n66\n67\n68\n69\n70\n71\n73\n74\n75\n76\n77\n78\n79\n80\n81\n83\n84\n85\n86\n87\n88\n89\n90\n91\n93\n94\n95\n96\n97\n98\n99\n100

Explanation

Makes all numbers a string, removes their '2's and weeds out the duplicates.

Answer 61

Ruby, 33 bytes

Solution:

puts (?1..'100').reject{|x|x[?2]}

Answer 62

JavaScript, 57 bytes

_=>`${[...Array(101).keys()]}`.replace(/^0,|\d?2.?,/g,'')

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Answer 63

SmileBASIC, 50 bytes

@L
N=N+1IF.>INSTR(STR$(N),"2")THEN?N
ON N>99GOTO@L

Explanation:

@LABEL
 N = N + 1
 IF 0 > INSTR(STR$(N), "2") THEN PRINT N
ON N>99 GOTO @LABEL

INSTR(STR$(N), "2") is -1 if N doesn't contain a 2.

ON ... GOTO takes a list of labels, and jumps to a label in that list corresponding to the value of an expression.
If N isn't greater than 99, N>99 returns 0 so it jumps to the 0th label, @LABEL.
Otherwise, N>99 is 1 so it tries to jump to label 1 in the list, but since the list isn't long enough, it doesn't jump and the program ends.

ON is meant to be used like switch/case, with a longer list of labels. But ON x GOTO @LABEL can be used as a shorter way of writing IF !(x) GOTO @LABEL:

IF N<=99GOTO@L
IF N<100GOTO@L
ON N>99GOTO@L

Answer 64

ink, 34 bytes

-(i){("{i}"!?"2"):{i}}
{i<100:->i}

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Explanation

-(i)             // Labelled gather - keeps track of how many times it's been visited (in variable i)
{"{i}"!?"2":     // If "2" is not a substring of i...
{i}              // ...print i
}
{i<100:->i}      // If i is less than 100, go back to i.

Answer 65

Vim, 18 bytes/keystrokes

100o0<esc>V{g<C-a>J:g/2/d<cr>

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Answer 66

C++, 84 81 bytes

-3 bytes thanks to ceilingcat

The function needs a void return value to compile with MSVC

#include<cstdio>
void f(){for(int i=0;++i<101;)i%10-2&&i/10-2&&printf("%d\n",i);}

The if read as "if the first digit isn't 2 and the second digit isn't 2"

Answer 67

Perl 5, 19 bytes

map{/2/||say}1..100

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