A crowd of blank stares

Question

Problem

Given no input write a program or a function that outputs or returns the following string:

(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)

Rules

• Shortest program wins.
• Trailing whitespace allowed.
• Trailing newlines allowed.
• Unused parameters for functions allowed.

Answer 1

SOGL V0.12, 12 bytes

pΙ2○3V?hG]‘Γ

Explanation:

pΙ2○3V?hG]‘   Push compressed string of the first half of the string (this is the kind of thing this compressor was made for)
           Γ  mirror, swap chars & palindromize with one character overlap

Try it Here!

Answer 2

05AB1E, 16 bytes

"(<>.".∞ηJÀ24£.∞

Try it online!

Explanation

"(<>."             # push this string
                   # STACK: "(<>."
      .∞           # intersected mirror
                   # STACK: "(<>.<>)"
        η          # compute prefixes
         J         # join to string
                   # STACK: "((<(<>(<>.(<>.<(<>.<>(<>.<>)"
          À        # rotate left
           24£     # take the first 24 chars
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>."
              .∞   # intersected mirror
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Answer 3

Python 3, 49 bytes

for i in range(11):print(end='(<>.<>)'[i-12:i+2])

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Answer 4

JS (Jsfuck), 10,614 bytes

Didn't have access to the website, had to figure this all out manually -.-

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+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
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+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+!+[]+!+[]]
+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]

Explanation:

Most of the characters are relatively easy: For the brackets im executing

   ([]["fill"]+[])[13] // '('

   ([]["fill"]+[])[14] // ')'

The full stop is gotten by making js create a scientific notation number like 1.1e+21 And taking the dot character after converting to a string

The square brackets are harder, we have to execute the function to create an italic html object string and steal the angle brackets. The main trick in this is getting the 'c' for the word italics, which requires building up another function to take the c from 'function'

There's a lot of scope for improvement here, mostly on which functions are used to get the square brackets. I also recall an easier way to get the character 'c' if italics is better, but i'd have to look though my old files to find it

console.log( (!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]
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+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])])

Answer 5

C# (Mono), 54 52 bytes

s=>"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

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-2 bytes thanks to Kevin Cruijssen

RIP C#

Answer 6

Retina, 30 bytes

(<>.<>)
5`.
$&$'
7`.
$`$&
^.

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Answer 7

V, 28 27 25 22 bytes

3? 4? bytes thanks to @KritixiLithos

i(<>.<>)òÙxlHÄ$xGòxÍî

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i(<>.<>)                'insert (<>.<>)
         ò        ò      'recursively
          Ù              'duplicate this (bottom line) down
           x             'delete the first character
            l            'and break when there's only one character left
             H           'go to the top of the buffer
              Ä          'duplicate that line up
               $x        'delete the last character
                 G       'and go back to the bottom of the buffer
                   x     'delete the extra ) left by the loop
                    Íî   'and remove all newlines

Answer 8

Charcoal, 18 17 bytes

Ｆ⁶…(<>.<>)⁺²ι‖ＢＯ⁷

Try it online! Link is to verbose version of code. Uses the new Slice operator.

Answer 9

R, 42 bytes

cat(substring('(<>.<>)',-4:6,2:12),sep='')

Fairly simple program that takes advantage of the way substring works in R. So substring('(<>.<>)',-4:6,2:12) produces the following vector

> substring('(<>.<>)',-4:6,2:12)
 [1] "(<"      "(<>"     "(<>."    "(<>.<"   "(<>.<>"  "(<>.<>)" "<>.<>)"  ">.<>)"  
 [9] ".<>)"    "<>)"     ">)"  

cat with an empty separator outputs it to STDOUT in the required format.

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Answer 10

TrumpScript, 70 Bytes

I know, it's a boring solution.

say "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"
America is great

Answer 11

Brachylog, 14 bytes

"(<>.<>)"aᶠckb

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"(<>.<>)"           #   string
         aᶠ         #       get all Affixes (pre- and suffixes)
           c        #       Concatenate
            kb      #       remove last (Knife) and first (Behead)

Answer 12

C (gcc), 59 57 bytes

2 4 bytes less than a simple puts() solution. There is sure to be some elegant recursive solution, but so far the overhead becomes too large at every attempt.

f(i){for(i=1;i++<12;)printf("%.*s",i,"(<>.<>)"+i/7*i%7);}

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Answer 13

Brainfuck, 198 175 167 Bytes

I have never done a codegolf, so this is my first one. Feedback is highly appreciated.

++++[>+++++<-]>[>++>+++>+++>++>++[<]>-]>.>.<.>.>++.<<.>.>.>>++++++.<<<<.>.>.>>.<<<.<.>.>.>>.<<<.>.<<.>.>.>>.<<<.>.>+.<<.>.>>.<<<.>.>.<.>>.<<<.>.>.>.<<<.>.>.<<.>.>.<.>.

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I went for the most obvious solution in my opinion. First, I set cells 1-5 to one of the letters "().<>". Then I just go to the right cells and output the character.

UPDATE: I changed the order in which the characters appear on the "tape" making the program way shorter and more efficient.

UPDATE 2: Just revisited my post after a while and realized, that using a shorter sequence for setting up the cells I could save some bytes.

Answer 14

Charcoal, 20 bytes

Ａ(<>ι(<ιι.ι.<ι.ιι.‖Ｂ

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Thanks to Destructible Lemon for noticing a pattern (-4).

AST:

Program
├Ａ: Assign
│├'(<>': String '(<>'
│└ι: Identifier ι
├Print
│└'(<': String '(<'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└'.<': String '.<'
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
└‖Ｂ: Reflect butterfly
 └Multidirectional

What ‖Ｂ does is basically visually palindromize canvas.

Answer 15

JavaScript, 47 bytes

g=(i=2)=>i>12?'':'(<>.<>)'.slice(i-14,i)+g(i+1)
f=(i=11)=>i?f(i-1)+'(<>.<>)'.slice(i-13,i+1):''

// Both of the above work and are the same size

document.write('<pre>Actual g(): ' + g() + '\nActual f(): ' + f() + '\nExpected:   (<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)</pre>');

Uses the same method as Rod's Python answer.

Answer 16

C (gcc), 61 bytes

I know this is lame but it's much shorter than my other solution...

f(){puts("(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)");}

C (gcc), 103 bytes

Here's a version where I'm trying to be somewhat tricky...

char*e="(<>.<>)<>.<>)>.<>).<>)<>)>)";f(i,n){for(n=2;n<8;n++)for(i=0;i<n;i++)putchar(e[i]);puts(&e[i]);}

C (gcc), 117 115 bytes

A recursive version that's fully tricky...

char*e="(<>.<>)";main(i,j){if(i<6){for(++i,j=0;j<i;putchar(e[j++]));main(i);}else if(i<12)printf(e+i++-6),main(i);}

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Answer 17

Mathematica 41 bytes

""<>"(<>.<>)"~StringDrop~i~Table~{i,-5,5}

Answer 18

q, 29 bytes

raze"(<>.<>)"{(y-5)_x}/:(!)11

-2 bytes thanks to streetster

EDIT for explanation:

Language is right to left interpreted.

How it works

raze"(<>.<>)"{(y-5)_x}/:(!)11
                        (!)11 /yields indices [0-10], right parameter of function (y)
                      /:      /each right: loop right parameter of a dyadic function
             {       }        /function
    "(<>.<>)"                 /left parameter of function (x)
              (y-5)           /subtract 5 from y (indices)
                   _          /remove first y chars from x, or last y chars if negative
raze                          /flatten string output to produce the final string

Answer 19

A crowd of blank stares watching Batman in honor of Adam West...

C# (.NET Core), 393 bytes

s=>{string b="NanananaNanaBATMAN!NanaBATMAN!NANANanaBATMAN!NANAnanaNanaBATMAN!NANABATMAN!NanaBATMAN!NANABATMAN!naNABATMAN!NANABATMAN!naNANAnaNANABATMAN!naNANANABATMAN!naNABATMAN!naNANAnanaNA",r="",t;for(int i=0;i<176;)if(b[i]=='B'){r+="<>";i+=7;}else{t=b.Substring(i,4);if(t=="Nana")r+="(";else if(t=="nana")r+="<";else if(t=="NAna")r+=">";else if(t=="NANA")r+=".";else r+=")";i+=4;}return r;}

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Answer 20

Haskell, 55 45 bytes

map take[2..7]++map drop[1..5]>>=($"(<>.<>)")

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First Haskell answer to beat the hardcoded solution!

Explanation

The way this answer works is by building a list of functions to be applied to the string (<>.<>). First we build the left and center with

map take[2..7]

which gives us all the prefixes from size two to seven. Then we build the right with

map drop[1..5]

which gives us all the suffixes from size six to two.

Once we have the list of functions we use a monadic bind (>>=) which is just concatMap but shorter. The function we concatmap with is ($"(<>.<>)") which applies the input to the string (<>.<>).

This makes the string.

Answer 21

Jelly, 22 bytes

1 byte thanks to Kritixi Lithos.

U;\UṚṖ
“(<>.<>)”;\ḊṖ,Ç

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Answer 22

Java 8, 52 bytes

x->"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Boring, but there isn't any way to make this shorter in Java.. Just initializing a temp String is already 11 bytes.. (String t="something";), and using substring a couple of times certainly costs too many bytes..

Shortest alternative to a literal return is probably this (58 bytes):

x->"(<(x(x.(x.<(x.x(x.x)x.x)>.x).x)x)>)".replace("x","<>")

Try it here.

Answer 23

Python 2, 57 bytes

print''.join("(<>.<>)"[max(0,n-5):n+2]for n in range(11))

I say it looks like a gang of owls peeking out behind their leader. Just saying.

Answer 24

MATL, 28 bytes

'(<>.<>)'XH5:"H7@-:)wh2M@+)h

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Answer 25

Haskell, 95 bytes

import Data.List
import Control.Arrow
concat$tail$init$uncurry(++)$inits&&&tail.tails$"(<>.<>)"

This is far longer than the 49 bytes necessary for a string literal with the output, but the best I could do to utilise the structure. As usual, I love arrows, and inits &&& tails does produce a tuple of the list of leading substrings and the list of trailing substrings of the input. Then those two tuple elements are put together in one list by passing the tuple to ++, and that list is concatenated to one large string. The tail and init calls avoid duplicating the (<>.<>) in the middle (one generated by inits, the other by tails) and drop the unwanted parenthesis from the start and end, taking only substrings of length 2 or more into account.

Answer 26

brainfuck, 245 210 bytes

Golfing in progress.

>++++++++[<+++++>-]>++++++[<++++++++++>-]>++++++[<++++++++++>-]<++>>++++++++[<+++++>-]<++++++<<<.>.<.>.>.<<.>.>.>.<<<.>.>.>.<<.<.>.>.>.<<.>.<<.>.>.>.<<.>.<<+.>.>.>.<<.>.<<.>>.>.<<.>.<<.>>>.<<.>.<<.>.>.<<.>>.<<.

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Answer 27

Jelly, 18 bytes

“(<>.<>)”ḣJœ|ṫJ$ḊṖ

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How it works

“(<>.<>)”ḣJœ|ṫJ$ḊṖ  Main link. No arguments.

“(<>.<>)”           Set the argument and return value to s := "(<>.<>)".
          J         Yield all indices of s, i.e., [1, 2, 3, 4, 5, 6, 7].
         ḣ          Dyadic head; yield s's prefixes of lengths 1 to 7.
               $    Combine the two links to the left into a chain.
              J         Indices; yield [1, 2, 3, 4, 5, 6, 7].
             ṫ          Dyadic tail; yield s's postfixes of lengths 1 to 7.
           œ|       Multiset union; concatenate the results to both sides,
                    discarding the copy of s. (s is both a prefix and a postfix.)
                Ḋ   Dequeue; remove the first prefix, i.e., "(".
                 Ṗ  Pop; remove the last postfix, i.e., ")".

Answer 28

C (clang), 62 61 bytes

main(n){while(write(++n<13,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}

This terminates only after timing out on TIO because the write to standard input fails, but it will terminate in a terminal. The program relies on a specific order of evaluation (undefined behavior) and won't work with, e.g., gcc.

Thanks to @Steadybox for an idea that saved a byte!

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Verification

$ cat crowd.c
main(n){while(write(++n<12,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}
$ clang -o crowd crowd.c 2> /dev/null

$ ./crowd 0> /dev/null
(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)

Alternate version, 62 bytes

main(n){while(++n<13)write(1,n/7*(n-7)+"(<>.<>)",n/7?14-n:n);}

At the cost of one more byte, the solution becomes a lot more portable.

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Answer 29

Python 2, 55 bytes

couldn't resist beating the current python 2 answer

print "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

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Answer 30

Jelly, 19 bytes

“(<>.<>)”µṖ¹Ƥ;¹ÐƤṖḊ

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Answer 31

J, 30 25 24 Bytes

;}.}:~.(<\,<\.)'(<>.<>)'

Explanation later, I have a feeling I can golf this more...

Edit:

-5 6 Bytes thanks to @FrownyFrog :)

Explanation:

               '(<>.<>)'   | The face
       (   <\.)            | Apply box to the suffixes of '(<>.<>)': Gives '(<>.<>)', '<>.<>)' ... ')'
          ,                | Append to...
        <\                 | Box applied to the prefixes of '(<>.<>)'
 }.}:~.                    | Remove the extra '(<>.<>)', as well as '(' and ')' from the front and back
;                          | Join into one string

Answer 32

Stax, 16 14 bytes

ü■_'σIHa¬ø·hÑè

Run and debug it at staxlang.xyz!

Unpacked (16 bytes) and explanation:

"(<>.":w|[D$3T:w
"(<>."              String literal                     (<>.
      :w            Palindromize, flipping (){}[]<>    (<>.<>)
        |[          Array of prefixes                  [ ( (< .. (<>.<>) ]
          D         Drop first                         [ (< (<> .. (<>.<>) ]
           $        Concatenate                        (<(<>(<>.(<>.<(<>.<>(<>.<>)
            3T      Drop last three                    (<(<>(<>.(<>.<(<>.<>(<>.
              :w    Palindromize, flipping (){}[]<>    

Answer 33

Python 2, 54 bytes

f=lambda i=5:L*0**i or L[:-i]+f(i-1)+L[i:]
L='(<>.<>)'

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Slight improvement on the leading Python 2 answer

Port of my Lenny's answer

Answer 34

Retina, 39 bytes

(<(a(a.(a.<(a.a(abab>bba)>)
b
.a)
a
<>

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Answer 35

C#, 104 bytes

string a="(<>.<>)",s="";for(int i=2,k=a.Length;i<k*2-1;i++){s+=(k>i)?a.Substring(0,i):a.Substring(i-k);}

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Answer 36

JavaScript (ES6), 52 bytes

Obvious solution; doesn't seem to be much room for any trickery here.

f=

_=>"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

o.innerText=f()

<pre id=o>

Answer 37

Brainfuck, 489 bytes

++[------>+<]>---.[-->+++<]>.[--->++<]>.[-->+++<]>.++.--[--->++<]>.[-->+++<]>.++.[->+++++++++<]>.------.[-->+++<]>.++.[->+++++++++<]>.--[----->+<]>.[--->++<]>.[-->+++<]>.++.[->+++++++++<]>.--[----->+<]>.++.--[--->++<]>.[-->+++<]>.++.[->+++++++++<]>.--[----->+<]>.++.+[--->++<]>-.-[-->+++<]>.++.[->+++++++++<]>.--[----->+<]>.++.+[--->++<]>-.+[-->+++<]>-.[->+++++++++<]>.--[----->+<]>.++.+[--->++<]>-.+++++.--[----->+<]>.++.+[--->++<]>-.-[-->+++<]>.++.+[--->++<]>-.+[-->+++<]>-.+[--->++<]>-.

Answer 38

Japt, 41 25 bytes

"(<>.<>)"
¤£¯Ò°TÃ+U+¤£s°V

Test it

Answer 39

T-SQL, 54 bytes (the trivial solution)

PRINT'(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)'

I like this challenge, simple and yet so annoying.

I tried hard to find alternates, but nothing was shorter, due mostly due to the length of SQL keywords. Hmm, maybe I need to create GolfSQL with minimized keywords and other optimizations...

Here's my best attempt at a procedural solution (97 bytes golfed, presented here formatted):

DECLARE @ INT=-4, @o VARCHAR(99)=''
a:
    SET @o+=SUBSTRING('(<>.<>)',@,7)
    SET @+=1
IF @<7 GOTO a
PRINT @o

This works because SUBSTRING can take a negative start value, in which case it simply reduces the length.

Edit: Found a slightly shorter non-trivial solution (96 bytes):

SELECT STRING_AGG(SUBSTRING('(<>.<>)',number-4,7),'')FROM
spt_values WHERE TYPE='P'AND number<11

Only works on MS SQL Server, where the master database has a built-in system table called spt_values. This table (when filtered by WHERE TYPE='P') can be used as a number table to generate the values from -4 to 6.

Answer 40

Bubblegum, 24 bytes

0000000: d3 b0 d1 b0 b1 03 22 3d 10 b6 01 13 76 10 52 13  ......"=....v.R.
0000010: 42 82 09 10 06 b1 35 01                          B.....5.

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Answer 41

Pyth, 29 bytes

K"(<>.<>)"s++m<KhdS5Km>hdK_S5

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Answer 42

Perl 5, 75+1(-w) = 76 bytes

I'm unsure of how needed -w is, but it wasn't printing the output until I tried it.

for(-5..5){$l=-abs($_)+7;$o=$_>0?7-$l:0;$s.=substr"(<>.<>)",$o,$l;}print$s;

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Ungolfed

for(-5..5){
  $l = -abs($_) + 7;
  $o = $_ > 0 ? 7 - $l : 0;
  $s .= substr "(<>.<>)", $o, $l;
}

Answer 43

Matlab, 74 68 65 bytes

function[m]=f,s='(<>.<>)';m=s;for i=2:6,m=[s(1:8-i),m,s(i:7)];end

Runs perfectly on Matlab and prints: (<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>). However, it prints on Octave. So the link is useless.

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Answer 44

Julia, 60 bytes

prod([("(<>.<>)"^2)[min(x,8):max(x,7)] for x in[9:13;1:6]])

Answer 45

PHP, 47 bytes

Needs a file with the Content-Type text/plain

(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)

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PHP, 53 bytes

<?="(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)";

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