The greedy regex (robbers)

Question

This is the robbers' post. The cops' is here.

Your challenge is to take a cop's post and find an input that the regex matches but the program returns a falsey value.

Once you have cracked a cop's post, comment in a link to your crack. (If you don't have enough rep to comment, please say so, and someone will do it for you.) The robber with the most cracks wins.

Example

Let's say a cop's regex is (all of the flavors):

/^[0-9]$/

And the program is (JS):

x=>Boolean(parseInt(x))

Than a valid crack would be 0, because the regex matches 0 but 0 is falsey.

Answer 1

Python 3, pperry

İ

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The lower case variant i̇ of this character is created by a an i and a ċȯṁḃi̇̇ṅi̇̇ṅġ ḋȯṫ which results in a length of 2.

Answer 2

Python, ppperry

\n

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. doesn't match newline by default.

Answer 3

JavaScript, ThePirateBay

Solution:

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Answer 4

Java, Roman Gräf

is.is.is.is.

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Most things which match the regex crack it, so I'm not sure if the regex is what was intended