Check if a given string is valid romaji

Your program is given a string consisting entirely of lowercase letters at STDIN (or closest alternative). The program must then output a truthy or falsey value, depending on whether the input is valid romaji.

Rules:

It must be possible to divide the entire string into a sequence of kana without any leftover characters.
Each kana can be a single vowel (aeiou)
Each kana can also be a consonant p, g, z, b, d, k, s, t, n, h, m, or r followed by a vowel. For example, ka and te are valid kana, but qa is not.
The exceptions to the above rule are that zi, di, du, si, ti, and tu are not valid kana.
The following are also valid kana: n, wa, wo, ya, yu, yo, ji, vu, fu, chi, shi, tsu.
If a particular consonant is valid before an i (i.e ki, pi), the i can be replaced by a ya, yu, or yo and still be valid (i.e kya, kyu, kyo)
Exceptions to the above rule are chi and shi, for which the y has to be dropped too (i.e cha, chu, cho, sha, shu, sho)
It is also valid to double consonants if they are the first character of a kana (kka is valid but chhi is not)
Shortest answer wins. All regular loopholes are disallowed.

List of all valid kana:

Can have double consonant:

ba, bu, be, bo, bi
ga, gu, ge, go, gi
ha, hu, he, ho, hi
ka, ku, ke, ko, ki
ma, mu, me, mo, mi
na, nu, ne, no, ni
pa, pu, pe, po, pi
ra, ru, re, ro, ri
sa, su, se, so,
za, zu, ze, zo,
da,     de, do,
ta,     te, to,
wa,         wo,
ya, yu,     yo,
    fu,
    vu
                ji

Can not have double consonant:

a, i, u, e, o, 
    tsu,
chi, cha, cho, chu,
shi, sha, sho, shu,
n

Test cases

Pass:

kyoto
watashi
tsunami
bunpu
yappari

Fail:

yi
chhi
zhi
kyi

takra

Posted 2017-05-24T00:08:26.497

Reputation: 793

How do we win? Is this a code golf? – caird coinheringaahing – 2017-05-24T00:09:37.357

2Need test cases. Also could do with a list of all valid kana instead of the rules – Robert Fraser – 2017-05-24T00:11:05.033

1@RobertFraser both is preferred - test cases are not rules – Stephen – 2017-05-24T00:12:18.673

If pa pi pu pe po are valid kana, then can't you simply group p with the other consonants? – Value Ink – 2017-05-24T00:15:59.960

I added all the kana, I think. Please tell me if I missed some. – takra – 2017-05-24T00:20:06.643

@ValueInk good point, that makes it easier to understand – takra – 2017-05-24T00:20:29.103

"If a particular consonant is valid before an i (i.e ki, pi), the i can be replaced by a ya, yu, or yo and still be valid (i.e kya, kyu, kyo)" The list seems to be missing these for "h", and "p" – Jonathan Allan – 2017-05-24T02:32:38.590

The list is missing all doubled consonant variants. Is chchi valid or not (i.e. is ch considered a character)? – Jonathan Allan – 2017-05-24T02:38:16.780

I've updated list of valid kana, but n needs clarification – Dead Possum – 2017-05-24T14:08:45.197

2n cannot be doubled. I know enough about the Japanese alphabets to say that. If n was doubled, it would need to have a vowel after, but then it wouldn't be n. So if kanna was a word (just making it up), it'd actually be ka n na. – mbomb007 – 2017-05-24T14:16:40.737

You know, I wanted to make a solution using unicodedata, but it'll definitely be longer than a regex solution. Partial program

– mbomb007 – 2017-05-24T14:30:48.697

@mbomb007 Does it output vowels twice intended? – Dead Possum – 2017-05-24T14:34:49.287

@DeadPossum This isn't a solution. If I were going to use it, I'd be checking if the list contains something. – mbomb007 – 2017-05-24T14:35:31.650