1
Challenge
Given an integer greater or equal to 4, n, print a rounded rectangle of as close as possible (with a gap of 1) sides and a perimeter of n characters.
Rules
- n is always 4 or greater, because otherwise the output wouldn't be a square
- The characters for the perimeter can be any non-whitespace character
- The rectangle should have equal sides when possible
- When not possible, the rectangle can be up to one character taller or wider than its other side
- The rectangle should have one whitespace character in each corner
- The rectangle can only ever have a gap of 1 (excluding corners) along the entire perimeter
- The gap can be on any side and any position along the perimeter
Rules
Least amount of bytes wins!
Examples
Input: 4
Output:
o
o o
o
Input: 5
Output:
oo
o o
o
Input: 8
Output:
oo
o o
o o
oo
Input: 21
Output:
oooooo
o o
o o
o o
o o
o o
ooooo
Here is the python3 code I used to generate the above examples:
import math ch = 'o' def print_rect(p): side_length = math.ceil(p / 4) height = side_length remainder = p - side_length * 3 p = side_length + 2 if side_length - remainder >= 2 or not remainder: remainder += 2 height -= 1 lines = [(ch * side_length).center(p)] for i in range(height): lines.append(ch + ch.rjust(side_length + 1)) lines.append((ch * remainder).center(p)) print('Output:') for line in lines: print(line) print_rect(int(input('Input: ')))
q=n%2==1?x+1:x
->q=n%2+x
;.repeat
->[R='repeat']
;Array..fill..join
->...[R]
;floor -> (no need, String#repeat would do floor)
; Tio – tsh – 2018-06-29T07:32:23.433